M
Mark Folsom
Guest
"mike" <spamme0@juno.com> wrote in message news:3FD7AFA5.1010001@juno.com...
half that in 50 us. Here's an exact quote of what I wrote in a previous
post:
"I have two capacitors that I am charging in series, with a lot of noise, in
about 50 microseconds--then discharging in parallel. I use some diodes to
allow that to happen--I modeled it and then built it and it works and allows
me to get a lot more energy than I do by charging them from the same source
in parallel. The capacitors then power a custom timer ASIC that draws about
5 microamps. At the end of a programable interval that ranges between 100
and 1000 milliseconds, the circuit switches the remaining charge into a 2
ohm resistance. Any device for this function would have to conduct about 8
amps for a few hundred microseconds and have less than a quarter ohm
resistance when in the on condition.
The diodes that we use to switch from series to parallel seem to have enough
capacitance to keep the output up to the charging voltage until a little
charge is drawn off. It appears to take less than two microseconds to go
from 52 volts to 26 volts when the capacitors are loaded with 12kohm on the
output."
It explicitly says that it goes from 52 to 26 volts in a couple of
microseconds, with a 12 kohm load. It doesn't do that by draining the
charge on the two caps--it drains a much smaller unintended capacitance in
the circuit while changing the effective configuration of the caps from
series to parallel.
capacitance of some diodes in the circuit.
60 volts is applied and then conducts with less than 0.25 ohm resistance for
as long as voltage remains positive. And it needs to draw off a few
nanocoulombs before it switches. And it needs to be tiny. What's
complicated?
Mark Folsom
I have two 1 uf capacitors. It isn't a 5 uA load that takes it from 60 V toMark Folsom wrote:
[snip]
Ok, so I'm playing 20-questions, reverse engineering a secret design to
help someone who's calling me names.
I think that's called masochism.
But I'm bored, and I really am a nice guy (most of the time), so here
goes.
Interesting little details the 8 amps and 2 ohms.
Would have been nice to have that information in the beginning.
Let's do a back of the envelope approximation.
If your tiny bit of charge is the 5 uA load that takes your caps from
60V to half that in 50 uS, you have about 8.3 pF of capacitance.
half that in 50 us. Here's an exact quote of what I wrote in a previous
post:
"I have two capacitors that I am charging in series, with a lot of noise, in
about 50 microseconds--then discharging in parallel. I use some diodes to
allow that to happen--I modeled it and then built it and it works and allows
me to get a lot more energy than I do by charging them from the same source
in parallel. The capacitors then power a custom timer ASIC that draws about
5 microamps. At the end of a programable interval that ranges between 100
and 1000 milliseconds, the circuit switches the remaining charge into a 2
ohm resistance. Any device for this function would have to conduct about 8
amps for a few hundred microseconds and have less than a quarter ohm
resistance when in the on condition.
The diodes that we use to switch from series to parallel seem to have enough
capacitance to keep the output up to the charging voltage until a little
charge is drawn off. It appears to take less than two microseconds to go
from 52 volts to 26 volts when the capacitors are loaded with 12kohm on the
output."
It explicitly says that it goes from 52 to 26 volts in a couple of
microseconds, with a 12 kohm load. It doesn't do that by draining the
charge on the two caps--it drains a much smaller unintended capacitance in
the circuit while changing the effective configuration of the caps from
series to parallel.
I told you I thought the capacitance that kept the voltage up was the tinyWhen you discharge that into 2 ohms, you have a time constant of
16.6 picoseconds.
So, you need a deivce that can switch 8 amps and get that 16pS time
constant to last a few hundred microseconds.
I expect that's not what you meant. Can you see why some of us might
be more than a little confused by a descrepancy that's 4 orders of
magnitude?
capacitance of some diodes in the circuit.
I want a device that blocks current for about 100 microseconds after 50 toSo, I guess I am an ignorant jerk that just can't understand what you're
trying to do even after I've read it.
If you're gonna hide the details, at least try to have some consistency
in the numbers you do post. My subscription to the psychic hotline
has expired.
60 volts is applied and then conducts with less than 0.25 ohm resistance for
as long as voltage remains positive. And it needs to draw off a few
nanocoulombs before it switches. And it needs to be tiny. What's
complicated?
Mark Folsom