off topic....

[atec77]

On 16/10/2010 5:51 AM, Baron wrote:

mark krawczuk Inscribed thus:

mmm its very simple you just complicate things.....


i actually have a jet with a 1.17 mm hole ...... i want to
increase it by 33% .... what size drill do i use... simple.....
physical facts ???????? i`m using a differant fuel, and i have
to flow 33% more of this type of fuel..
very simple,


mark k

Diameter divided by 100 times 100 plus the percentage ie
1.17/100=0.0117 times 133=1.55610
easy ;-)

calculator does 1.17 x 1.33 = 1.5561 near enough

--
X-No-Archive: Yes

 

[terryc]

On Fri, 15 Oct 2010 08:26:11 +0930, mark krawczuk wrote:

hi, i`m trying to find if theres a table or calculator online that

rec.crafts.metalworking perhaps?

 

[who where]

On Sat, 16 Oct 2010 00:09:04 +1000, atec77 <atec77@hotmail.com> wrote:

On 15/10/2010 11:19 PM, who where wrote:
On Fri, 15 Oct 2010 11:38:20 +0930, "mark krawczuk"
krawczuk@adam.com.au> wrote:

ummmm i know crap all about spread sheets and such.....

its like asking you to do something which you have NO KNOWLEDGE about
...... thats why i ask here,.,...

mark

Can you drive a slide rule?

"who where"<noone@home.net> wrote in message
news:r28fb6d465dnigakmdr07tokvclq1o19id@4ax.com...
On Fri, 15 Oct 2010 08:26:11 +0930, "mark krawczuk"
krawczuk@adam.com.au> wrote:

hi, i`m trying to find if theres a table or calculator online that
will
allow me to plug in a diameter of a hole in mm (i.e 1.5 mm ,
carburettor jet ..) then plug in the % increase ... i.e 33 % , , then
hopefully that will tell me what size drill to use to acheive a 33 % in
size
of hole.

i`ve had a darn good look , but i cannot find anything !!

Crikey, a four-second Excel spreadsheet exercise.


Have to be my age or an engineer to know ?

I'm at least one of those.

 

[who where]

On Sat, 16 Oct 2010 08:19:42 +1000, atec77 <atec77@hotmail.com> wrote:

On 16/10/2010 5:51 AM, Baron wrote:
mark krawczuk Inscribed thus:

mmm its very simple you just complicate things.....


i actually have a jet with a 1.17 mm hole ...... i want to
increase it by 33% .... what size drill do i use... simple.....
physical facts ???????? i`m using a differant fuel, and i have
to flow 33% more of this type of fuel..
very simple,


mark k

Diameter divided by 100 times 100 plus the percentage ie
1.17/100=0.0117 times 133=1.55610
easy ;-)

calculator does 1.17 x 1.33 = 1.5561 near enough

I think he's after an AREA increase, not diameter.

 

[atec77]

On 16/10/2010 10:44 AM, who where wrote:

On Sat, 16 Oct 2010 08:19:42 +1000, atec77<atec77@hotmail.com> wrote:

On 16/10/2010 5:51 AM, Baron wrote:
mark krawczuk Inscribed thus:

mmm its very simple you just complicate things.....


i actually have a jet with a 1.17 mm hole ...... i want to
increase it by 33% .... what size drill do i use... simple.....
physical facts ???????? i`m using a differant fuel, and i have
to flow 33% more of this type of fuel..
very simple,


mark k

Diameter divided by 100 times 100 plus the percentage ie
1.17/100=0.0117 times 133=1.55610
easy ;-)

calculator does 1.17 x 1.33 = 1.5561 near enough

I think he's after an AREA increase, not diameter.
Thing is being fuel irt isn't a simple matter as the variations in fuel

density and pressure change with swept area of the aperture to its
better to go rich although in this case I think a 1.45 drill will be
very close

 

[mark krawczuk]

can you drive a space shuttle . ?



"who where" <noone@home.net> wrote in message
news:26lgb6h1u4imqnr7vsn5b4jm02pbkp4h8p@4ax.com...

