spring/shock absorber has "reactance"?

The "spring back" is due to the compressed air and
not to a spring, as such.

"Farina" <nospam@nospam.com> wrote in message
news:35cjj0F4k0g9gU1@individual.net...
"Airy R.Bean" <Me@privacy.net> wrote in message
news:35civeF4kfve7U1@individual.net...
If you take a shock absorber that is not mounted in a vehicle,
and compress it, you'll find that it will spring back, just
as will a bicycle pump.

Bicycle pump I have has no internal spring
 
You are that spikeful old crone, Old Mother-Hen
Nugatory RVMJ-Binaryera, and I claim my Ł5!

What's up, Mrs Nugatory? Are you cowering behind
your curtains because there's a couple of gleams-in-the-milkman's-eye
threatening you from your front gate?

<me@privacy.net> wrote in message
news:8uq1v0hpjecgrho33igqj1elot8gnmkbdk@4ax.com...
On Fri, 21 Jan 2005 09:53:26 -0000, "Airy R.Bean" <Me@privacy.net
wrote:

The same analogy applies to springs and to shock absorbers;
the spring stores energy when stretched; the shock-absorber
stores energy when compressed.

Your statement is complete rubbish. If you don't know the science,
don't make it up.
 
On Fri, 21 Jan 2005 14:43:49 -0000, "Airy R.Bean" <Me@privacy.net>
wrote:

Yes- you're partly right, and I was misled by
the OP, who perhaps was misguided into referring
to shock absorbers rather than to masses.

However, if you take a shock absorber that is not
mounted in a vehicle and compress it, you'll find that
it will spring back, much as if you compress a bicycle
pump with your finger closing the hole at the sharp end.

It won't spring back as far, nor as readily, however.
Rubbish.

Your analogy is incorrect.

You are trying use the technology to explain the science.

Let us not get side-tracked into irrelevancies
You need to follow your own advice.
 
On Fri, 21 Jan 2005 14:38:59 -0000, "Airy R.Bean" <Me@privacy.net>
wrote:

If you take a shock absorber that is not mounted in a vehicle,
and compress it, you'll find that it will spring back, just
as will a bicycle pump.
Rubbish.

Your analogy is incorrect.

You are trying use technology to explain the science.
 
On 20 Jan 2005 15:52:41 -0800, alanh_27@yahoo.com wrote:

They say that the mechanical analogues of capacitors are springs, and
of inductors are shock absorbers. And this does have a strong
intuitive appeal.

But do springs/shock absorbers have any kind of frequency-dependent
behaviors?
Yes... Think of a standard spring watch movement. (I believe the
formal term is "escapement"). There is a specific time period between
each direction reversal, just like a clock pendulum.

Beachcomber
 
alanh_27@yahoo.com schrieb:
They say that the mechanical analogues of capacitors are springs, and
of inductors are shock absorbers. And this does have a strong
intuitive appeal.

But do springs/shock absorbers have any kind of frequency-dependent
behaviors?

If the mechanical analogue of capacitance is a spring, then the analogue
of an inductor is a mass.
These two can resonate like a car without shock absorbers. The shock
absorbers are the analogue of a resistor (damping the oscillation.
 
"richy" <invalid@nospam.com> wrote in message
news:35auukF4jsfq1U1@individual.net...
alanh_27@yahoo.com> wrote in message
news:1106265161.475444.323700@z14g2000cwz.googlegroups.com...
They say that the mechanical analogues of capacitors are springs, and
of inductors are shock absorbers. And this does have a strong
intuitive appeal.

But do springs/shock absorbers have any kind of frequency-dependent
behaviors?


inductors are not shock absorbers, as they do not dissipate energy like
shocks do.
Shocks would be simulated by a resistive element.

Answer to second is Yes. They are "tuned" to your cars mass, and expected
road conditions.

Shock absorbers are non linear.
They have different resistance in bounce and rebound
They normaly act approximatly to the viscus rule ( force proportional to the
square of speed ) at low speed, at higher speeds a spring loaded valve opens
and holds force approximatly constant.
In addition to this gas shock absorbers have a non liniar "spring" turm as
the gas in there top chamber acts as a gas spring storing energy.
As if the above was not enough they have end stops.. rubber springs..

To regard a shock absorber as an equivelent to a single electronic component
is just daft.

A simple dash pot can be modeled by the viscos law.

--
Jonathan

Barnes's theorem; for every foolproof device
there is a fool greater than the proof.

