T
Tom Gardner
Guest
On 23/05/19 19:45, John Larkin wrote:
A resistor in the liquid or pan's metal is 100% efficient. A
poorly thermally coupled resistor is not.
One point about induction hobs is that the "resistor" is
inside the pan's metal. Certainly the pans do heat up fast,
the heat source to the pan can be turned off rapidly (cf
conventional electric hobs), and the hob surface stays warm,
not hot.
On Thu, 23 May 2019 09:19:35 -0700, Joerg <news@analogconsultants.com
wrote:
On 2019-05-23 09:04, John Larkin wrote:
On Thu, 23 May 2019 08:29:49 -0700, Joerg <news@analogconsultants.com
wrote:
Thinking about induction cooktops for beer brewing because the two 1kW
burners that my brew kettle straddles result in a whopping 2h+ total
just to heat up stuff. On Belgian beers more like 3h. Induction cooktops
can be had with 1.8kW but realistically more like 1.5kW on a 15A
circuit. That's more and supposedly the induction method is more efficient.
Inductive heating must be less efficient than resistive. Resistive is
best if you can make a good thermal connection to your kettle.
From what I heard and read so far inductiove is more efficient. Power
loss in the bridge FETs and coil is so low that a small fan suffices but
there is almost no more transfer loss.
A resistor is 100% efficient. The only better thing would be a heat
pump.
A resistor in the liquid or pan's metal is 100% efficient. A
poorly thermally coupled resistor is not.
One point about induction hobs is that the "resistor" is
inside the pan's metal. Certainly the pans do heat up fast,
the heat source to the pan can be turned off rapidly (cf
conventional electric hobs), and the hob surface stays warm,
not hot.