J
Jeroen Belleman
Guest
Jan Panteltje wrote:
Yeah, well, you forgot about the h_oe output conductance,
which isn't zero. There is effectively a resistor of a
few 10 kOhm in parallel with your 10 MOhm collector resistor,
limiting the gain. Somebody already told you.
Jeroen Belleman
On a sunny day (Fri, 7 Jun 2019 03:59:16 -0700 (PDT)) it happened
ithacacollegephysics@gmail.com wrote in
85e803ec-c2d7-4b6a-a752-ce08625c0a32@googlegroups.com>:
Jan Panteltje, several kOhm of input impedance will reduce our expected current
by a factor of ten or more. So I am not sure your design will work. We'd
drop our expected current down to 100 pA, or less.
This is the interesting part.
That 100 pA (1e-10) will flow into the base junction of that transistor and if it is a high beta type
here for the simplicity of numbers not hFE 900 but 1000, result in a collector current of 1e-7,
or .1 uA.
In a 10 MOhm collector resistor that will give 1 V (1e-7 * 1e7).
Yeah, well, you forgot about the h_oe output conductance,
which isn't zero. There is effectively a resistor of a
few 10 kOhm in parallel with your 10 MOhm collector resistor,
limiting the gain. Somebody already told you.
Jeroen Belleman