To reply remove AT
 
I know how the sytem works.

The spring ABSORBS the shock.

Try the basic cart with your "shock absorbers" and no springs.

Better still, take the road springs off your car/automobile, leaving
your "shock absorbers in place.
 
On Thu, 20 Jan 2005 23:27:41 -0800, Robert Monsen
<rcsurname@comcast.net> wrote:

John Larkin wrote:

If you jump on the fender of a car with bad shocks, the entire car
oscillates. It's the mass of the car and the stiffness of the springs
that determine the resonant frequency, typically a couple of Hz; if
you take the cars's mass as infinite, absolutely nothing will happen
if you jump on it.

John


Actually, you'll be sucked into the resulting black hole...
Sort of like one of those Escalade objects.

John
 
On Thu, 20 Jan 2005 16:40:45 -0800, John Larkin
<jjlarkin@highSNIPlandTHIStechPLEASEnology.com> wrote:


If you treat

Capacitance = mass
Inductance = spring
Resistance = damping (shock absorber, viscoscity)

then identical differential equations will describe both systems.
---
I haven't read the whole thread so I don't know if anyone else caught
it, but:

Capacitance = spring
Inductance = mass
Resistance = damping

--
John Fields
 
in article rowbotth-A19E16.12171021012005@news.telus.net, Rowbotth at
rowbotth@telusplanet.net wrote on 1/21/05 11:17 AM:

These analogies are meaningful because of identical mathematical
description. As part of the formalism, charge is equivalent to position and
rate of charge change is current and analogous to rate of change of
position.

Capacitors store potential electrical energy C*V^2/2 as springs store
potential mechanical energy k*x^2/2. Inductors store kinetic electrical
energy L*I^2/2 as masses store kinetic mechanical energy m*v^2/2.

When you make a lagrangian formulation based upon these energies, the
equations for electrical and mechanical motions are identical and frequency
dependence is identical.

Bill

I agree with this. It is only an analogy. Just as process / chemical
engineers equate water pressure to voltage and water flow to current,
you can use a spring or shock absorber to describe the VAr.

As long as the analogy is only appropriate to grasp basic principle of
operation, you are OK. If they know enough to get into calculations and
want to start doing the math, then get them an electrical textbook and
get them to accept that a negative number can have a square root....

The spring is how I describe the VAr to our mechies and process types.
It seems to satisfy them, and allows them to understand enough about
what I'm talking about to accept what they see, electrically.
I do not know what you mean by "It is only an analogy." The analogy I
described wrt capacitors and inductors corresponding and their energies is
MATHEMATICALLY IDENTICAL to potential and kinetic energies of springs and
masses respectively. This is a much better analogy than the water/pressure
analogy you allude to.

For decades, these analogies were used to carry out acoustic calculations
because there were tables such as the Campbell and Foster fourier transforms
that were designed for electrical work. The formalism of electtic circuitry
made it easier to determine the electrical analog of acoustical and
mechanical systems and then solve the corresponding electrical problem than
to formulate the acoustic or mechanical system equations. See the book on
analogs by Olson.

My original description using lagrangian formulation based upon lagrangians
need to have a velocity dependent dissipation function added to the
lagrangian to take into account resistive as well as rective components.
Unforunately lagrangian formulation is not a tool used by many EEs.

Bill
 
A shock absorber that moves other than in
a straight line is an MOT failure.

"Jonathan Barnes" <jbarnes6@btinternet.com> wrote in message
news:csrio2$8je$1@titan.btinternet.com...
> Shock absorbers are non linear.
 
On Sat, 22 Jan 2005 11:18:16 +0000, Airy R.Bean top posted:

A shock absorber that moves other than in a straight line is an MOT
failure.

"Jonathan Barnes" <jbarnes6@btinternet.com> wrote in message
news:csrio2$8je$1@titan.btinternet.com...
Shock absorbers are non linear.
I think he was referring to transfer function, not mechanical alignment.

Anyway, what about lever-type shock absorbers?

--
Then there's duct tape ...
(Garrison Keillor)
 
On Sat, 22 Jan 2005 06:51:39 GMT, Repeating Rifle
<salmonegg@sbcglobal.net> wrote:


My original description using lagrangian formulation based upon lagrangians
need to have a velocity dependent dissipation function added to the
lagrangian to take into account resistive as well as rective components.
Unforunately lagrangian formulation is not a tool used by many EEs.
Our lives are too complex and too nonlinear.

