S
Stephanie
Guest
Resistors are rated by 2 parameters: ohms and (W). Capacitors are rated in
(C) and (V).
It's taught to make sure that (W) doesn't exceed the resistor's power rating,
which takes (I) into calculation, but capacitors are only chosen by their
primary parameters, (C) and (V).
Why is a capacitor not rated for power dissipation?
What got me thinking about this is that I looked up a capacitor (via (C) and
(V)) to replace a 20-year-old design and it's tiny compared to the original.
Then I got to thinking that, were it a resistor, I'd presume that the larger
one was rated for greater power dissipation. But capacitors, no: as long as
the (C) and (V) ratings are identical, they are interchangeable (generally;
specific application aside).
So, why is it not important to consider power dissipation and, in turn, (I)
when choosing a capacitor?
Thanks.
Stef
(C) and (V).
It's taught to make sure that (W) doesn't exceed the resistor's power rating,
which takes (I) into calculation, but capacitors are only chosen by their
primary parameters, (C) and (V).
Why is a capacitor not rated for power dissipation?
What got me thinking about this is that I looked up a capacitor (via (C) and
(V)) to replace a 20-year-old design and it's tiny compared to the original.
Then I got to thinking that, were it a resistor, I'd presume that the larger
one was rated for greater power dissipation. But capacitors, no: as long as
the (C) and (V) ratings are identical, they are interchangeable (generally;
specific application aside).
So, why is it not important to consider power dissipation and, in turn, (I)
when choosing a capacitor?
Thanks.
Stef