J
John Larkin
Guest
On 18 Oct 2004 04:06:21 -0700, tatto0_2000@yahoo.com (Wong) wrote:
Yup. If you jam in 1/10 as much base current as the load current, that
would be called a "forced beta" of 10.
But more base current doesn't always lead to lower saturation voltage.
For either the normal or inverted setup, there's some base current
that makes for the lowest Vce. A forced beta of 10 should be pretty
good, though.
John
tatto0_2000@yahoo.com (Wong) wrote in message news:<509bfe22.0410150112.7c079369@posting.google.com>...
Hi,
Is it possible to saturate the NPN BJT transistor in this biasing ?
Vcc
___
|
|
|
_| C
B |
---- Resistor ----|
|
-
| E
|---------------- Output
|
Resistor
|
|
|
---
- Ground
Since the transistor is OFF when '0' to base and hence output is '0'.
Then when '1' to base I would like to have 4.5V at the output, is that
possible to bias the transistor in saturation region (since Vce no
more <0.2V)?
OK, one more question.
If my transistor datasheet stated that the minimum hFE (DC current
transfer ratio) is 100 and the maximum is 400, can I still force this
transistor into saturation where hFE normally is 10 in saturated
transistor?
Thank you.
Yup. If you jam in 1/10 as much base current as the load current, that
would be called a "forced beta" of 10.
But more base current doesn't always lead to lower saturation voltage.
For either the normal or inverted setup, there's some base current
that makes for the lowest Vce. A forced beta of 10 should be pretty
good, though.
John