On Fri, 15 Oct 2010 11:38:20 +0930, "mark krawczuk"
krawczuk@adam.com.au> wrote:

ummmm i know crap all about spread sheets and such.....

its like asking you to do something which you have NO KNOWLEDGE
about
...... thats why i ask here,.,...

mark

Can you drive a slide rule?

"who where" <noone@home.net> wrote in message
news:r28fb6d465dnigakmdr07tokvclq1o19id@4ax.com...
On Fri, 15 Oct 2010 08:26:11 +0930, "mark krawczuk"
krawczuk@adam.com.au> wrote:

hi, i`m trying to find if theres a table or calculator online that
will
allow me to plug in a diameter of a hole in mm (i.e 1.5 mm ,
carburettor jet ..) then plug in the % increase ... i.e 33 % , ,
then
hopefully that will tell me what size drill to use to acheive a 33 % in
size
of hole.

i`ve had a darn good look , but i cannot find anything !!

Crikey, a four-second Excel spreadsheet exercise.

 

[Alan]

On Fri, 15 Oct 2010 21:23:11 +0800, who where <noone@home.net> wrote:

On Fri, 15 Oct 2010 16:26:50 +1300, David Shorter
dazzreal@ihug.co.nz> wrote:

On 15/10/2010 11:56 a.m., mark krawczuk wrote:
hi, i`m trying to find if theres a table or calculator online that will
allow me to plug in a diameter of a hole in mm (i.e 1.5 mm ,
carburettor jet ..) then plug in the % increase ... i.e 33 % , , then
hopefully that will tell me what size drill to use to acheive a 33 % in size
of hole.

i`ve had a darn good look , but i cannot find anything !!

mark


Hi,

I'm assuming you have a calculator that has "pi", "squared" and "square root" buttons.

Proceed as follows:

(radius of existing jet) [squared] [multiply] [pi] [multiply] (area increase) [divide] [pi] [=] [square root]

This will give you the required radius.

(....) are numbers you enter

[....] are function buttons you press

Your area increase of 33% should be entered as 1.33

The radius is half the diameter (I'm assuming you already know this but .....)



The answer is 1.73mm diameter.

Hope this all makes sense.


p.s. In this case you can enter the the diameter instead of the radius and the answer will the be the required diameter.

Can you explain why you felt the need to include pi in the equation?
You don't need to calculate the actual_area, just the ratio.

So the O/P enters the required ratio (1.33 as you indicated for his
example 33% CSA increase), take the square root, and multiply that by
the original size.

I agree with your method of calculation. No necessity to involve pi in
any way.

Be careful as well of the 1.73mm answer as that was calculated using
an initial diameter of 1.5mm and not 1.17mm!
--
Sell your surplus electronic components at
http://ozcomponents.com
Search or browse for that IC, capacitor,
crystal or other component you need.
Or find new components at http://auscomponents.com

 

[Dennis]

"mark krawczuk" <krawczuk@adam.com.au> wrote in message
news:Gdedne70isUCaiXRnZ2dnUVZ_tWdnZ2d@adnap.net.au...

can you drive a space shuttle . ?

Are shuttles driven or ridden?

 

[who where]

On Sat, 16 Oct 2010 11:25:39 +0930, "mark krawczuk"
<krawczuk@adam.com.au> wrote:

can you drive a space shuttle . ?

No (and it probably wouldn't help with your problem - the one you
posted), but I can still remember how to operate a slide rule and it
would help with your calculation.

"who where" <noone@home.net> wrote in message
news:26lgb6h1u4imqnr7vsn5b4jm02pbkp4h8p@4ax.com...
On Fri, 15 Oct 2010 11:38:20 +0930, "mark krawczuk"
krawczuk@adam.com.au> wrote:

ummmm i know crap all about spread sheets and such.....

its like asking you to do something which you have NO KNOWLEDGE
about
...... thats why i ask here,.,...

mark

Can you drive a slide rule?

