J
John Larkin
Guest
On Wed, 15 Oct 2003 19:32:49 +0200, "Mathew Orman" <orman@nospam.com>
wrote:
John
wrote:
Don't tell me what I'm confusing."John Larkin" <jjlarkin@highlandSNIPtechTHISnologyPLEASE.com> wrote in
message news:v5pqov8b9bp3ssh2mp18duovn36m72j6v5@4ax.com...
On 15 Oct 2003 07:33:19 -0700, Winfield Hill
Winfield_member@newsguy.com> wrote:
John Fields wrote...
My test setup will be precisely as indicated in my previous post, and
if you wish for me to proceed you must still agree to the remainder
of my requirements, from my previous post, namely:
John, you shouldn't create two separate 50-ohm signal paths simply
by paralleling the two coax lines. Instead you need at least a
splitter, or better, a splitter with each output followed by a 20dB
attenuator to insure completely independent pathways. Furthermore
you need to measure the impedance of the line under test to verify
it's 50 ohms (higher impedances move closer to the speed of light).
Thanks,
- Win
whill_at_picovolt-dot-com
Why not just drive the stupid thing from a signal generator and poke
the same hi-z scope probe on the input and output, and note the
waveforms? Since the FTL cable is flexible, presumably one can locate
the termination near to the source, at least to within scope probe
range.
Oh, in coax, the prop velocity depends on the dielectric constant of
the insulator, not on the impedance.
John
You are confusing EM waves propagation with transmission line waveform
propagation.
Moron.The later depends on nominal RLC only!
Right. Partial differentiation is the key to the illusion.Also one must drive it with the signal that defines the coax segment as
"Electrically Short and Open Ended".
John