OT: Smartphone always charging destroyed battery?

Whoey Louie <trader4@optonline.net> wrote in news:c92585bb-426c-475f-
86f0-ce4fac894cd4@googlegroups.com:

I never used the term CPU, only you did.

8 cores, you retarded fuck.

So it also appears that you are too stupid to even know what the
terms you spew mean.

 

[Chris Jones]

On 22/01/2020 16:48, John Doe wrote:

https://www.flickr.com/photos/27532210@N04/

Another Chinese battery bit the dust here. Noticed my smartphone was
bulging, the screen was warping. The cause was obvious so, not having a
torx t1 screwdriver, I ripped it apart. Tried using a capacitor in place
of the stock battery but that didn't work. An 18650 works, but it's
charged to 4.36 V.

The smartphone is used for Wi-Fi security camera monitoring, so it is
plugged in all the time.

Question:
Would putting a resistor or diode in series with the battery reduce the
constant charge voltage? Is there some way to very simply reduce the
battery voltage peak while it is always connected to the charging cable?

I won't attempt messing with the smartphone's charging circuit wherever
or whatever it is.

Thanks.

I'd try putting two schottky diodes in anti-parallel, so that they will
conduct in either direction but drop maybe 0.5V, between the battery and
the phone. That way, the battery voltage will be a bit less than what
the charger is set to, but the phone can still draw current from the
battery if it wants to. Of course the run time on battery will be
reduced, but it sounds like that won't bother you.

If that doesn't work, then you could add some circuit with a comparator
(or these days, a microcontroller might be easier) to check the battery
voltage and turn off the charger output (with a relay or ideally MOSFET)
whenever the battery goes above 3.9V, turn back on at maybe 3.8V or so.

 

[Rick C]

On Sunday, January 26, 2020 at 9:49:49 AM UTC-5, Chris Jones wrote:

On 22/01/2020 16:48, John Doe wrote:
https://www.flickr.com/photos/27532210@N04/

Another Chinese battery bit the dust here. Noticed my smartphone was
bulging, the screen was warping. The cause was obvious so, not having a
torx t1 screwdriver, I ripped it apart. Tried using a capacitor in place
of the stock battery but that didn't work. An 18650 works, but it's
charged to 4.36 V.

The smartphone is used for Wi-Fi security camera monitoring, so it is
plugged in all the time.

Question:
Would putting a resistor or diode in series with the battery reduce the
constant charge voltage? Is there some way to very simply reduce the
battery voltage peak while it is always connected to the charging cable?

I won't attempt messing with the smartphone's charging circuit wherever
or whatever it is.

Thanks.


I'd try putting two schottky diodes in anti-parallel, so that they will
conduct in either direction but drop maybe 0.5V, between the battery and
the phone. That way, the battery voltage will be a bit less than what
the charger is set to, but the phone can still draw current from the
battery if it wants to. Of course the run time on battery will be
reduced, but it sounds like that won't bother you.

The battery will charge to a bit less than the charger voltage, but then when the charger turns off the battery voltage will appear to drop even lower turning the charger back on. No? The circuit will likely oscillate turning on and off and on again.

If that doesn't work, then you could add some circuit with a comparator
(or these days, a microcontroller might be easier) to check the battery
voltage and turn off the charger output (with a relay or ideally MOSFET)
whenever the battery goes above 3.9V, turn back on at maybe 3.8V or so.

I think I'd buy a phone that doesn't destroy the battery by overcharging.

--

Rick C.

+-+ Get 1,000 miles of free Supercharging
+-+ Tesla referral code - https://ts.la/richard11209

 

[John Doe]

This incessant troll just doesn't get the fact... As Lenovo
EXPLICITLY states, keeping the battery charged to less than maximum
when it is always plugged in helps increase battery life. A citation
to Lenovo's advice was given already. That is the main reason,
Lenovo allows changing the maximum battery charge level on its
laptops.

Maybe it just can't read...

