Lowest noise amps

On Wed, 24 Aug 2005 09:09:44 GMT, Robert Baer
<robertbaer@earthlink.net> wrote:

It is a simple differential of the equation for capacitance as a
finction of the plate seperation.
The capacitance change has a simple linear relation to the change in
seperation (leaving out constant multiplier).
And someone is tying to imply that it is 1/(X*X)...
We all find ourselves needing a bit of a refresher now and then, it is
quite easy to look at a problem backward or upside down without
realizing it. An inverse relationship is not linear. Capacitance is
proportional to 1/x or x^(-1), where x is the distance between
parallel plates. You should be able to verify that, as well as the
solution of d/dx{x^(-1)], in your dusty old college textbooks. In the
meantime we will award you 2 points towards a peppermint sneaker award
:).
 
I read in sci.electronics.design that Glen Walpert <gwalpert@notaxs.com>
wrote (in <depog1pkkjlj76qblthvvcejdg6snh0mbp@4ax.com>) about 'Lowest
noise amps', on Wed, 24 Aug 2005:
No need for such sarcasm, John. I'm sure we can all think of many much
better reasons why you should leave SED in disgrace!
Oh, right.

I came back because some people enquired after me, even to phoning me.
Maybe those people are more intelligent than others.
--
Regards, John Woodgate, OOO - Own Opinions Only.
If everything has been designed, a god designed evolution by natural selection.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk
 
Glen Walpert wrote:

On Wed, 24 Aug 2005 09:09:44 GMT, Robert Baer
robertbaer@earthlink.net> wrote:


It is a simple differential of the equation for capacitance as a
finction of the plate seperation.
The capacitance change has a simple linear relation to the change in
seperation (leaving out constant multiplier).
And someone is tying to imply that it is 1/(X*X)...


We all find ourselves needing a bit of a refresher now and then, it is
quite easy to look at a problem backward or upside down without
realizing it. An inverse relationship is not linear. Capacitance is
proportional to 1/x or x^(-1), where x is the distance between
parallel plates. You should be able to verify that, as well as the
solution of d/dx{x^(-1)], in your dusty old college textbooks. In the
meantime we will award you 2 points towards a peppermint sneaker award
:).
It is true that capacitance is inversely proportional to separation,
1/X (all other items constant). Obviously not linear, as you mentioned.
The change of capacitance is proportional to the change of separation dX.
And i merely quoted the simple differential equation, which happened
to be the same found in college textbooks and the Chem Rubber Handbook.
**
Do i get to sneak up on Peppermint Patty?
 
On Wed, 24 Aug 2005 13:42:25 +0100, John Woodgate
<jmw@jmwa.demon.contraspam.yuk> wrote:

I read in sci.electronics.design that Glen Walpert <gwalpert@notaxs.com
wrote (in <depog1pkkjlj76qblthvvcejdg6snh0mbp@4ax.com>) about 'Lowest
noise amps', on Wed, 24 Aug 2005:
No need for such sarcasm, John. I'm sure we can all think of many much
better reasons why you should leave SED in disgrace!

Oh, right.

I came back because some people enquired after me, even to phoning me.
Maybe those people are more intelligent than others.
It never occurred to me that you of all people would fail to
appreciate my sarcastic response to your sarcastic response. If I
really thought you should leave SED I would not bother to respond to
any of your posts. But I guess humor is wasted on you so I will skip
such attempts in the future.
 
On Wed, 24 Aug 2005 18:39:03 GMT, Robert Baer
<robertbaer@earthlink.net> wrote:

Glen Walpert wrote:

On Wed, 24 Aug 2005 09:09:44 GMT, Robert Baer
robertbaer@earthlink.net> wrote:


It is a simple differential of the equation for capacitance as a
finction of the plate seperation.
The capacitance change has a simple linear relation to the change in
seperation (leaving out constant multiplier).
And someone is tying to imply that it is 1/(X*X)...


We all find ourselves needing a bit of a refresher now and then, it is
quite easy to look at a problem backward or upside down without
realizing it. An inverse relationship is not linear. Capacitance is
proportional to 1/x or x^(-1), where x is the distance between
parallel plates. You should be able to verify that, as well as the
solution of d/dx{x^(-1)], in your dusty old college textbooks. In the
meantime we will award you 2 points towards a peppermint sneaker award
:).
It is true that capacitance is inversely proportional to separation,
1/X (all other items constant). Obviously not linear, as you mentioned.
The change of capacitance is proportional to the change of separation dX.
And i merely quoted the simple differential equation, which happened
to be the same found in college textbooks and the Chem Rubber Handbook.
**
Do i get to sneak up on Peppermint Patty?
I suppose you could, but the Peppermint Sneaker Award is designed to
sweeten the lives of those who spend time with foot in mouth. The
flavor is largely gone from mine, however, and at only 2 points you
have a long way to go to qualify for one :).
 
I read in sci.electronics.design that Glen Walpert <gwalpert@notaxs.com>
wrote (in <4aorg1libplkbafnari9ovd92k3mqijh6h@4ax.com>) about 'Lowest
noise amps', on Thu, 25 Aug 2005:

It never occurred to me that you of all people would fail to appreciate
my sarcastic response to your sarcastic response. If I really thought
you should leave SED I would not bother to respond to any of your
posts. But I guess humor is wasted on you so I will skip such attempts
in the future.
I'm afraid you misunderstood my response. I will admit to not being sure
of it being sarcastic, but I didn't mean to imply anything about you
personally. I meant that the people who enquired after my welfare
were/are more intelligent that those who level nebulous attacks and
refuse to explain.
--
Regards, John Woodgate, OOO - Own Opinions Only.
If everything has been designed, a god designed evolution by natural selection.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk
 

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