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On Saturday, November 12, 2022 at 9:07:06 AM UTC-5, Joe wrote:
On Sat, 12 Nov 2022 12:03:58 -0000
\"Commander Kinsey\" <C...@nospam.com> wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwal...@gmail.com> wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey
wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky
gnuarm.del...@gmail.com> wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul
nos...@needed.invalid> wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to
charge! No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense
to have anything in the cable unless the currents are so high,
they would overheat a typical cable.
Charging cables have no connection on the data lines, they
advertise them as being secure - you can charge your phone on an
aeroplane or in a cafe without risking someone hacking into your
phone. So resistors on data lines within the power supply cannot
possibly do anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for
it flat out until the voltage drop on the power supply causes it
to use less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when they
did that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at
5V but some can also deliver 9V, 12V, 15V and 20V and in some cases
lots of smaller steps in between. My pixel3a phone likes to charge
at 9V for example. I have a notebook PC that prefers to charge at
20V. if it can. Very high power USB chargers can deliver up to 48V
at up to 5A giving a maximum output power of 240W.
The more exotic combinations (more than 20V or more than 3A) will
only work with special cables that have identity chips which
specify the current and voltage rating of the cable and connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Surely nowadays the charger is in the device being charged, and is fed
the 5V (or whatever) directly?
For modern devices like cell phones and tablets, part of the charger is
in the device, part in the charger it\'s connected to. Modern devices conform
to either Quickcharge or PD power specs that specify many possible
charging voltages and currents. The device being charged negotiates with
the wall charger over the USB, the wall charger tells it what it\'s capable of
and then the device tells the charger what it wants. The charging voltage
requested can also change as the battery is partially charged.
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker <jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com
wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to
have anything in the cable unless the currents are so high, they
would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise
them as being secure - you can charge your phone on an aeroplane or
in a cafe without risking someone hacking into your phone. So
resistors on data lines within the power supply cannot possibly do
anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for it
flat out until the voltage drop on the power supply causes it to use
less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V
but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps
in between.
My pixel3a phone likes to charge at 9V for example. I have a notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving
a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will only
work with special
cables that have identity chips which specify the current and voltage
rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
On Sat, 12 Nov 2022 16:00:20 -0000, JNugent <jenningsandco@mail.com> wrote:
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker <jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com
wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to
have anything in the cable unless the currents are so high, they
would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise
them as being secure - you can charge your phone on an aeroplane or
in a cafe without risking someone hacking into your phone. So
resistors on data lines within the power supply cannot possibly do
anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for it
flat out until the voltage drop on the power supply causes it to use
less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V
but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps
in between.
My pixel3a phone likes to charge at 9V for example. I have a notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving
a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will only
work with special
cables that have identity chips which specify the current and voltage
rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
Nothing to do with it. For some reason Samsung have decided the input
to the phone shall not exceed 1.1A.
If the CPU and screen are using
750mA, the battery charges very slowly.
On Sat, 12 Nov 2022 15:50:38 -0000, trader_4 <trader4@optonline.net> wrote:
For modern devices like cell phones and tablets, part of the charger is
in the device, part in the charger it\'s connected to. Modern devices conform
to either Quickcharge or PD power specs that specify many possible
charging voltages and currents. The device being charged negotiates with
the wall charger over the USB, the wall charger tells it what it\'s capable of
and then the device tells the charger what it wants. The charging voltage
requested can also change as the battery is partially charged.
And how is this done when you\'re using a charging cable with no data lines?
On 12/11/2022 04:21 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:00:20 -0000, JNugent <jenningsandco@mail.com> wrote:
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker <jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com
wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to
have anything in the cable unless the currents are so high, they
would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise
them as being secure - you can charge your phone on an aeroplane or
in a cafe without risking someone hacking into your phone. So
resistors on data lines within the power supply cannot possibly do
anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for it
flat out until the voltage drop on the power supply causes it to use
less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V
but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps
in between.
My pixel3a phone likes to charge at 9V for example. I have a notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving
a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will only
work with special
cables that have identity chips which specify the current and voltage
rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
Nothing to do with it. For some reason Samsung have decided the input
to the phone shall not exceed 1.1A.
Really?
How did they manage to get Ohm\'s Law repealed?
If the CPU and screen are using
750mA, the battery charges very slowly.
Internal resistance / impedance (depending on whether it is an AC or DC
circuit).
\"Commander Kinsey\" <CK1@nospam.com> writes:
On Sat, 12 Nov 2022 15:50:38 -0000, trader_4 <trader4@optonline.net> wrote:
For modern devices like cell phones and tablets, part of the charger is
in the device, part in the charger it\'s connected to. Modern devices conform
to either Quickcharge or PD power specs that specify many possible
charging voltages and currents. The device being charged negotiates with
the wall charger over the USB, the wall charger tells it what it\'s capable of
and then the device tells the charger what it wants. The charging voltage
requested can also change as the battery is partially charged.