John
 
"richy" <invalid@nospam.com> wrote in message
news:35auukF4jsfq1U1@individual.net...
alanh_27@yahoo.com> wrote in message
news:1106265161.475444.323700@z14g2000cwz.googlegroups.com...
They say that the mechanical analogues of capacitors are springs, and
of inductors are shock absorbers. And this does have a strong
intuitive appeal.

But do springs/shock absorbers have any kind of frequency-dependent
behaviors?


inductors are not shock absorbers, as they do not dissipate energy like
shocks do.
Shocks would be simulated by a resistive element.

Answer to second is Yes. They are "tuned" to your cars mass, and expected
road conditions.
cross-posted to the universe at large.

its time to refer back to the "water" analogy.

or maybe electricity is like tiny little fireflies trapped in a still...they
try to excape but are slowed by the spiral condensor... then they fall to
the ground drunk exausted and happy...
 
On Thu, 20 Jan 2005 16:40:45 -0800, John Larkin
<jjlarkin@highSNIPlandTHIStechPLEASEnology.com> wrote:

On 20 Jan 2005 15:52:41 -0800, alanh_27@yahoo.com wrote:

They say that the mechanical analogues of capacitors are springs, and
of inductors are shock absorbers. And this does have a strong
intuitive appeal.

But do springs/shock absorbers have any kind of frequency-dependent
behaviors?

If you treat

Capacitance = mass
Inductance = spring
Resistance = damping (shock absorber, viscoscity)

then identical differential equations will describe both systems.

A parallel L-C circuit has a resonant frequency where it's easiest to
excite. A mass hung on a spring is the same, it twangs at a resonant
frequency if whacked. Jump on the fender of a car with bad shocks; it
will bounce at the resonant frequency.

John

Yes, a car suspension has all three derivatives. The mass and its
spring are supported parts, definining a resonant frequency (taking
the mass of the car as infinite). The shock absorber with its viscous
drag adds dissipation sufficient to overwhelm the sharp resonance, or
else you have to buy new shocks.

John Polasek
If you have something to say, write an equation.
If you have nothing to say, write an essay
 
On Fri, 21 Jan 2005 01:55:28 GMT, Repeating Rifle
<salmonegg@sbcglobal.net> wrote:

in article 1106265161.475444.323700@z14g2000cwz.googlegroups.com,
alanh_27@yahoo.com at alanh_27@yahoo.com wrote on 1/20/05 3:52 PM:

They say that the mechanical analogues of capacitors are springs, and
of inductors are shock absorbers. And this does have a strong
intuitive appeal.

But do springs/shock absorbers have any kind of frequency-dependent
behaviors?


These analogies are meaningful because of identical mathematical
description. As part of the formalism, charge is equivalent to position and
rate of charge change is current and analogous to rate of change of
position.

Capacitors store potential electrical energy C*V^2/2 as springs store
potential mechanical energy k*x^2/2. Inductors store kinetic electrical
energy L*I^2/2 as masses store kinetic mechanical energy m*v^2/2.

When you make a lagrangian formulation based upon these energies, the
equations for electrical and mechanical motions are identical and frequency
dependence is identical.

Bill

Bill
Though it is quite possible to use several different physical pairs
for C and L anologs, I confirm that for mass and springs,
Bill is spelling out a pairing that I know is in use: i.e. the spring
is not the L as you might suppose, but the C.

Brian Whatcott Altus OK
 
Brian Whatcott wrote:
On Fri, 21 Jan 2005 01:55:28 GMT, Repeating Rifle
salmonegg@sbcglobal.net> wrote:


in article 1106265161.475444.323700@z14g2000cwz.googlegroups.com,
alanh_27@yahoo.com at alanh_27@yahoo.com wrote on 1/20/05 3:52 PM:


They say that the mechanical analogues of capacitors are springs, and
of inductors are shock absorbers. And this does have a strong
intuitive appeal.

But do springs/shock absorbers have any kind of frequency-dependent
behaviors?


These analogies are meaningful because of identical mathematical
description. As part of the formalism, charge is equivalent to position and
rate of charge change is current and analogous to rate of change of
position.

Capacitors store potential electrical energy C*V^2/2 as springs store
potential mechanical energy k*x^2/2. Inductors store kinetic electrical
energy L*I^2/2 as masses store kinetic mechanical energy m*v^2/2.

When you make a lagrangian formulation based upon these energies, the
equations for electrical and mechanical motions are identical and frequency
dependence is identical.

