D
Dave.H
Guest
On Jan 24, 12:05 pm, ehsjr <eh...@bellatlantic.net> wrote:
This is an easy enough circuit to build, I'll go with this one, thanks.Dave.H wrote:
I'm looking to convert a flashlight I have to LED, the flashlight uses
a 6 volt "lantern battery but the LED's max voltage rating is 3.1
volts DC. What value resistor would I need for this? I also want to
run it off a 9 volt supply, again I need to know the value of the
resistor.
The LED is part # Z4251 atwww.dse.com.au.
I didn't see a constant current solution posted, probably
because it is costs more than using just a series resistor.
But constant current was mentioned, so here's a constant
current circuit that uses 1 watt resistors and an LM317
chip, and works either 6 or 9 volts input. It provides
about 347 mA to the LED.
-----
+ ----Vin|LM317|Vout---+-----+
----- | |
Adj [3R9] [47R]
| | |
+----------+-----+ I = 347 mA
|
[LED]
|
Gnd --------------------------+
The chip needs to be installed on a heat sink. I would omit the 47
ohm resistor to reduce the current to about 320 mA. That's kinder
to the LED.
Dick Smith has the heatsink for $1.25, the LM317 for $2.10 and
the resistors for 10 cents each.
Ed