R
Rolavine
Guest
That is if this is going to be used to monitor clipping.From: kensmith@green.rahul.net (Ken Smith)
No, you don't want to take the RMS value of the product. You want to
average to product. The product of the current and voltage will have two
components. It will have a DC value equal to the average power and a sine
wave at twice the frequency. This sine wave at twice the frequency, you
want to ingore. The RMs would include it in the answer.
For this to have much value wouldn't you just want to show the wattage peeks?
Rocky