J
John Larkin
Guest
On Wed, 14 Jun 2023 11:38:33 -0700 (PDT), whit3rd <whit3rd@gmail.com>
wrote:
C may not be literal capacitance, but shoot-through current
equivalent.
wrote:
On Wednesday, June 14, 2023 at 1:06:37?PM UTC-4, John Larkin wrote:
On Tue, 13 Jun 2023 13:04:09 -0700 (PDT), Ricky
gnuarm.del...@gmail.com> wrote:
32768 Hz is not \"fast\" in any sense. The energy used in digital logic is due to charging and discharging the capacitance of the circuit elements.
P = 1/2 C F V^2, where P is power, C is capacitance, F is frequency and V is voltage.
C F V^2. Both edges burn power.
Two other fine points: C for a gate is proportional to its output current limit, so less current
means you can design low-C transistors that burn less power. Clocking a flipflop (ripple or
synchronous counter) has a strict dV/dt requirement (CD4013 max rise time 10 us at 5V),
so lower current inputs don\'t suffice to drive it as a divider; watches use different CMOS.
Also, this is about driving a capacitive load, i.e. an electrostatic motor, where there\'s
a torque because rotation raises the capacitance of the most-charged stator elements.
That \"C\" in the formula isn\'t a constant for this case.
C may not be literal capacitance, but shoot-through current
equivalent.