C
Commander Kinsey
Guest
I thought the data line was used to signal what current the device requires and what the power supply or computer USB socket is capable of. But aren\'t charging cables missing the data lines?
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On 12/11/2022 04:21 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:00:20 -0000, JNugent <jenningsandco@mail.com
wrote:
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com
wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to
have anything in the cable unless the currents are so high, they
would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise
them as being secure - you can charge your phone on an aeroplane or
in a cafe without risking someone hacking into your phone. So
resistors on data lines within the power supply cannot possibly do
anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for it
flat out until the voltage drop on the power supply causes it to use
less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when they
did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V
but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps
in between.
My pixel3a phone likes to charge at 9V for example. I have a notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving
a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will only
work with special
cables that have identity chips which specify the current and voltage
rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
Nothing to do with it. For some reason Samsung have decided the input
to the phone shall not exceed 1.1A.
Really?
How did they manage to get Ohm\'s Law repealed?
 If the CPU and screen are using 750mA, the battery charges very slowly.
Internal resistance / impedance (depending on whether it is an AC or DC
circuit).
On 12/11/2022 16:33, JNugent wrote:
On 12/11/2022 04:21 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:00:20 -0000, JNugent <jenningsandco@mail.com
wrote:
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey
wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com
wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to
have anything in the cable unless the currents are so high, they
would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise
them as being secure - you can charge your phone on an aeroplane or
in a cafe without risking someone hacking into your phone. So
resistors on data lines within the power supply cannot possibly do
anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for it
flat out until the voltage drop on the power supply causes it to use
less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when
they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V
but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps
in between.
My pixel3a phone likes to charge at 9V for example. I have a
notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving
a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will
only
work with special
cables that have identity chips which specify the current and voltage
rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
Nothing to do with it. For some reason Samsung have decided the
input to the phone shall not exceed 1.1A.
Really?
How did they manage to get Ohm\'s Law repealed?
Intelligent semiconductor circuits simply dont obey it.
On 11/11/2022 8:59 PM, Commander Kinsey wrote:
I thought the data line was used to signal what current the device requires and what the power supply or computer USB socket is capable of. But aren\'t charging cables missing the data lines?
This isn\'t the whole story, but it\'ll fill in what some
of the other sites miss. USB-PD spec is another way to do it,
instead of some of these other earlier attempts.
https://obddiag.net/usb-power.html
That makes it easier to understand why
a cable might matter. As demonstrated here.
It\'s too bad the chart does not have a column
for the \"suspected charging standard\" used in each
case. If they had included some names, it would
make it easier for you to Google each
(proprietary or otherwise) standard.
https://www.extremetech.com/wp-content/uploads/2017/04/USB-FastCharging-640x419.png
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
If you have a 1 ampere wall adapter, and you
use a \"charging cable that indicates 2 amperes\",
then plugging your iPad into that, the iPad believes
the 2 ampere resistor-strap-indication and draws
the 2 amperes, and the wall adapter... shuts off
on overcurrent.
You cannot necessarily join just
any old random cable between wall adapter and device.
The combinations must be intelligently selected by the
person doing this. When using one of the active cable
standards, the hope is the automation avoids
some of the potential issues. Just because one end
of your setup supports USB PD, does not mean the other
end does. You could even join two USB PD devices
with *the wrong cable*.
If you use a USB extension cable, with just the four wires
and no resistors whatsoever, then I would expect the
charging current to be one ampere or less.
I think it would take a significant number of web page
URLs, to cover all the methods. Start Googling
Why the hell aren\'t all these devices using charging pads yet?
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid> wrote:
On 11/11/2022 8:59 PM, Commander Kinsey wrote:
I thought the data line was used to signal what current the device requires and what the power supply or computer USB socket is capable of. But aren\'t charging cables missing the data lines?
This isn\'t the whole story, but it\'ll fill in what some
of the other sites miss. USB-PD spec is another way to do it,
instead of some of these other earlier attempts.
https://obddiag.net/usb-power.html
Interesting, they say \"Samsung devices require 1.2V voltage on both D+ and D- data lines\". I have a Samsung phone which will not charge off one particular 3.1A power supply, but it\'s happy with anything else. Even 500mA chargers below it\'s max current. And the weird thing is it works with a \"charging cable\" which presumably has no data lines, so it can\'t possibly need a voltage on them.
That makes it easier to understand why
a cable might matter. As demonstrated here.
