K
Kevin Aylward
Guest
Dbowey wrote:
reactance at the be and ce terminals, with inductive reactance at the bc
terminals. This is *not* debatable. Its how it works. End of story. Go
and do the math as I outlined.
its how the impedances act at the oscilation frequency.
I have subsequently done a little search, and this paper here certainly
supports my view, not that I require such support.
http://www.oscilent.com/esupport/TechSupport/ReviewPapers/IntroQuartz/vigtypes.htm
Note what terminals are the base, emitter and collector, and where the
capacitors and xtal are located.
Kevin Aylward
salesEXTRACT@anasoft.co.uk
http://www.anasoft.co.uk
SuperSpice, a very affordable Mixed-Mode
Windows Simulator with Schematic Capture,
Waveform Display, FFT's and Filter Design.
"That which is mostly observed, is that which replicates the most"
http://www.anasoft.co.uk/replicators/index.html
"quotes with no meaning, are meaningless" - Kevin Aylward.
I disagree. It is. The circuit clearly functions by action of capacitorFred posted:
Are you saying it is a tuned circuit because C4 is a variable
capacitor? I think it would be simpler to say it is a tunable
colppits because one of the C's is variable, otherwise people
(me) might think "tuned circuit" as in "pure LC circuit". This
circuit is so bad in the way it is drawn, the LC circuit gives
the impression it's a pure tuned circuit. The circuit is
difficult enoght without this added confusion. The person who
drew this circuit probably didn't quite understand it.
I think the circuit is drawn quite well, and that you need to study a
bit more before you critique other's work.
The L and C form a "tank circuit" which is tunable by varying the
value of C4. I could also tune it by varying the inductance by
compressing or stretching the coil. I can also tune it by varying
the applied voltage to the circuit. Whether it is "pure" or all
screwed up, is all in your mind.
Whether the type of circuit is a Colpits or something else, is not
particularly relevant to how the circuit tunes.
However, regardless of all the previous posts, this is not a Colpits.
reactance at the be and ce terminals, with inductive reactance at the bc
terminals. This is *not* debatable. Its how it works. End of story. Go
and do the math as I outlined.
This is probably a bit of symantics. The name itself is not important,It looks like a form of Pierce oscillator.
its how the impedances act at the oscilation frequency.
I have subsequently done a little search, and this paper here certainly
supports my view, not that I require such support.
http://www.oscilent.com/esupport/TechSupport/ReviewPapers/IntroQuartz/vigtypes.htm
Note what terminals are the base, emitter and collector, and where the
capacitors and xtal are located.
Kevin Aylward
salesEXTRACT@anasoft.co.uk
http://www.anasoft.co.uk
SuperSpice, a very affordable Mixed-Mode
Windows Simulator with Schematic Capture,
Waveform Display, FFT's and Filter Design.
"That which is mostly observed, is that which replicates the most"
http://www.anasoft.co.uk/replicators/index.html
"quotes with no meaning, are meaningless" - Kevin Aylward.