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Guest
I hope you all can explain this to me.
Let's assume we have an AC adapter with only a small number of parts,
a step-down transformer and 1 to 4 diodes.
Let's assume that the primary of the adpater uses 0.1 amps at 120
volts. (I don't think it matters for the sake of this question how
much the device itself uses. We can pretend that there are no losses
and it has an output of 1 amp at 12 volts, and powers a device that
uses the full amp. Or that the device uses less than that.)
So in this case when the device is on, it's consuming 12 watts from
the power company. The primary of the AC adapter is using 12 watts.
Roughly, with an adapter of typical, simple, only 5 parts, design, how
much in watts would the adapter use if the device were turned off,
that is, if the secondary circuit of the adapter were open? The
primary circuit would still be closed. The inductive impedance of the
primary winding would go up -- it took me years to figure that out --
but I have no idea how much.
2) Yesterday, someone gave me a broken AC adapter used to power a
Westell DSL modem. I broke it open and instead of the 5 or 6 parts
such things used to have, this one had about 25 parts, including a
small transformer and what looked like another winding on a metal
core. Plus 3 big caps (one or more filter caps), I need more light
and better glasses to count the diodes, one transistor, and something
looking like a little glass fuse but with a white sandy body.
Something this complicated must be smarter than earlier adapters.
Does that mean it uses less current when the device intended to be
powered is Off? Any idea how much a 25-part adapter like this uses
when the devices is Off, assuming when it's On it uses 12 watts?
Thanks.
Let's assume we have an AC adapter with only a small number of parts,
a step-down transformer and 1 to 4 diodes.
Let's assume that the primary of the adpater uses 0.1 amps at 120
volts. (I don't think it matters for the sake of this question how
much the device itself uses. We can pretend that there are no losses
and it has an output of 1 amp at 12 volts, and powers a device that
uses the full amp. Or that the device uses less than that.)
So in this case when the device is on, it's consuming 12 watts from
the power company. The primary of the AC adapter is using 12 watts.
Roughly, with an adapter of typical, simple, only 5 parts, design, how
much in watts would the adapter use if the device were turned off,
that is, if the secondary circuit of the adapter were open? The
primary circuit would still be closed. The inductive impedance of the
primary winding would go up -- it took me years to figure that out --
but I have no idea how much.
2) Yesterday, someone gave me a broken AC adapter used to power a
Westell DSL modem. I broke it open and instead of the 5 or 6 parts
such things used to have, this one had about 25 parts, including a
small transformer and what looked like another winding on a metal
core. Plus 3 big caps (one or more filter caps), I need more light
and better glasses to count the diodes, one transistor, and something
looking like a little glass fuse but with a white sandy body.
Something this complicated must be smarter than earlier adapters.
Does that mean it uses less current when the device intended to be
powered is Off? Any idea how much a 25-part adapter like this uses
when the devices is Off, assuming when it's On it uses 12 watts?
Thanks.