J
John Fields
Guest
On Mon, 15 Nov 2004 21:23:29 GMT, donaldun@spamfreepearce.uk.com (Don
Pearce) wrote:
By that criterion, then, it's the end of the cable that's driving the
load! Picky, picky, picky, but I get your point!
Thanks,
--
John Fields
Pearce) wrote:
---For the other bit, as you say the cables are short so they don't enter
into the situation. The 50 ohm source is transformed by the |MATCH|
bit in the middle - whatever that is - to the conjugate of the load
impedance. It is that conjugate impedance that drives the load, not
the 50 ohms.
By that criterion, then, it's the end of the cable that's driving the
load! Picky, picky, picky, but I get your point!
Thanks,
--
John Fields