J
Jasen Betts
Guest
On 2020-05-29, default <default@defaulter.net> wrote:
it\'s just a node.
current into the base is close enough to monodirectional that it
doesn\'t matter.
a capacitor across the added transistor could maybe help with charge
scavenging a little but that 1K resistor is going to slow that down
anyway.
--
Jasen.
On Thu, 28 May 2020 19:29:11 -0000 (UTC), Jasen Betts
jasen@xnet.co.nz> wrote:
On 2020-05-28, default <default@defaulter.net> wrote:
On Thu, 28 May 2020 10:13:52 -0000 (UTC), Jasen Betts
jasen@xnet.co.nz> wrote:
On 2020-05-26, alberto.m.scattolo@gmail.com <alberto.m.scattolo@gmail.com> wrote:
On Tuesday, May 26, 2020 at 2:36:40 PM UTC+2, default wrote:
When you say the blocking oscillator works are you saying the light
works as long as the battery is charged, and the cell has full
sunlight on it? So the light stays on all the time and doesn\'t turn
off when there is light on the cell?
It would be better to think of it as a light detector that stops the
oscillator while the cell has light on it.
(the \"famous\" joule thief, is ancient technology from the days of
vacuum toobes)
https://en.wikipedia.org/wiki/Blocking_oscillator
Hi!
When I say \"The joule thief part works just fine\" I mean that, with a charged 1.2 AA battery, and bypassing the light detector, a 5mm blue led lights up very bright. So, the oscillator works, otherwise the led would not switch on at all.
\"Bypassing the light detector\" means that I connect the battery positive to the center of the transformer directly, without going through the first transistor so that the transformer is always powered by the battery as far as it is charged. This works with or without the solar panel, with or without light on it.
I am interested in making the light detector work, to switch on the light only when meaningful and to maintain the battery charged.
Eventually, I would also try to replace the battery with a capacitor but I am not 100% sure this is a good idea. And I would like to know the frequency of oscillation, I don\'t know if there is a practical way to calculate it, I do not an oscilloscope.
Thanks link too!
Switching the main current to the Joule Theif is probably the wrong
approach, switch the current to the base instead, that is only switch
the current that flows through the transformer branch that goes to the
base. this is a much smaller current, and so it takes less energy to
run the switch. (you can use a smaller base current to the switch)
A second problem is that the joule thief may not start automatically
when power is gradually applied. Some sort of positive feedback to
ensure that the power snaps on should help there.
How do you plan to switch only the base of the oscillator transistor?
https://www.jameco.com/Jameco/workshop/JamecoFavorites/solarled.html
the transformer has two windings, connect the other one to the supply.
The windiings have the turn on bias a well as the inductive feedback
and turn-off riding on them. The center-tap is integral to the
operation..
it\'s just a node.
There should be a way to do it: pass the AC feedback while isolating
the DC bias,
current into the base is close enough to monodirectional that it
doesn\'t matter.
but it is a little more complicated than separating the
center tap and it would take a few more components.
a capacitor across the added transistor could maybe help with charge
scavenging a little but that 1K resistor is going to slow that down
anyway.
--
Jasen.