J
John Woodgate
Guest
I read in alt.binaries.schematics.electronic that Chuck Harris
<cfharris@erols.com> wrote (in <3ff34855$0$4761$61fed72c@news.rcn.com>
about 'Do Wiggle Stick Meters Wear Out?', on Wed, 31 Dec 2003:
make oscillation less likely, as I show below. But you haven't actually
mentioned the key word. The crucial factor is the *resistance* of the
coil, as I tried to indicate before. If R =>sqrt(L/C) the current won't
oscillate. It didn't.
--
Regards, John Woodgate, OOO - Own Opinions Only. http://www.jmwa.demon.co.uk
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<cfharris@erols.com> wrote (in <3ff34855$0$4761$61fed72c@news.rcn.com>
about 'Do Wiggle Stick Meters Wear Out?', on Wed, 31 Dec 2003:
Not really; you are on the right lines insofar as a low value of L/CI would guess that the difference has something to do with how big
your capacitor is, vs how big the coil is. Perhaps if the coil is
really small in inductance, and the capacitor is very large in
capacitance you get enough loss that the coil cannot pass the energy
back to the capacitor before it is mostly all gone?
make oscillation less likely, as I show below. But you haven't actually
mentioned the key word. The crucial factor is the *resistance* of the
coil, as I tried to indicate before. If R =>sqrt(L/C) the current won't
oscillate. It didn't.
--
Regards, John Woodgate, OOO - Own Opinions Only. http://www.jmwa.demon.co.uk
Interested in professional sound reinforcement and distribution? Then go to
http://www.isce.org.uk
PLEASE do NOT copy news posts to me by E-MAIL!