It\'s too bad the chart does not have a column
for the \"suspected charging standard\" used in each
case. If they had included some names, it would
make it easier for you to Google each
(proprietary or otherwise) standard.
https://www.extremetech.com/wp-content/uploads/2017/04/USB-FastCharging-640x419.png
So Google and Samsung are in bed together and are pushing out anything else?
I have a Samsung A10, which no matter what I power it with it only takes 1.1A. But I don\'t have a genuine Samsung charger. Why? Because they don\'t supply them with the phone! It just says use any charger you have lying about!
I can\'t find anywhere what the max charging rate of an A10 is, amazing its not in some specs sheet somewhere! I had to use \"Ampere\", an app to monitor battery charging rate, to work out how much it was taking from various sources.
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge! No data lines, fast charging expected!
On 11/12/2022 1:37 AM, Commander Kinsey wrote:
Why the hell aren\'t all these devices using charging pads yet?
An electric toothbrush I got decades ago charges by induction.
It\'s not an expensive method.
On electronics, this is the inductive charging standard. \"Qi\"
https://en.wikipedia.org/wiki/Qi_%28standard%29
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid> wrote:
On 11/11/2022 8:59 PM, Commander Kinsey wrote:
I thought the data line was used to signal what current the device requires and what the power supply or computer USB socket is capable of. But aren\'t charging cables missing the data lines?
This isn\'t the whole story, but it\'ll fill in what some
of the other sites miss. USB-PD spec is another way to do it,
instead of some of these other earlier attempts.
https://obddiag.net/usb-power.html
Interesting, they say \"Samsung devices require 1.2V voltage on both D+ and D- data lines\". I have a Samsung phone which will not charge off one particular 3.1A power supply, but it\'s happy with anything else. Even 500mA chargers below it\'s max current. And the weird thing is it works with a \"charging cable\" which presumably has no data lines, so it can\'t possibly need a voltage on them.
That is an incorrect assumption, that the charging only cable has nothing on the data pins.
That makes it easier to understand why
a cable might matter. As demonstrated here.
It\'s too bad the chart does not have a column
for the \"suspected charging standard\" used in each
case. If they had included some names, it would
make it easier for you to Google each
(proprietary or otherwise) standard.
https://www.extremetech.com/wp-content/uploads/2017/04/USB-FastCharging-640x419.png
So Google and Samsung are in bed together and are pushing out anything else?
I have a Samsung A10, which no matter what I power it with it only takes 1.1A. But I don\'t have a genuine Samsung charger. Why? Because they don\'t supply them with the phone! It just says use any charger you have lying about!
I can\'t find anywhere what the max charging rate of an A10 is, amazing its not in some specs sheet somewhere! I had to use \"Ampere\", an app to monitor battery charging rate, to work out how much it was taking from various sources.
It\'s a cell phone. What do you expect?
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge! No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to have anything in the cable unless the currents are so high, they would overheat a typical cable.
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid> wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge! No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to have anything in the cable unless the currents are so high, they would overheat a typical cable.
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com> wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid> wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge! No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to have anything in the cable unless the currents are so high, they would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise them as being secure - you can charge your phone on an aeroplane or in a cafe without risking someone hacking into your phone. So resistors on data lines within the power supply cannot possibly do anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to charge? In the absence of data lines, does the device just go for it flat out until the voltage drop on the power supply causes it to use less?
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com> wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid> wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge! No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to have anything in the cable unless the currents are so high, they would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise them as being secure - you can charge your phone on an aeroplane or in a cafe without risking someone hacking into your phone. So resistors on data lines within the power supply cannot possibly do anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to charge? In the absence of data lines, does the device just go for it flat out until the voltage drop on the power supply causes it to use less?
Yes, that is exactly what happens with older chargers.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps in between.
My pixel3a phone likes to charge at 9V for example. I have a notebook PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will only work with special
cables that have identity chips which specify the current and voltage rating of the cable and
connectors.
On 13/11/2022 10:57 am, The Natural Philosopher wrote:
On 12/11/2022 16:33, JNugent wrote:
On 12/11/2022 04:21 pm, Commander Kinsey wrote:
Nothing to do with it. For some reason Samsung have decided the
input to the phone shall not exceed 1.1A.
Really?
How did they manage to get Ohm\'s Law repealed?
Intelligent semiconductor circuits simply dont obey it.
Do they reduce the supplied voltage, such that V, I and R stay in balance?
