D
Dave Platt
Guest
In article <n9g7445fdmof3nohavnt74eghlh02mb0je@4ax.com>,
JW <none@dev.nul> wrote:
that the device *really* needs very specific selection for various
parameters.
in this schematic, it looks as if the downward side would be the
lower-voltage side per the normal convention, and thus the drain's on
the top and the source is on the bottom.
JFETs tend to be fairly symmetrical, and will often work if you swap
the source and drain, but since the source/gate and drain/gate
capacitances may not be identical you should probably keep the part in
its preferred orientation.
--
Dave Platt <dplatt@radagast.org> AE6EO
Friends of Jade Warrior home page: http://www.radagast.org/jade-warrior
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JW <none@dev.nul> wrote:
Yeah... that's certainly the sensible thing to do, unless you findI think I'll try option 2 with a U441.![]()
that the device *really* needs very specific selection for various
parameters.
For an N-JFET, the source goes towards the more negative voltage...Now for my dumb/ignorant question: The schematic does not show source and
drain - how do I determine which is which when I replace the part?
in this schematic, it looks as if the downward side would be the
lower-voltage side per the normal convention, and thus the drain's on
the top and the source is on the bottom.
JFETs tend to be fairly symmetrical, and will often work if you swap
the source and drain, but since the source/gate and drain/gate
capacitances may not be identical you should probably keep the part in
its preferred orientation.
--
Dave Platt <dplatt@radagast.org> AE6EO
Friends of Jade Warrior home page: http://www.radagast.org/jade-warrior
I do _not_ wish to receive unsolicited commercial email, and I will
boycott any company which has the gall to send me such ads!