B
Bob Myers
Guest
"FEerguy9" <feerguy9@cs.com> wrote in message
news:20031015090435.28427.00000973@mb-m12.news.cs.com...
how it works.
Frank, actually THINK about this for a change. Here's a
gallon bucket. The ULTIMATE etching that you could ever
possibly do is to remove all of the material of the bucket
itself, down to whatever the minimum is to actually still have
a bucket. Let's say we have some unreasonably strong
material, and we can etch and etch and etch until the
"bucket" is just a molecule's-width thick.
How much volume have you gained over the original
"gallon bucket"? Hint: Unless the original bucket had
absurdly thick walls, such that the original inner volume
was significantly less that the volume defined by the outer
surface, it ISN'T going to be much more than the original
gallon.
And yes, this IS EXACTLY the same problem you face
with capacitors. Here's a given volume - you get to fill it
with any combination of dielectric and conductor (plates),
in any geometry. Obviously, the most dielectric you could
have is exactly the volume defined, in which case you don't
have any plate area at all. And just as obviously, you can
fill the volume with conductor, in which case you have no
dielectric at all (and therefore no capacitor). And there is
simply no way you put a unit volume's worth of plate material
AND a unit volume's worth of dielectric in to a single unit
volume. "Etching the plates" doesn't create ANY new
volume - for every bit of plate material you remove, you
add dielectric - but you don't gain anything in terms of the
total energy capacity of the volume. "Capacitance" BY ITSELF
IS NOT ENERGY CAPACITY.
Shall we add geometry to that list of "math" subjects that you
simply don't want to deal with?
Bob M.
news:20031015090435.28427.00000973@mb-m12.news.cs.com...
Yes, you keep saying that, but you still haven't shownvolume. Thus, a gallon is not really a gallon but much more
than a gallon. But Frank still hasn't explained how to
fill a gallon container with 2 gallons of gas.
Etch, and re-etch the indide of the glass.
how it works.
Frank, actually THINK about this for a change. Here's a
gallon bucket. The ULTIMATE etching that you could ever
possibly do is to remove all of the material of the bucket
itself, down to whatever the minimum is to actually still have
a bucket. Let's say we have some unreasonably strong
material, and we can etch and etch and etch until the
"bucket" is just a molecule's-width thick.
How much volume have you gained over the original
"gallon bucket"? Hint: Unless the original bucket had
absurdly thick walls, such that the original inner volume
was significantly less that the volume defined by the outer
surface, it ISN'T going to be much more than the original
gallon.
And yes, this IS EXACTLY the same problem you face
with capacitors. Here's a given volume - you get to fill it
with any combination of dielectric and conductor (plates),
in any geometry. Obviously, the most dielectric you could
have is exactly the volume defined, in which case you don't
have any plate area at all. And just as obviously, you can
fill the volume with conductor, in which case you have no
dielectric at all (and therefore no capacitor). And there is
simply no way you put a unit volume's worth of plate material
AND a unit volume's worth of dielectric in to a single unit
volume. "Etching the plates" doesn't create ANY new
volume - for every bit of plate material you remove, you
add dielectric - but you don't gain anything in terms of the
total energy capacity of the volume. "Capacitance" BY ITSELF
IS NOT ENERGY CAPACITY.
Shall we add geometry to that list of "math" subjects that you
simply don't want to deal with?
Bob M.