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Bill Sloman
Guest
On Thursday, July 16, 2020 at 4:01:59 AM UTC+10, Ricketty C wrote:
https://en.wikipedia.org/wiki/Shockley_diode_equation
The current a low levels - roughly within 26mV of zero - looks resistive.
At negative voltages it is insensitive to voltage - the charge carriers appearing get swept out until you get to a high enough voltage to sustain avalanche multiplication.
Letting light shine on an LED does generate charge carriers in the junction - they aren\'t great photo-diodes, but they can be used that way.
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Bill Sloman, Sydney
On Wednesday, July 15, 2020 at 12:19:04 PM UTC-4, Jim Jackson wrote:
Maybe I should just give in and limit the voltage with a Zener diode.
I was trying to keep a part off the BOM if possible. There\'s already
a green LED in use.
I think you will find a zener to be worse than a LED
Worse in what regard exactly??? My only real complaint with the LED is the light sensitivity. At the voltages I need to measure (up to 1.7 volts) the dark current would seem to be very minimal.
If the current at low voltages is truly logarithmic, does that mean there is a current at zero or even negative voltages? So a diode will pump out very low levels of power? Perhaps the level of power is below the uncertainty principle level of detection like the quantum foam?
https://en.wikipedia.org/wiki/Shockley_diode_equation
The current a low levels - roughly within 26mV of zero - looks resistive.
At negative voltages it is insensitive to voltage - the charge carriers appearing get swept out until you get to a high enough voltage to sustain avalanche multiplication.
Letting light shine on an LED does generate charge carriers in the junction - they aren\'t great photo-diodes, but they can be used that way.
--
Bill Sloman, Sydney