And how is this done when you\'re using a charging cable with no data lines?
Impose a high-frequency AC signal over the DC voltage used for charging.
On Sat, 12 Nov 2022 16:33:32 -0000, JNugent <jenningsandco@mail.com> wrote:
On 12/11/2022 04:21 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:00:20 -0000, JNugent <jenningsandco@mail.com
wrote:
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey
wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com
wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to
have anything in the cable unless the currents are so high, they
would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise
them as being secure - you can charge your phone on an aeroplane or
in a cafe without risking someone hacking into your phone. So
resistors on data lines within the power supply cannot possibly do
anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for it
flat out until the voltage drop on the power supply causes it to use
less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when
they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V
but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps
in between.
My pixel3a phone likes to charge at 9V for example. I have a
notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving
a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will
only
work with special
cables that have identity chips which specify the current and voltage
rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
Nothing to do with it. For some reason Samsung have decided the input
to the phone shall not exceed 1.1A.
Really?
How did they manage to get Ohm\'s Law repealed?
Why do you believe ohms law prevents it drawing 2 amps? 1 amp for the
battery to charge and 1 amp for the screen and CPU?
If the CPU and screen are using
750mA, the battery charges very slowly.
Internal resistance / impedance (depending on whether it is an AC or DC
circuit).
You know perfectly well it\'s DC. Why would they limit the socket to
only be able to power the phone or the battery?
On 12/11/2022 04:52 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:33:32 -0000, JNugent <jennin...@mail.com> wrote:
On 12/11/2022 04:21 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:00:20 -0000, JNugent <jennin...@mail.com
wrote:
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwal...@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey
wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com
wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to
have anything in the cable unless the currents are so high, they
would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise
them as being secure - you can charge your phone on an aeroplane or
in a cafe without risking someone hacking into your phone. So
resistors on data lines within the power supply cannot possibly do
anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for it
flat out until the voltage drop on the power supply causes it to use
less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when
they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V
but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps
in between.
My pixel3a phone likes to charge at 9V for example. I have a
notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving
a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will
only
work with special
cables that have identity chips which specify the current and voltage
rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
Nothing to do with it. For some reason Samsung have decided the input
to the phone shall not exceed 1.1A.
Really?
How did they manage to get Ohm\'s Law repealed?
Why do you believe ohms law prevents it drawing 2 amps? 1 amp for the
battery to charge and 1 amp for the screen and CPU?
Do you understand Ohm\'s law?
What do you understand it to say?
If the CPU and screen are using
750mA, the battery charges very slowly.
Internal resistance / impedance (depending on whether it is an AC or DC
circuit).
You know perfectly well it\'s DC. Why would they limit the socket to
only be able to power the phone or the battery?
On 12/11/2022 04:52 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:33:32 -0000, JNugent
jenningsandco@mail.com> wrote:
On 12/11/2022 04:21 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:00:20 -0000, JNugent
jenningsandco@mail.com> wrote:
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky
gnuarm.del...@gmail.com> wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4,
Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul
nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to
charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no
sense to
have anything in the cable unless the currents are so high,
they would overheat a typical cable.
Charging cables have no connection on the data lines, they
advertise them as being secure - you can charge your phone on
an aeroplane or in a cafe without risking someone hacking
into your phone. So resistors on data lines within the power
supply cannot possibly do anything if you\'re using a charging
cable.
So.... how does a device and power supply work out what rate
to charge? In the absence of data lines, does the device just
go for it flat out until the voltage drop on the power supply
causes it to use less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew
about 570mA. Some motherboards were shutting the USB socket
off when they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start
at 5V but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller
steps in between.
My pixel3a phone likes to charge at 9V for example. I have a
notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A
giving a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A)
will only
work with special
cables that have identity chips which specify the current and
voltage rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a
while to charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
Nothing to do with it. For some reason Samsung have decided the
input to the phone shall not exceed 1.1A.
Really?
How did they manage to get Ohm\'s Law repealed?
Why do you believe ohms law prevents it drawing 2 amps? 1 amp for
the battery to charge and 1 amp for the screen and CPU?
Do you understand Ohm\'s law?
What do you understand it to say?
 If the CPU and screen are using
750mA, the battery charges very slowly.
Internal resistance / impedance (depending on whether it is an AC
or DC circuit).
You know perfectly well it\'s DC. Why would they limit the socket
to only be able to power the phone or the battery?
piss offOn Sat, 12 Nov 2022 16:00:20 +0000, JNugent, another demented, notorious,
troll-feeding, senile idiot, blathered again:
Ohm\'s law?
Or rather another bait set out by the wanker for all you troll-feeding
senile assholes? <G
And how is this done when you\'re using a charging cable with no data lines?
Impose a high-frequency AC signal over the DC voltage used for charging.
Do you understand Ohm\'s law?
What do you understand it to say?
Ohm\'s law?
Or rather another bait set out by the wanker for all you troll-feeding
senile assholes? <G
piss off