J
Jonathan Kirwan
Guest
On Wed, 27 Oct 2004 09:36:40 GMT, Jonathan Kirwan <jkirwan@easystreet.com>
wrote:
Coulomb's worth of protons instead of electrons, as they are nearly 2000 times
as massive and the force will impress a much lower acceleration on them. But
the net energy at impact should be the same. Since potential energy is
proportional to M*V^2, I'd anticipate that the velocity of the protons at
arrival would be about the square root of the ratio of the mass of the electron
to the mass of the proton, or about sqrt(1/1836.15266) = .02334 times as fast.
A little more than 2% of the speed that the electrons would achieve. (Assuming
neither case was approaching relativistic speeds, of course.) Same energy,
though.
Jon
wrote:
By the way, this "final velocity" won't be the same if you were propelling aIf they are close together, the electrons will be accelerated
more and take less time to arrive, but their final velocity will be the same
when they hit and the resulting energy of the impact will be the same.
Coulomb's worth of protons instead of electrons, as they are nearly 2000 times
as massive and the force will impress a much lower acceleration on them. But
the net energy at impact should be the same. Since potential energy is
proportional to M*V^2, I'd anticipate that the velocity of the protons at
arrival would be about the square root of the ratio of the mass of the electron
to the mass of the proton, or about sqrt(1/1836.15266) = .02334 times as fast.
A little more than 2% of the speed that the electrons would achieve. (Assuming
neither case was approaching relativistic speeds, of course.) Same energy,
though.
Jon