Charging cables have no connection on the data lines, they advertise them as
being secure - you can charge your phone on an aeroplane or in a cafe without
risking someone hacking into your phone. So resistors on data lines within
the power supply cannot possibly do anything if you\'re using a charging
cable.
So.... how does a device and power supply work out what rate to charge? In
the absence of data lines, does the device just go for it flat out until the
voltage drop on the power supply causes it to use less?
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwalliker@gmail.com> wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey
wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky
gnuarm.del...@gmail.com> wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul
nos...@needed.invalid> wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to
charge! No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense
to have anything in the cable unless the currents are so high,
they would overheat a typical cable.
Charging cables have no connection on the data lines, they
advertise them as being secure - you can charge your phone on an
aeroplane or in a cafe without risking someone hacking into your
phone. So resistors on data lines within the power supply cannot
possibly do anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for
it flat out until the voltage drop on the power supply causes it
to use less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when they
did that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at
5V but some can also deliver 9V, 12V, 15V and 20V and in some cases
lots of smaller steps in between. My pixel3a phone likes to charge
at 9V for example. I have a notebook PC that prefers to charge at
20V. if it can. Very high power USB chargers can deliver up to 48V
at up to 5A giving a maximum output power of 240W.
The more exotic combinations (more than 20V or more than 3A) will
only work with special cables that have identity chips which
specify the current and voltage rating of the cable and connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
On Sat, 12 Nov 2022 12:03:58 -0000
\"Commander Kinsey\" <CK1@nospam.com> wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwalliker@gmail.com> wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey
wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky
gnuarm.del...@gmail.com> wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul
nos...@needed.invalid> wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to
charge! No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense
to have anything in the cable unless the currents are so high,
they would overheat a typical cable.
Charging cables have no connection on the data lines, they
advertise them as being secure - you can charge your phone on an
aeroplane or in a cafe without risking someone hacking into your
phone. So resistors on data lines within the power supply cannot
possibly do anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for
it flat out until the voltage drop on the power supply causes it
to use less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when they
did that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at
5V but some can also deliver 9V, 12V, 15V and 20V and in some cases
lots of smaller steps in between. My pixel3a phone likes to charge
at 9V for example. I have a notebook PC that prefers to charge at
20V. if it can. Very high power USB chargers can deliver up to 48V
at up to 5A giving a maximum output power of 240W.
The more exotic combinations (more than 20V or more than 3A) will
only work with special cables that have identity chips which
specify the current and voltage rating of the cable and connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Surely nowadays the charger is in the device being charged, and is fed
the 5V (or whatever) directly?
Lithium batteries are quite fussy about
charging, particularly fast charging.
Charge rate is specific to the
battery, and the maximum current should typically be about 40-50% of the
capacity in Ah.
Once the battery voltage has reached 4.2V/cell, current
is reduced to maintain 4.2V until it\'s below a certain level, again
depending on capacity. The battery temperature must also be monitored,
as the voltage is dependent on it, and also to shut down if the
temperature gets too high with a faulty battery. It makes sense to have
all this stuff physically close to the battery.
On 12/11/2022 04:52 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:33:32 -0000, JNugent <jenningsandco@mail.com> wrote:
On 12/11/2022 04:21 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:00:20 -0000, JNugent <jenningsandco@mail.com
wrote:
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey
wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com
wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to
have anything in the cable unless the currents are so high, they
would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise
them as being secure - you can charge your phone on an aeroplane or
in a cafe without risking someone hacking into your phone. So
resistors on data lines within the power supply cannot possibly do
anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for it
flat out until the voltage drop on the power supply causes it to use
less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when
they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V
but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps
in between.
My pixel3a phone likes to charge at 9V for example. I have a
notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving
a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will
only
work with special
cables that have identity chips which specify the current and voltage
rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
Nothing to do with it. For some reason Samsung have decided the input
to the phone shall not exceed 1.1A.
Really?
How did they manage to get Ohm\'s Law repealed?
Why do you believe ohms law prevents it drawing 2 amps? 1 amp for the
battery to charge and 1 amp for the screen and CPU?
Do you understand Ohm\'s law?
What do you understand it to say?
If the CPU and screen are using
750mA, the battery charges very slowly.
Internal resistance / impedance (depending on whether it is an AC or DC
circuit).
You know perfectly well it\'s DC. Why would they limit the socket to
only be able to power the phone or the battery?
