T
Terry Pinnell
Guest
Tony Williams <tonyw@ledelec.demon.co.uk> wrote:
--
Terry Pinnell
Hobbyist, West Sussex, UK
Excellent, thanks. Will get stuck into that asap.In article <8eji91h3197k3a837hgcmuq7r63rcqovif@4ax.com>,
Terry Pinnell <terrypinDELETE@THESEdial.pipex.com> wrote:
The motor looks like this;
I Rmotor Lmotor
V-Atmotor +->----/\/\----))))---[Vback-emf]---+0v
Under steady state (dc) conditions the motor equation is.
V-Atmotor = I*Rmotor + Vback-emf.
Voltage (DC V)
Test description At source At motor Current (A)
---------------- --------- -------- -----------
- Stalled 0.98 0.34 4.4
- Stalled 1.67 0.67 8.5
- Stalled 2.19 0.95 11.5
- Stalled 2.77 1.26 14.1
When stalled, Vback-emf = Zero.
So V-Atmotor = I*Rmotor, or Rmotor = V-Atmotor/I.
So Rmotor = .34/4.4 or .67/8.5 or 0.95/11.5, or 1.26/14.1
which nicely averages out to Rmotor= 0.08 ohms.
~~~~~~~~~~~~~~~~~
- Motor unloaded 1.18 0.96 1.8 (0.816)
- Motor unloaded 2.35 2.12 2.1 (1.952)
- Motor unloaded 3.64 3.41 2.3 (3.226)
- Motor unloaded 4.97 4.74 2.5 (4.54 )
When running, the equation is V-Atmotor = I*Rmotor + Vback-emf.
eg, 0.96 = 1.8A*0.08ohms + (Vbemf at that speed, = 0.816V).
The added things in brackets are the calc'd internal Vbemfs
that the motor generates at the various rpm's.
That gearbox-only load will have a fixed current representing
the fixed friction, in parallel with a speed-dependant load,
ie, proportional to the Vbemf.
It roughly looks like Imotor = 1.7A + Vbemf/5.3ohms in the
unloaded condition. ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
I 0.08R Lmotor
V-Atmotor +->----/\/\----))))-+-[Vback-emf]-+-+0v
| |
Fixed loss--> +--[ 1.7A ]---+
| |
Speed-dependant loss--> +----/\/\/----+
| 5.3R |
| |
. .
. .
+---[I-Ext]---+
An external torque load will be another current in parallel
with Vbemf.
--
Terry Pinnell
Hobbyist, West Sussex, UK