"who where" <noone@home.net> wrote in message
news:r28fb6d465dnigakmdr07tokvclq1o19id@4ax.com...
On Fri, 15 Oct 2010 08:26:11 +0930, "mark krawczuk"
krawczuk@adam.com.au> wrote:

hi, i`m trying to find if theres a table or calculator online that
will
allow me to plug in a diameter of a hole in mm (i.e 1.5 mm ,
carburettor jet ..) then plug in the % increase ... i.e 33 % , ,
then
hopefully that will tell me what size drill to use to acheive a 33 % in
size
of hole.

i`ve had a darn good look , but i cannot find anything !!

Crikey, a four-second Excel spreadsheet exercise.

 

[who where]

On Sat, 16 Oct 2010 11:21:09 +1000, atec77 <atec77@hotmail.com> wrote:

On 16/10/2010 10:44 AM, who where wrote:
On Sat, 16 Oct 2010 08:19:42 +1000, atec77<atec77@hotmail.com> wrote:

On 16/10/2010 5:51 AM, Baron wrote:
mark krawczuk Inscribed thus:

mmm its very simple you just complicate things.....


i actually have a jet with a 1.17 mm hole ...... i want to
increase it by 33% .... what size drill do i use... simple.....
physical facts ???????? i`m using a differant fuel, and i have
to flow 33% more of this type of fuel..
very simple,


mark k

Diameter divided by 100 times 100 plus the percentage ie
1.17/100=0.0117 times 133=1.55610
easy ;-)

calculator does 1.17 x 1.33 = 1.5561 near enough

I think he's after an AREA increase, not diameter.
Thing is being fuel irt isn't a simple matter as the variations in fuel
density and pressure change with swept area of the aperture to its
better to go rich although in this case I think a 1.45 drill will be
very close

I'm assuming he's done the research on those aspects (viscosity
gradient, reynolds number etc) and has decided that the 33% larger CSA
is the target he's happy with.

1.17 * SQRT(1.33) = 1.35

 

[atec77]

On 16/10/2010 8:56 PM, who where wrote:

On Sat, 16 Oct 2010 11:21:09 +1000, atec77<atec77@hotmail.com> wrote:



calculator does 1.17 x 1.33 = 1.5561 near enough

I think he's after an AREA increase, not diameter.
Thing is being fuel irt isn't a simple matter as the variations in fuel
density and pressure change with swept area of the aperture to its
better to go rich although in this case I think a 1.45 drill will be
very close

I'm assuming he's done the research on those aspects (viscosity
gradient, reynolds number etc) and has decided that the 33% larger CSA
is the target he's happy with.

1.17 * SQRT(1.33) = 1.35
I still wonder how the 33% was determined hence my suggestion of

slightly larger

--
X-No-Archive: Yes

 

[kreed]

On Oct 15, 12:08 pm, "mark krawczuk" <krawc...@adam.com.au> wrote:

ummmm  i know crap all about spread sheets and such.....

its like asking you  to do something  which you have   NO  KNOWLEDGE   about
......  thats why  i ask here,.,...

mark

Using Open Office Calc or MS excel, you can do a lot of amazing stuff.

Even regardless of this current problem with the diameter,

I think you would benefit a lot and find it incredibly useful
in all sorts of areas by learning some basic stuff about these
spreadsheet programs.

I did a lot of our tax and basic records in this form and its very
good, you can set it up however you want
for whatever things interest you.


There are a lot of free starters online if you want to search.

"who where" <no...@home.net> wrote in message

news:r28fb6d465dnigakmdr07tokvclq1o19id@4ax.com...

On Fri, 15 Oct 2010 08:26:11 +0930, "mark krawczuk"
krawc...@adam.com.au> wrote:

hi,  i`m trying to find  if theres a   table or calculator online that
will
allow me to  plug in a    diameter of a  hole  in mm   (i.e 1.5 mm ,
carburettor jet ..)  then plug in the  %  increase ...  i.e 33 %  , , then
hopefully that will tell me what size drill to use to acheive a 33 % in
size
of hole.

 i`ve had a  darn good look  , but i cannot find anything !!

