G
Glen Walpert
Guest
On Wed, 24 Aug 2005 09:09:44 GMT, Robert Baer
<robertbaer@earthlink.net> wrote:
quite easy to look at a problem backward or upside down without
realizing it. An inverse relationship is not linear. Capacitance is
proportional to 1/x or x^(-1), where x is the distance between
parallel plates. You should be able to verify that, as well as the
solution of d/dx{x^(-1)], in your dusty old college textbooks. In the
meantime we will award you 2 points towards a peppermint sneaker award
.
<robertbaer@earthlink.net> wrote:
We all find ourselves needing a bit of a refresher now and then, it isIt is a simple differential of the equation for capacitance as a
finction of the plate seperation.
The capacitance change has a simple linear relation to the change in
seperation (leaving out constant multiplier).
And someone is tying to imply that it is 1/(X*X)...
quite easy to look at a problem backward or upside down without
realizing it. An inverse relationship is not linear. Capacitance is
proportional to 1/x or x^(-1), where x is the distance between
parallel plates. You should be able to verify that, as well as the
solution of d/dx{x^(-1)], in your dusty old college textbooks. In the
meantime we will award you 2 points towards a peppermint sneaker award
.