--
Rick C <gnuarm.deletethisbit gmail.com> wrote:

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Subject: Re: OT: Smartphone always charging destroyed battery?
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On Sunday, January 26, 2020 at 9:49:49 AM UTC-5, Chris Jones wrote:
On 22/01/2020 16:48, John Doe wrote:
https://www.flickr.com/photos/27532210 N04/

Another Chinese battery bit the dust here. Noticed my smartphone was
bulging, the screen was warping. The cause was obvious so, not having a
torx t1 screwdriver, I ripped it apart. Tried using a capacitor in place
of the stock battery but that didn't work. An 18650 works, but it's
charged to 4.36 V.

The smartphone is used for Wi-Fi security camera monitoring, so it is
plugged in all the time.

Question:
Would putting a resistor or diode in series with the battery reduce the
constant charge voltage? Is there some way to very simply reduce the
battery voltage peak while it is always connected to the charging cable?

I won't attempt messing with the smartphone's charging circuit wherever
or whatever it is.

Thanks.


I'd try putting two schottky diodes in anti-parallel, so that they will
conduct in either direction but drop maybe 0.5V, between the battery and
the phone. That way, the battery voltage will be a bit less than what
the charger is set to, but the phone can still draw current from the
battery if it wants to. Of course the run time on battery will be
reduced, but it sounds like that won't bother you.

The battery will charge to a bit less than the charger voltage, but then when the charger turns off the battery voltage will appear to drop even lower turning the charger back on. No? The circuit will likely oscillate turning on and off and on again.


If that doesn't work, then you could add some circuit with a comparator
(or these days, a microcontroller might be easier) to check the battery
voltage and turn off the charger output (with a relay or ideally MOSFET)
whenever the battery goes above 3.9V, turn back on at maybe 3.8V or so.

I think I'd buy a phone that doesn't destroy the battery by overcharging.

--

Rick C.

+-+ Get 1,000 miles of free Supercharging
+-+ Tesla referral code - https://ts.la/richard11209

 

[Rick C]

On Sunday, January 26, 2020 at 7:08:28 PM UTC-5, John Doe wrote:

This incessant troll just doesn't get the fact... As Lenovo
EXPLICITLY states, keeping the battery charged to less than maximum
when it is always plugged in helps increase battery life. A citation
to Lenovo's advice was given already. That is the main reason,
Lenovo allows changing the maximum battery charge level on its
laptops.

Maybe it just can't read...

Apparently not. I read that you were discussing a cell phone. Silly me. No, silly you.

--

Rick C.

-++ Get 1,000 miles of free Supercharging
-++ Tesla referral code - https://ts.la/richard11209

 

[John Doe]

Anyone with at least half a brain easily correlates the computers
that are both meant to be portable. Nevermind the obvious technical
fact they are the same batteries overcharged to the same voltage,
under the same condition of being left plugged in. But seriously!

Maybe the poster needs glasses...

--
Rick C <gnuarm.deletethisbit gmail.com> wrote:

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Subject: Re: OT: Smartphone always charging destroyed battery?
From: Rick C <gnuarm.deletethisbit gmail.com
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On Sunday, January 26, 2020 at 7:08:28 PM UTC-5, John Doe wrote:
This incessant troll just doesn't get the fact... As Lenovo
EXPLICITLY states, keeping the battery charged to less than maximum
when it is always plugged in helps increase battery life. A citation
to Lenovo's advice was given already. That is the main reason,
Lenovo allows changing the maximum battery charge level on its
laptops.

Maybe it just can't read...


Apparently not. I read that you were discussing a cell phone. Silly me. No, silly you.

--

Rick C.

-++ Get 1,000 miles of free Supercharging
-++ Tesla referral code - https://ts.la/richard11209

 

[Rick C]

On Sunday, January 26, 2020 at 9:31:00 PM UTC-5, John Doe wrote:

Anyone with at least half a brain easily correlates the computers
that are both meant to be portable. Nevermind the obvious technical
fact they are the same batteries overcharged to the same voltage,
under the same condition of being left plugged in. But seriously!

