W
whit3rd
Guest
On Tuesday, October 25, 2022 at 8:52:40 AM UTC-7, John Larkin wrote:
If there\'s enough energy to unbalance a thermistor bridge, a single detector
would handle the whole range. Just put one thermistor in shade, and expose
the other to the \'beam\'. That does require a mirror for beam forming from a
small-spot source, but no wavelengths omitted if you spend the money for a reflective
grating do do the wavelength selection. The replica gratings, at $1 each, don\'t
come with a lot of detailed specs for 1500 nm.
You\'d not want the operator to breathe on the detector, of course.
On Tue, 25 Oct 2022 16:03:40 +0100, piglet <erichp...@hotmail.com
wrote:
Regular silicon detectors cover 900-300nm (or thereabouts) at low cost
so I wonder if a non-linear crystal can be switched in ahead of the
grating to double or triple 1600nm into the Si-detectable range. JL
wants to verify single bright monochromatic sources so losses needn\'t be
a worry?
A typical source is a connectorized fiber-coupled laser of a couple of
milliwatts. Multiplication usually requires very high powers.
The longest wavelength lasers that we now use are 1550, and we have
corresponding photodiodes. The shortest are 800, ditto.
A wavelength splitter and three photodiodes would at least identify
the band of a laser: 1500ish, 1300ish, and 850ish.
If there\'s enough energy to unbalance a thermistor bridge, a single detector
would handle the whole range. Just put one thermistor in shade, and expose
the other to the \'beam\'. That does require a mirror for beam forming from a
small-spot source, but no wavelengths omitted if you spend the money for a reflective
grating do do the wavelength selection. The replica gratings, at $1 each, don\'t
come with a lot of detailed specs for 1500 nm.
You\'d not want the operator to breathe on the detector, of course.