S
Sunil
Guest
hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
and how do you find it out experimentally??
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It depends on the circuit it's operated in. If you're referring to the devicehi.....can anyone define input and output impedence of a transistor??
By measurement !and how do you find it out experimentally??
Why can't you go to the prof., and say, "I still don't get this -my professor measured it using the ratio between Rin and Rs (internal
resistance)....i kinda dint understand that...can u xplain me this
method??
Frankly, if you want my precise opinion, most 'professors' haven't the tiniestmy professor measured it using the ratio between Rin and Rs (internal
resistance)....i kinda dint understand that...can u xplain me this
method??
I went to the Prof (age 18) and said (something along the lines of to the bestSunil wrote:
my professor measured it using the ratio between Rin and Rs (internal
resistance)....i kinda dint understand that...can u xplain me this
method??
Why can't you go to the prof., and say, "I still don't get this -
can you explain it to me again, in a form I can understand?"
Measure the voltage across the resistor and the voltage across the BEhi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
Connect a battery and a resistor in series with a base emitter junction.
You just measured a DIODE not a transistor.Sunil wrote in message
hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
Connect a battery and a resistor in series with a base emitter junction.
Measure the voltage across the resistor and the voltage across the BE
junction. From ohms law you can figure out the current flowing into the
junction and the resistance of the junction.
thanksbg wrote:
Sunil wrote in message
hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
Connect a battery and a resistor in series with a base emitter junction.
Measure the voltage across the resistor and the voltage across the BE
junction. From ohms law you can figure out the current flowing into the
junction and the resistance of the junction.
You just measured a DIODE not a transistor.
Please don't flaunt your ignorance in this way.
Graham
Ok so we measured h and not Bh, but the flaunting is not negotiable.
here in the states!.Sunil wrote:
hi.....can anyone define input and output impedence of a transistor??
It depends on the circuit it's operated in. If you're referring to the device
itself alone, those parameters will vary with collector current.
and how do you find it out experimentally??
By measurement !
Now, maybe you can us about the reason behind your question.
Graham
Now you're starting to sound like one of the brothers,
Rich Grise wrote:
Sunil wrote:
my professor measured it using the ratio between Rin and Rs (internal
resistance)....i kinda dint understand that...can u xplain me this
method??
Why can't you go to the prof., and say, "I still don't get this -
can you explain it to me again, in a form I can understand?"
I went to the Prof (age 18) and said (something along the lines of to the best
of my memory) why are you using Y parameters when no damn * (OK I didn't say
"damn") semiconductor manufacturer publishes any such damn * thing and I think
he was mostly embarassed that a student was probably better informed about
current practice than he was.
His answer when I suggested that H parameters might be more useful was IIRC
"that's another way you can do it". DUH !
What a useless piece of trash ! I had 2 very good friends on the course who both
admitted at the end of the first year "I still don't understand what a
transistor does". I did and I hadn't learnt it at UCL and that's why I left.
Graham
No comment.. How ever, I do admire your truthfulness.
Eeyore wrote in message <470E8A9D.50A212DC@hotmail.com>...
bg wrote:
Sunil wrote in message
hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
Connect a battery and a resistor in series with a base emitter junction.
Measure the voltage across the resistor and the voltage across the BE
junction. From ohms law you can figure out the current flowing into the
junction and the resistance of the junction.
You just measured a DIODE not a transistor.
Please don't flaunt your ignorance in this way.
Graham
Ok so we measured h and not Bh, but the flaunting is not negotiable.
thanks
Pay no mind to Mr Ham.. He can be as rude as he can be ignorant.
Whereas you can be relied upon to be ignorant and WRONG about everything.Pay no mind to Mr Ham.. He can be as rude as he can be ignorant.
"Brothers" ? I thought that was a reference to 'black' people.Eeyore wrote:
Sunil wrote:
hi.....can anyone define input and output impedence of a transistor??
It depends on the circuit it's operated in. If you're referring to the device
itself alone, those parameters will vary with collector current.
and how do you find it out experimentally??
By measurement !
Now, maybe you can us about the reason behind your question.
Now you're starting to sound like one of the brothers,
here in the states!.
Not everything American is a bad thing !Keep it up, you'll be wearing an American patch very soon!
how transistors work AND I might add, how to use them in practicalhi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
The book, "The Art of Electronics" does an excellent job of explaining
problem with that.bg wrote:
Eeyore wrote in message <470E8A9D.50A212DC@hotmail.com>...
bg wrote:
Sunil wrote in message
hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
Connect a battery and a resistor in series with a base emitter junction.
