H
HC
Guest
On Feb 15, 10:38 pm, John Popelish <jpopel...@rica.net> wrote:
bookmarked that.
What I've been intending to use as the "messenger" wire for the relay
is some 24 gauge wire I have already (from where and when I don't
recall; it's followed me for about 10 years now).
If I understand you correctly, the resistance of the wire for this
distance and for this load (the relay coil) is not significant enough
to worry about, within some parameters. I went and measured my
relay's coil resistance and found it to be 308 ohms. I then applied
11.89 volts (according to my DVM) from my proto-board and measured
37.7 mA (using the same DVM) across the relay coil with that voltage.
I guess all I needed to measure was the 308 ohms, but since I was
there it seemed useful to measure the rest. I ran it through the
equations I have for power (Watts) and Ohm's Law, just to see if my
measurements were right and got numbers that seem good.
1/20th of the 308 would be 15.4 ohms, so, you're saying I could add up
to 15.4 ohms of round-trip "messenger" wire to the relay, on a 12VDC
supply, and it would be okay? So, looking at the chart you linked to,
24 gauge has 38.958 feet per ohm so I could run, round-trip, roughly
600 feet?
I really am an amateur at this stuff and I've seen your posts all over
the place helping people so I ask the following with no ill-will or
attitude towards you; you said that a 2W coil would be about a 288 ohm
coil. I tried to get that (because I want to be able to calculate
this information for other relays and to better understand this stuff)
assuming a 12 volt DC supply and I did a calculation for current with
P = I E so I = 2W / 12V and got I = 0.1667A. I put that into E = I R
solving for R = 12V / 0.1667A, R = 72 ohms. What have I done wrong?
Thank you very much again for your reply. It helped a lot. I will
set up a test rig to verify that the numbers I work out on paper are
accurate but I'm confident this will work. This is going to simplify
my project quite a bit (not having to use a 24 VAC supply to try to
run 12 VDC relays).
--HC
Hey, John, thank you for your reply. That wire link is cool and I'veHC wrote:
Hey, all, I'm not sure if this can be done but here's what I am trying
to do and how I've tried to go about doing it.
I want to be able to control 120VAC devices some distance away from a
controller, say, up to 100 feet or so. I would like to run the 120VAC
to the device through a switch (relay) at the device with no other
switches or control devices in line from the breaker. Then I would
like to have the controller turn that relay on and off to control the
device. The idea is that I could run the thicker, high-voltage lines
directly to the device and then use smaller wire to operate a relay at
the device to turn it on and off instead of running the high-voltage
wire to each switch I would like to use.
Since I have a boat-load of low-cost 12VDC relays that can switch up
to 250VAC and 15 amps and since 24VAC relays seem, in my searching, to
be a lot more expensive and harder to come by (they seem to be, in my
searching, related to HVAC and other "industrial" uses; they're not
like the overly-abundant 12VDC relays we have for our cars and such) I
would like to use a 12VDC relay at the device. However, I'm afraid
that if I attempt to use 12VDC to control these relays over a distance
like I mention of up to 100 feet that the line-loss will be
significant (on 12VDC). I was thinking that using 24VAC would be much
better (it's higher voltage and it's AC, so line-loss should be quite
a bit less than 12VDC).
(snip)
For the same coil power, the 24 volt relay will need about
1/4 of the copper to operate over the distance. AC relays
are not quite as efficient as DC relays are and have an
inductive current component added to that which powers the
coil, so the actual improvement may be closer to 3 to 1 or
even 2 to 1.
But 100 feet is not so far for a couple watt 12 volt coil.
How fine a wire do you want to use to drive the coil?
Measure the coil resistance and use a wire table to figure
out how many ohms you can afford in series with that (maybe
1/20th of the coil resistance for 200 feet of wire.
For instance if your have a relay that has a 2 watt coil
(many are lower than this) that would be about a 288 ohm
coil. So you would loose only about 5% of the drive voltage
if the wire loop added another 288/20=14.4 ohms. You could
use higher resistance wire if you had a bit more than 12
volts to drive the loop.
Taking a look at a wire table,http://www.pupman.com/listarchives/1998/April/msg00189.html
the size that has less then 14.4 ohms for 200 feet would be
AWG 28, which is really fine. Something like cheap 22 AWG
speaker wire would have a resistance of only about 3.2 ohms
for the 200 feet, and that would drop only
12*3.2/(288+3.2)=0.13 volts or about 1% of the 12 volts.
You really do not have much of a problem to solve.
--
Regards,
John Popelish
bookmarked that.
What I've been intending to use as the "messenger" wire for the relay
is some 24 gauge wire I have already (from where and when I don't
recall; it's followed me for about 10 years now).
If I understand you correctly, the resistance of the wire for this
distance and for this load (the relay coil) is not significant enough
to worry about, within some parameters. I went and measured my
relay's coil resistance and found it to be 308 ohms. I then applied
11.89 volts (according to my DVM) from my proto-board and measured
37.7 mA (using the same DVM) across the relay coil with that voltage.
I guess all I needed to measure was the 308 ohms, but since I was
there it seemed useful to measure the rest. I ran it through the
equations I have for power (Watts) and Ohm's Law, just to see if my
measurements were right and got numbers that seem good.
1/20th of the 308 would be 15.4 ohms, so, you're saying I could add up
to 15.4 ohms of round-trip "messenger" wire to the relay, on a 12VDC
supply, and it would be okay? So, looking at the chart you linked to,
24 gauge has 38.958 feet per ohm so I could run, round-trip, roughly
600 feet?
I really am an amateur at this stuff and I've seen your posts all over
the place helping people so I ask the following with no ill-will or
attitude towards you; you said that a 2W coil would be about a 288 ohm
coil. I tried to get that (because I want to be able to calculate
this information for other relays and to better understand this stuff)
assuming a 12 volt DC supply and I did a calculation for current with
P = I E so I = 2W / 12V and got I = 0.1667A. I put that into E = I R
solving for R = 12V / 0.1667A, R = 72 ohms. What have I done wrong?
Thank you very much again for your reply. It helped a lot. I will
set up a test rig to verify that the numbers I work out on paper are
accurate but I'm confident this will work. This is going to simplify
my project quite a bit (not having to use a 24 VAC supply to try to
run 12 VDC relays).
--HC