Crikey, a four-second Excel spreadsheet exercise.

 

[David Shorter]

On 16/10/2010 4:59 p.m., Alan wrote:

On Fri, 15 Oct 2010 21:23:11 +0800, who where<noone@home.net> wrote:

On Fri, 15 Oct 2010 16:26:50 +1300, David Shorter
dazzreal@ihug.co.nz> wrote:

On 15/10/2010 11:56 a.m., mark krawczuk wrote:
hi, i`m trying to find if theres a table or calculator online that will
allow me to plug in a diameter of a hole in mm (i.e 1.5 mm ,
carburettor jet ..) then plug in the % increase ... i.e 33 % , , then
hopefully that will tell me what size drill to use to acheive a 33 % in size
of hole.

i`ve had a darn good look , but i cannot find anything !!

mark


Hi,

I'm assuming you have a calculator that has "pi", "squared" and "square root" buttons.

Proceed as follows:

(radius of existing jet) [squared] [multiply] [pi] [multiply] (area increase) [divide] [pi] [=] [square root]

This will give you the required radius.

(....) are numbers you enter

[....] are function buttons you press

Your area increase of 33% should be entered as 1.33

The radius is half the diameter (I'm assuming you already know this but .....)



The answer is 1.73mm diameter.

Hope this all makes sense.


p.s. In this case you can enter the the diameter instead of the radius and the answer will the be the required diameter.

Can you explain why you felt the need to include pi in the equation?
You don't need to calculate the actual_area, just the ratio.

So the O/P enters the required ratio (1.33 as you indicated for his
example 33% CSA increase), take the square root, and multiply that by
the original size.

I agree with your method of calculation. No necessity to involve pi in
any way.

He gave the impression that he didn't understand areas, not just the ratio am so I took him through
the steps that calculate the area which should help him to get a better understanding of what he's
trying to achieve.

Be careful as well of the 1.73mm answer as that was calculated using
an initial diameter of 1.5mm and not 1.17mm!

Well he did give the diameter as 1.5mm in his first post.

--
Sell your surplus electronic components at
http://ozcomponents.com
Search or browse for that IC, capacitor,
crystal or other component you need.
Or find new components at http://auscomponents.com

--

Regards,
David Shorter

Any error in tact, fact or spelling is entirely
due to transmission error.

 

[Mr.T]

"who where" <noone@home.net> wrote in message
news:6s0jb65ko4onmmhoegikkdttaneklbth9i@4ax.com...

I'm assuming he's done the research on those aspects (viscosity
gradient, reynolds number etc) and has decided that the 33% larger CSA
is the target he's happy with.

So you think he could do all that research and not work out how to calculate
a 33% increase in CSA?
I'm doubtful to say the least

MrT.

 

[who where]

On Sat, 16 Oct 2010 21:11:34 +1000, atec77 <atec77@hotmail.com> wrote:

On 16/10/2010 8:56 PM, who where wrote:
On Sat, 16 Oct 2010 11:21:09 +1000, atec77<atec77@hotmail.com> wrote:



calculator does 1.17 x 1.33 = 1.5561 near enough

I think he's after an AREA increase, not diameter.
Thing is being fuel irt isn't a simple matter as the variations in fuel
density and pressure change with swept area of the aperture to its
better to go rich although in this case I think a 1.45 drill will be
very close

I'm assuming he's done the research on those aspects (viscosity
gradient, reynolds number etc) and has decided that the 33% larger CSA
is the target he's happy with.

1.17 * SQRT(1.33) = 1.35
I still wonder how the 33% was determined hence my suggestion of
slightly larger

He may well have found a reference in some forum, or equally likely
pulled it out of his arse. I've only been trying to point him towards
a solution methodology, but if spreadsheets and slide rules dazzle him
then I'm close to giving up.

 

[who where]

On Sun, 17 Oct 2010 10:27:51 +1100, "Mr.T" <MrT@home> wrote:

"who where" <noone@home.net> wrote in message
news:6s0jb65ko4onmmhoegikkdttaneklbth9i@4ax.com...
I'm assuming he's done the research on those aspects (viscosity
gradient, reynolds number etc) and has decided that the 33% larger CSA
is the target he's happy with.