Measure the voltage across the resistor and the voltage across the BE
junction. From ohms law you can figure out the current flowing into the
junction and the resistance of the junction.
You just measured a DIODE not a transistor.
Please don't flaunt your ignorance in this way.
Graham
Ok so we measured h and not Bh, but the flaunting is not negotiable.
thanks
Pay no mind to Mr Ham.. He can be as rude as he can be ignorant.
Frankly, I don't understand the instructor placing a question in suck
an awkward manner? In any case. Your idea of applying current in the base,
assuming the emitter is at common, is just one step less than that of
the final process of measuring the current from source to C.(collector).
This would then give you the current gain ratio. found in reference of
Hfe, also found in text as Beta.
Now most of us know, that figure is not absolute due to the nature of
bipolar transistors.
The above assumes bipolar, since, that is most likely what they teach
first in school.
--
"I'm never wrong, once i thought i was, but was mistaken"
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5
Graham is right. I gave a wrong answere.Unlike some people, I don't have a
I apologise for my bluntness.Jamie wrote in message ...
bg wrote:
Eeyore wrote in message <470E8A9D.50A212DC@hotmail.com>...
bg wrote:
Sunil wrote in message
hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
Connect a battery and a resistor in series with a base emitter junction.
Measure the voltage across the resistor and the voltage across the BE
junction. From ohms law you can figure out the current flowing into the
junction and the resistance of the junction.
You just measured a DIODE not a transistor.
Please don't flaunt your ignorance in this way.
Graham
Ok so we measured h and not Bh, but the flaunting is not negotiable.
thanks
Pay no mind to Mr Ham.. He can be as rude as he can be ignorant.
Frankly, I don't understand the instructor placing a question in suck
an awkward manner? In any case. Your idea of applying current in the base,
assuming the emitter is at common, is just one step less than that of
the final process of measuring the current from source to C.(collector).
This would then give you the current gain ratio. found in reference of
Hfe, also found in text as Beta.
Now most of us know, that figure is not absolute due to the nature of
bipolar transistors.
The above assumes bipolar, since, that is most likely what they teach
first in school.
--
"I'm never wrong, once i thought i was, but was mistaken"
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5
Graham is right. I gave a wrong answere.Unlike some people, I don't have a
problem with that.
bg
Well, you may think so how ever, over here black people callJamie wrote:
Eeyore wrote:
Sunil wrote:
hi.....can anyone define input and output impedence of a transistor??
It depends on the circuit it's operated in. If you're referring to the device
itself alone, those parameters will vary with collector current.
and how do you find it out experimentally??
By measurement !
Now, maybe you can us about the reason behind your question.
Now you're starting to sound like one of the brothers,
here in the states!.
"Brothers" ? I thought that was a reference to 'black' people.
Keep it up, you'll be wearing an American patch very soon!
Not everything American is a bad thing !
Graham
You change your mind like most people change their underwear.
wasn't correct, was just incomplete of what should have been done inJamie wrote in message ...
Graham is right. I gave a wrong answere.Unlike some people, I don't have a
problem with that.
bg
I understand that how ever, the procedure you describe even though
bg wrote:
Jamie wrote in message ...
bg wrote:
Eeyore wrote in message <470E8A9D.50A212DC@hotmail.com>...
bg wrote:
Sunil wrote in message
hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
Connect a battery and a resistor in series with a base emitter junction.
Measure the voltage across the resistor and the voltage across the BE
junction. From ohms law you can figure out the current flowing into the
junction and the resistance of the junction.
You just measured a DIODE not a transistor.
Please don't flaunt your ignorance in this way.
Graham
Ok so we measured h and not Bh, but the flaunting is not negotiable.
thanks
Pay no mind to Mr Ham.. He can be as rude as he can be ignorant.
Frankly, I don't understand the instructor placing a question in suck
an awkward manner? In any case. Your idea of applying current in the base,
assuming the emitter is at common, is just one step less than that of
the final process of measuring the current from source to C.(collector).
This would then give you the current gain ratio. found in reference of
Hfe, also found in text as Beta.
Now most of us know, that figure is not absolute due to the nature of
bipolar transistors.
The above assumes bipolar, since, that is most likely what they teach
first in school.
--
"I'm never wrong, once i thought i was, but was mistaken"
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5
Graham is right. I gave a wrong answere.Unlike some people, I don't have a
problem with that.
bg
I apologise for my bluntness.
Graham
That's today.