J
John Larkin
Guest
On Mon, 17 Jan 2022 23:59:27 +0100, Klaus Vestergaard Kragelund
<klauskvik@hotmail.com> wrote:
It\'s fun to design circuits, until some clown sells an IC that does it
all for you cheap. Looks like we\'ll use INA280, which is available and
costs 80 cents, according to TI.
Digikey wants $3. Digikey has become a scalper.
--
If a man will begin with certainties, he shall end with doubts,
but if he will be content to begin with doubts he shall end in certainties.
Francis Bacon
<klauskvik@hotmail.com> wrote:
On 12/01/2022 03.44, jlarkin@highlandsniptechnology.com wrote:
On Tue, 11 Jan 2022 14:44:57 -0800 (PST), Lasse Langwadt Christensen
langwadt@fonz.dk> wrote:
tirsdag den 11. januar 2022 kl. 23.31.35 UTC+1 skrev John Larkin:
On Tue, 11 Jan 2022 12:12:37 -0800 (PST), Lasse Langwadt Christensen
lang...@fonz.dk> wrote:
tirsdag den 11. januar 2022 kl. 18.09.07 UTC+1 skrev jla...@highlandsniptechnology.com:
On Mon, 10 Jan 2022 22:34:08 -0800 (PST), whit3rd <whi...@gmail.com
wrote:
On Monday, January 10, 2022 at 7:26:19 PM UTC-8, jla...@highlandsniptechnology.com wrote:
We\'ll have a 48 volt, 20 amp power supply that feeds eight plug-in
modular load boards. We want to measure all 9 currents ...
So, is this regulated voltages, nine of \'em, and you want the output currents
from nine low-V regulators, or is it input to the regulators, and is that input somewhere
in the vicinity of 48VDC? Are these nine currents going to include initial
charging of filter capacitors? How big are those capacitors? Are some of the
regulators switchers?
As for \'intelligent cutoffs\', do you want to do that at the high-side? A secondary
low-current power supply grounded at the high rail might be economic, if
you want to have nine sensors and nine cutoffs all near the +48V source.
There will be eight user-programmable power supplies, each running off
+48, all off a common +48 bus fed from a kilowatt bulk power supply.
Users can potentially install modules and program and load the
supplies such as to cave in the main source, which would be really
ugly. That\'s against the rules in the manual, but we need to protect
things if they do it.
there is quite a few high side load switches with short circuit protection
and a combined current monitor / error output , but I think most of them
are limited to a ~24V supply
The c code can shut down supply modules as needed. Each power supply
module has its own FPGA that the main controller can address. There\'s
no need to actually remove 48v power from the baby boards. The master
controller just needs to know the currents and have some reasonable
rules.
check.
depending on how good the ADC is, maybe just a resistivity divider on the 48V and after each shunt is good enough?
Looks like we can use the XADC in the Zynq, the main controller FPGA.
That\'s a 1-volt full-scale, pretty terrible ADC. The voltage drop
across a shunt might be 50 mV with a common-mode of 48 volts. So we
need some sort of high-side amp.
Maybe use the idea with the resistive divider, but then don\'t use the
ADC, use a slope converter for increased precision.
That can be done with one cheap comparator, and a loop from the FPGA/Micro
Add a resistor with known drop, to calibrate
It\'s fun to design circuits, until some clown sells an IC that does it
all for you cheap. Looks like we\'ll use INA280, which is available and
costs 80 cents, according to TI.
Digikey wants $3. Digikey has become a scalper.
--
If a man will begin with certainties, he shall end with doubts,
but if he will be content to begin with doubts he shall end in certainties.
Francis Bacon