J
James Arthur
Guest
Tim Williams wrote:
check them.
Here's Terry Given's take on a similar app, complete with
worked out examples and wisdom of the ages:
http://groups.google.com/group/sci.electronics.design/browse_thread/thread/74808f35486301d9/6ae3c6dec198792a?hl=en
HTH,
James Arthur
No it's not safe to conclude your calcs are right--I didn'tOn May 11, 1:10 am, James Arthur <bogusabd...@verizon.net> wrote:
They offer a range of E-cores, toroids, in a variety of materials.
I assumed you'd want a mess of ferrite E-cores in mat'l #77--you'll
have to stack 'em to get to 10kVA.
https://www.amidoncorp.com/items/65
#77 is starting to look like the material of choice. Or something
similar, like 75 or 78.
The largest E-core Amidon offers is rated for "about 200W", which
suggests I'd need roughly 50 of them for the 10kW level I'm interested
in.
On an indirectly linked page, I discovered the data:
https://www.amidoncorp.com/specs/2-40.pdf
This says the largest core has a winding window of 2 * 0.593 x 0.375
inch (using an E-E arrangement). A stack of 50 would be 50 * 0.605 =
30" thick, which is certainly possible, but would stick out one side
of my chassis. On the plus side, I would certainly be able to push
all the voltage through one turn. A single piece of 3/8" tubing would
fit without too much trouble, though leakage inductance to the primary
wouldn't be great (though it doesn't need to be). Evidently, A_L
would be 5.3 * 50 = 265uH/T^2, which would be fairly "ideal". But it
seems like an awful lot of overkill, not to mention way too expensive
($312 for 50 E-cores? no thanks).
Where does cross sectional area fit into this, anyway? Isn't that
absorbed into A_L? So, as long as I am given A_L, I can calculate
inductance and saturation at will? And saturation only involves path
length, right? -- by amperes per meter, they mean *A/m*, not A.m/m^2
(like how resistivity is actually ohm.m^2/m)?
Ok, so, this is Usenet, right? If I've made an error, surely there
would have been fifty people in the first hour telling me what an
idiot I am -- since this has not happened, I can only assume my
calculations are correct??? Then why do I calculate that a moderately
sized toroid (like the FT-290-W) will suffice, whereas others have
suggested that I need something approximately as thick as my ankle?
Tim
check them.
Here's Terry Given's take on a similar app, complete with
worked out examples and wisdom of the ages:
http://groups.google.com/group/sci.electronics.design/browse_thread/thread/74808f35486301d9/6ae3c6dec198792a?hl=en
HTH,
James Arthur