Bill

Bill


Though it is quite possible to use several different physical pairs
for C and L anologs, I confirm that for mass and springs,
Bill is spelling out a pairing that I know is in use: i.e. the spring
is not the L as you might suppose, but the C.

Brian Whatcott Altus OK
For a mass-spring system, if we assume a rectifying force which is
dependent on position, then

F = -k*x

By newtons famous law,

F = m * a

So, if x is a function of time, we have

-k*x(t) = m * x''(t)

thus,

x''(t) = -k/m * x(t)

The solution is, of course,

x(t) = sin(sqrt(k/m) * t)

where sqrt(k/m) is called the 'angular frequency'

For electronics, if we say that

k = 1/C, and m = L, then

v(t) = sin(t/sqrt(LC))

This makes the resonant frequency w = 1/sqrt(LC), which we know to be
the case.

By this, we can say that the spring is the equivalent to the capacitor,
and the mass is equivalent to the inductor.

Another way to look at it is that the fundamental correpondence is mass
and charge. The spring creates a rectifying force, just like the voltage
across the capacitor induces the charges to move. Once the mass is in
motion, its inertia keeps it going, which is what F = ma is all about.
An inductor opposes motion, and then wants to keep the motion going,
just like inertia.

Thus, the real correspondence is voltage across the capacitor to tension
in the spring, and the movement of charge throught the inductor to the
inertia of the mass.

For more information, you can consult "The Feynman Lectures", volume I,
chapter 23. He uses a cool technique to derive the equations of damped
oscillation for both mass-spring and inductor-capacitor systems.

--
Regards,
Robert Monsen

"Your Highness, I have no need of this hypothesis."
- Pierre Laplace (1749-1827), to Napoleon,
on why his works on celestial mechanics make no mention of God.
 
On Thu, 20 Jan 2005 20:12:00 -0500, John C. Polasek
<jpolasek@cfl.rr.com> wrote:

On Thu, 20 Jan 2005 16:40:45 -0800, John Larkin
jjlarkin@highSNIPlandTHIStechPLEASEnology.com> wrote:

On 20 Jan 2005 15:52:41 -0800, alanh_27@yahoo.com wrote:

They say that the mechanical analogues of capacitors are springs, and
of inductors are shock absorbers. And this does have a strong
intuitive appeal.

But do springs/shock absorbers have any kind of frequency-dependent
behaviors?

If you treat

Capacitance = mass
Inductance = spring
Resistance = damping (shock absorber, viscoscity)

then identical differential equations will describe both systems.

A parallel L-C circuit has a resonant frequency where it's easiest to
excite. A mass hung on a spring is the same, it twangs at a resonant
frequency if whacked. Jump on the fender of a car with bad shocks; it
will bounce at the resonant frequency.

John

Yes, a car suspension has all three derivatives. The mass and its
spring are supported parts, definining a resonant frequency (taking
the mass of the car as infinite). The shock absorber with its viscous
drag adds dissipation sufficient to overwhelm the sharp resonance, or
else you have to buy new shocks.
If you jump on the fender of a car with bad shocks, the entire car
oscillates. It's the mass of the car and the stiffness of the springs
that determine the resonant frequency, typically a couple of Hz; if
you take the cars's mass as infinite, absolutely nothing will happen
if you jump on it.

John
 
"John Larkin" <jjlarkin@highSNIPlandTHIStechPLEASEnology.com> wrote in
message news:6dj0v0h4lt6fuo8i52l64ehhsrdvq6og9p@4ax.com...
On 20 Jan 2005 15:52:41 -0800, alanh_27@yahoo.com wrote:

They say that the mechanical analogues of capacitors are springs, and
of inductors are shock absorbers. And this does have a strong
intuitive appeal.

But do springs/shock absorbers have any kind of frequency-dependent
behaviors?

If you treat

Capacitance = mass
Inductance = spring
Resistance = damping (shock absorber, viscoscity)

then identical differential equations will describe both systems.

A parallel L-C circuit has a resonant frequency where it's easiest to
excite. A mass hung on a spring is the same, it twangs at a resonant
frequency if whacked. Jump on the fender of a car with bad shocks; it
will bounce at the resonant frequency.

John

To complete your analogy - treat current as force and voltage as velocity.
(nodal modal)

You can also use

current+velocity
Voltage =force
Inductance=Mass
Capacitance =compliance
resistance =damping
--
Don Kelly
dhky@peeshaw.ca
remove the urine to answer
 

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