Maybe the poster needs glasses...

You would do very poorly in court trying to show evidence of this by providing testimony of that and saying... "well, they're a lot alike". Your phone overcharges the battery so my laptop must as well. Geeze, talk about not very smart.

My car is portable too, so I guess that overcharges as well.

The cure is still to get a new phone that works correctly.

--

Rick C.

+-- Get 1,000 miles of free Supercharging
+-- Tesla referral code - https://ts.la/richard11209

 

[John Doe]

lol
Dingbat...

--
Rick C <gnuarm.deletethisbit gmail.com> wrote:

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On Sunday, January 26, 2020 at 9:31:00 PM UTC-5, John Doe wrote:
Anyone with at least half a brain easily correlates the computers
that are both meant to be portable. Nevermind the obvious technical
fact they are the same batteries overcharged to the same voltage,
under the same condition of being left plugged in. But seriously!

Maybe the poster needs glasses...

You would do very poorly in court trying to show evidence of this by providing testimony of that and saying... "well, they're a lot alike". Your phone overcharges the battery so my laptop must as well. Geeze, talk about not very smart.

My car is portable too, so I guess that overcharges as well.

The cure is still to get a new phone that works correctly.

--

Rick C.

+-- Get 1,000 miles of free Supercharging
+-- Tesla referral code - https://ts.la/richard11209

 

[Martin Brown]

On 26/01/2020 17:36, Rick C wrote:

On Sunday, January 26, 2020 at 9:49:49 AM UTC-5, Chris Jones wrote:
On 22/01/2020 16:48, John Doe wrote:

Question: Would putting a resistor or diode in series with the
battery reduce the constant charge voltage? Is there some way to
very simply reduce the battery voltage peak while it is always
connected to the charging cable?

I won't attempt messing with the smartphone's charging circuit
wherever or whatever it is.

Thanks.

I'd try putting two schottky diodes in anti-parallel, so that they
will conduct in either direction but drop maybe 0.5V, between the
battery and the phone. That way, the battery voltage will be a bit
less than what the charger is set to, but the phone can still draw
current from the battery if it wants to. Of course the run time on
battery will be reduced, but it sounds like that won't bother you.

They are usually DC supplies so you should only need one with the right
polarity.

The battery will charge to a bit less than the charger voltage, but
then when the charger turns off the battery voltage will appear to
drop even lower turning the charger back on. No? The circuit will
likely oscillate turning on and off and on again.

It depends a lot on the charging circuit.

If the thing is relatively simple minded then knocking 0.4v or so off
the final charged battery state ought to improve longevity. In a sense
you are only using the battery to smooth out any mains failures here.

If that doesn't work, then you could add some circuit with a
comparator (or these days, a microcontroller might be easier) to
check the battery voltage and turn off the charger output (with a
relay or ideally MOSFET) whenever the battery goes above 3.9V, turn
back on at maybe 3.8V or so.

I think I'd buy a phone that doesn't destroy the battery by
overcharging.

They all do this to some extent iff you leave them permanently on mains
power. There is a trade off between runtime in use and battery life.

Leaving them flat for a long period is even more deleterious to their
health. You can end up with one that is unsafe to recharge if you let
the cell potential drop below a certain value due to neglect.

--
Regards,
Martin Brown

 

[John Doe]

Martin Brown <'''newspam'''@nezumi.demon.co.uk> wrote:

Rick C wrote:
Chris Jones wrote:
John Doe wrote:

Question: Would putting a resistor or diode in series with the
battery reduce the constant charge voltage? Is there some way
to very simply reduce the battery voltage peak while it is
always connected to the charging cable?

I won't attempt messing with the smartphone's charging circuit
wherever or whatever it is.