So you think he could do all that research and not work out how to calculate
a 33% increase in CSA?
I'm doubtful to say the least

MrT.

I was being kind. See my reply to atec77.

 

[Alan]

On Sun, 17 Oct 2010 03:06:03 +1300, David Shorter
<dazzreal@ihug.co.nz> wrote:

On 16/10/2010 4:59 p.m., Alan wrote:
On Fri, 15 Oct 2010 21:23:11 +0800, who where<noone@home.net> wrote:

On Fri, 15 Oct 2010 16:26:50 +1300, David Shorter
dazzreal@ihug.co.nz> wrote:

On 15/10/2010 11:56 a.m., mark krawczuk wrote:
hi, i`m trying to find if theres a table or calculator online that will
allow me to plug in a diameter of a hole in mm (i.e 1.5 mm ,
carburettor jet ..) then plug in the % increase ... i.e 33 % , , then
hopefully that will tell me what size drill to use to acheive a 33 % in size
of hole.

i`ve had a darn good look , but i cannot find anything !!


The answer is 1.73mm diameter.

Be careful as well of the 1.73mm answer as that was calculated using
an initial diameter of 1.5mm and not 1.17mm!

Well he did give the diameter as 1.5mm in his first post.

I realised that, but the OP changed the diameter part way through so I
just wanted to warn him not to take some of the answers on here as
gospel!

--
Sell your surplus electronic components at
http://ozcomponents.com
Search or browse for that IC, capacitor,
crystal or other component you need.
Or find new components at http://auscomponents.com

 

[atec77]

On 17/10/2010 11:10 PM, mark krawczuk wrote:

man , its easy , the fuel i WANT TO USE has to flow 33% more than
the fuel i WAS USING..
mark k

You said that but is the information accurate and fix your computer
clock thanks

 

[Dennis]

Ignore them Mark, they are taking the piss. It's an acronym for "Cute Sexy
Arse". Some of these guys couldn't even spell engineerring!



"mark krawczuk" <krawczuk@adam.com.au> wrote in message
news:ksCdnTEfnssPeifRnZ2dnUVZ_oudnZ2d@adnap.net.au...

what the hell is csa ????


its just a simple calculation ( for some !!!!) and theres always people
who always think of a complicated answer.
mark



"Mr.T" <MrT@home> wrote in message
news:4cba3548$0$316$afc38c87@news.optusnet.com.au...

"who where" <noone@home.net> wrote in message
news:6s0jb65ko4onmmhoegikkdttaneklbth9i@4ax.com...
I'm assuming he's done the research on those aspects (viscosity
gradient, reynolds number etc) and has decided that the 33% larger CSA
is the target he's happy with.

So you think he could do all that research and not work out how to
calculate
a 33% increase in CSA?
I'm doubtful to say the least

MrT.

 

[mark krawczuk]

man , its easy , the fuel i WANT TO USE has to flow 33% more than
the fuel i WAS USING..
mark k


"atec77" <atec77@hotmail.com> wrote in message
news:i9c19a$l9e$1@news.eternal-september.org...

On 16/10/2010 8:56 PM, who where wrote:
On Sat, 16 Oct 2010 11:21:09 +1000, atec77<atec77@hotmail.com> wrote:



calculator does 1.17 x 1.33 = 1.5561 near enough

I think he's after an AREA increase, not diameter.
Thing is being fuel irt isn't a simple matter as the variations in fuel
density and pressure change with swept area of the aperture to its
better to go rich although in this case I think a 1.45 drill will be
very close

I'm assuming he's done the research on those aspects (viscosity
gradient, reynolds number etc) and has decided that the 33% larger CSA
is the target he's happy with.

1.17 * SQRT(1.33) = 1.35
I still wonder how the 33% was determined hence my suggestion of
slightly larger

--
X-No-Archive: Yes