A
Alan B
Guest
On 29 Sep 2006 02:02:23 -0700, in message
<1159520543.255216.254310@m7g2000cwm.googlegroups.com>, "mark2006"
<iKolar26@yahoo.com> scribed:
cells to make a 48V 24mA battery. To wit:
48V * 24mA = 1152VA
2.53V * 0.5mA * 19 = 24.035VA
1152VA / 24VA = 48
So you need 48 columns of 19 rows of 2.5V .5mA cells. Only 47 more to go.
Keep us posted.
<1159520543.255216.254310@m7g2000cwm.googlegroups.com>, "mark2006"
<iKolar26@yahoo.com> scribed:
I believe your math is a bit off. It would take 912 (not 19) 2.53V .5mAI have connected 19 "small" homemade batteries into one realy,
realy huge battery. After some tests and after fixing some problems
with volmeter, i have this situation:
One "small" battery:
DCV : 2,53 V
DCAmps: : 0,5 mA
Huge battery:
DCV : 48V
DCAmps : 24 mA
cells to make a 48V 24mA battery. To wit:
48V * 24mA = 1152VA
2.53V * 0.5mA * 19 = 24.035VA
1152VA / 24VA = 48
So you need 48 columns of 19 rows of 2.5V .5mA cells. Only 47 more to go.
Keep us posted.