I'd try putting two schottky diodes in anti-parallel, so that
they will conduct in either direction but drop maybe 0.5V,
between the battery and the phone. That way, the battery voltage
will be a bit less than what the charger is set to, but the
phone can still draw current from the battery if it wants to. Of
course the run time on battery will be reduced, but it sounds
like that won't bother you.

They are usually DC supplies so you should only need one with the
right polarity.

The battery will charge to a bit less than the charger voltage,
but then when the charger turns off the battery voltage will
appear to drop even lower turning the charger back on. No? The
circuit will likely oscillate turning on and off and on again.

It depends a lot on the charging circuit.

Testing for that is another thing my dirt cheap primitive PC
oscilloscope can be used for. Another situation where I only need to
know what sort of signal is present without needing specifics. Just
connect one probe to ground and the other probe to the signal, then
click the automatic setup button (easy).

The cheap PC oscilloscope was similarly useful for connecting my drone
controller video output to FPV goggles. I just needed to know what
output was video. That was the squiggly lines Got the wiring right
the first time.

 

[Whoey Louie]

On Sunday, January 26, 2020 at 9:33:58 AM UTC-5, DecadentLinux...@decadence.org wrote:

Whoey Louie <trader4@optonline.net> wrote in news:c92585bb-426c-475f-
86f0-ce4fac894cd4@googlegroups.com:

I never used the term CPU, only you did.


8 cores, you retarded fuck.

So it also appears that you are too stupid to even know what the
terms you spew mean.

I know perfectly well what the term means and I know what I wrote
which was this:


"It's absurd to think that phones with 8 core
2 ghz CPUS and advanced electronics don't have charging circuits
and algorithms to correctly charge and maintain the batteries. "

"And in phone chip sets that have 8 cores and billions of transistors, they didn't put in the correct battery monitoring and charging solution? "

 

[John Doe]

Martin Brown <'''newspam'''@nezumi.demon.co.uk> wrote:

Rick C wrote:
Chris Jones wrote:
John Doe wrote:

Question: Would putting a resistor or diode in series with the
battery reduce the constant charge voltage? Is there some way
to very simply reduce the battery voltage peak while it is
always connected to the charging cable?

I won't attempt messing with the smartphone's charging circuit
wherever or whatever it is.

I'd try putting two schottky diodes in anti-parallel, so that
they will conduct in either direction but drop maybe 0.5V,
between the battery and the phone. That way, the battery voltage
will be a bit less than what the charger is set to, but the
phone can still draw current from the battery if it wants to. Of
course the run time on battery will be reduced, but it sounds
like that won't bother you.

They are usually DC supplies so you should only need one with the
right polarity.

The reason two diodes was suggested is probably because the
implementation is easier. Using one diode requires figuring out where
the charging circuit meets the device supply circuit since they both
go to the battery positive terminal.

Then an oscilloscope will be used to see if Birdbrain's prediction
about the charger quickly oscillating on and off is correct.

 

[John Doe]

Nah. For some reason the device sucks some current from the battery
while it's plugged in. Maybe that has something to do with most people
not using their smartphones when they are plugged in. I'd rather not
mess with it.

The battery will be on the outside, so I can keep an ion it.

There is an Android smartphone app for doing what Lenovo laptops do, but
requires root. Not sure this Verizon smartphone can be routed. I might
try again. But still not sure that app will work anyway. The situation
here is that the device draws a lot of current while it is plugged in.
It is not just a matter of cutting off the battery charge. It's a matter
of getting the line to power the device after the battery is charged.
But there is no way I can hack it.

Maybe a much bigger capacitor is worth a try, just for fun. I forget how
much gold capacitors cost, remember seeing them on Digi-Key long ago,
probably dirt cheap now.

 

[John Doe]

https://www.flickr.com/photos/27532210@N04/

 

John Doe <always.look@message.header> wrote in news:r0tse3$s88$1@dont-
email.me:

https://www.flickr.com/photos/27532210@N04/

Wind resistance!

OMG! No wonder it only goes 2 tenths of a mile (j/k)

BMX? Seriously?

You a Lollypop Guild guy?