On Sat, 12 Nov 2022 16:59:45 +0000
JNugent <jenningsandco@mail.com> wrote:
On 12/11/2022 04:52 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:33:32 -0000, JNugent
jenningsandco@mail.com> wrote:
On 12/11/2022 04:21 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 16:00:20 -0000, JNugent
jenningsandco@mail.com> wrote:
On 12/11/2022 12:03 pm, Commander Kinsey wrote:
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker
jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky
gnuarm.del...@gmail.com> wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4,
Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul
nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to
charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no
sense to
have anything in the cable unless the currents are so high,
they would overheat a typical cable.
Charging cables have no connection on the data lines, they
advertise them as being secure - you can charge your phone on
an aeroplane or in a cafe without risking someone hacking
into your phone. So resistors on data lines within the power
supply cannot possibly do anything if you\'re using a charging
cable.
So.... how does a device and power supply work out what rate
to charge? In the absence of data lines, does the device just
go for it flat out until the voltage drop on the power supply
causes it to use less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew
about 570mA. Some motherboards were shutting the USB socket
off when they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start
at 5V but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller
steps in between.
My pixel3a phone likes to charge at 9V for example. I have a
notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A
giving a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A)
will only
work with special
cables that have identity chips which specify the current and
voltage rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a
while to charge if the CPU is running flat out all 8 cores.
Ohm\'s law?
Nothing to do with it. For some reason Samsung have decided the
input to the phone shall not exceed 1.1A.
Really?
How did they manage to get Ohm\'s Law repealed?
Why do you believe ohms law prevents it drawing 2 amps? 1 amp for
the battery to charge and 1 amp for the screen and CPU?
Do you understand Ohm\'s law?
What do you understand it to say?
If the CPU and screen are using
750mA, the battery charges very slowly.
Internal resistance / impedance (depending on whether it is an AC
or DC circuit).
You know perfectly well it\'s DC. Why would they limit the socket
to only be able to power the phone or the battery?
The answer is likely to be ****that**** the phone electronics is only powered
by the battery. There\'s no provision for it to be powered from the
external power supply while the battery charges from the same source.
Not Ohm\'s law as such, just a constant-current feed to the battery,
from which any current used by the phone is subtracted.
On Sat, 12 Nov 2022 11:15:00 -0000, John Walliker <jrwalliker@gmail.com
wrote:
On Saturday, 12 November 2022 at 08:57:35 UTC, Commander Kinsey wrote:
On Sat, 12 Nov 2022 07:39:17 -0000, Ricky <gnuarm.del...@gmail.com
wrote:
On Saturday, November 12, 2022 at 2:37:14 AM UTC-4, Commander
Kinsey wrote:
On Sat, 12 Nov 2022 04:03:04 -0000, Paul <nos...@needed.invalid
wrote:
Other cabling schemes may use more \"active\"
means of signaling. \"Passive\" cabling (where
there is no D+ D- continuity, but there is resistor
straps on D+ D- on the cable output end) are generally
limited to lower currents.
WTF? These are charging cables, specifically designed to charge!
No data lines, fast charging expected!
Try using your ohm meter.
Wouldn\'t the resistors be in the power unit? It makes no sense to
have anything in the cable unless the currents are so high, they
would overheat a typical cable.
Charging cables have no connection on the data lines, they advertise
them as being secure - you can charge your phone on an aeroplane or
in a cafe without risking someone hacking into your phone. So
resistors on data lines within the power supply cannot possibly do
anything if you\'re using a charging cable.
So.... how does a device and power supply work out what rate to
charge? In the absence of data lines, does the device just go for it
flat out until the voltage drop on the power supply causes it to use
less?
Yes, that is exactly what happens with older chargers.
There were some modems back in the days of USB 2, which drew about
570mA. Some motherboards were shutting the USB socket off when they did
that.
Things get more complex with PD
chargers as the voltage can be negotiated. All chargers start at 5V
but some can also
deliver 9V, 12V, 15V and 20V and in some cases lots of smaller steps
in between.
My pixel3a phone likes to charge at 9V for example. I have a notebook
PC that prefers to
charge at 20V. if it can.
Very high power USB chargers can deliver up to 48V at up to 5A giving
a maximum output
power of 240W.
The more exotic combinations (more than 20V or more than 3A) will only
work with special
cables that have identity chips which specify the current and voltage
rating of the cable and
connectors.
Grrrr. My phone takes no more than 5V 1.1A. Takes quite a while to
charge if the CPU is running flat out all 8 cores.
Surely nowadays the charger is in the device being charged, and is fed
the 5V (or whatever) directly?