C
colin
Guest
<amremote@hotmail.com> wrote in message
news:1120304443.225111.39550@g14g2000cwa.googlegroups.com...
+12v +---+-------+
| | |
| R=2k @=meter
opt=R | |
| | |C
| +-----| T2=any med power (to220) npn just simply bolted to
something metal
| T1| |E
22k| |E |
o--R-+--| R=6.8 ohm
| |C |
10k=R | | t1= any smal signal (high gain) pnp
| | |
-----+---+-------+
The 0-5v sensor voltage is divided by the 22k/10k to ~ 0-1.6v
This voltage then apears accros the 6.8 ohm resistor where it sets the
curent through T1 and hence the meter to ~ 0-230ma
T1 counteracts the vbe drop acros T2 and provides curent gain.
This should be moderatly acurate. bear in mind this is untested and at full
scale T2 is just about saturating, wich may mean 'full' scale is not quite
acheived depending on type of transistor.
ov input might not be quite zero current, this may corespond better to the
the guage anyway, the optional R is if you want to increase the curent on
empty. (try with 1meg)
you can always tweak it ie lower the 10k or the 6.8 ohm etc.
Colin =^.^=
news:1120304443.225111.39550@g14g2000cwa.googlegroups.com...
Simple circuit idea ..I should know how to do this, but please treat as a Newbie query
I have a simple circuit question for any analogue experts out there !
I'd be delighted if someone can suggest what I suspect is a simple
solution. I have no problem with digital circuitry, or making the
solution. My problem is a lack of understanding of analogue bits n
pieces and lack of time to learn due to work pressures
THE PROBLEM
- I have to link a very modern fuel-tank level probe to an old
fashioned car fuel gauge, via a simple circuit and it all runs of the
cars 12v supply.
THE DETAILS
- The supply rail will be typically 12-14vs
- The fuel probe is an expensive dedicated hyper modern capacitive
device with a pic chip type device in it. Once calibrated it generates
a high impedance output voltage of 0-5v linearly. Linearity isn't
important to me. It cant source more than a milliamp.
- The old fuel gauge is a fixed resistance 45ohm device with internal
mechanical damping. It isn't very linear but this isn't important.
The gauge reads empty to full with a voltage change across it of 0 -
10volts, and current consumption of 0-230ma or so.
- The 0 -> 5v input signal is pretty much a steady DC value so I cant
have a capacitor on the input as in a conventional simple amplifier
circuit.
THE QUESTION
- What simple FET based (or transistor!) circuit would link these two
devices ? Ideally I'd like someone to advise on a schematic, with
approx component values, that I can go off and build and tweak.
Help !! If you want to email me offlist use amremote at hotmail dot
com
Thanks in advance.
Andy / UK.
+12v +---+-------+
| | |
| R=2k @=meter
opt=R | |
| | |C
| +-----| T2=any med power (to220) npn just simply bolted to
something metal
| T1| |E
22k| |E |
o--R-+--| R=6.8 ohm
| |C |
10k=R | | t1= any smal signal (high gain) pnp
| | |
-----+---+-------+
The 0-5v sensor voltage is divided by the 22k/10k to ~ 0-1.6v
This voltage then apears accros the 6.8 ohm resistor where it sets the
curent through T1 and hence the meter to ~ 0-230ma
T1 counteracts the vbe drop acros T2 and provides curent gain.
This should be moderatly acurate. bear in mind this is untested and at full
scale T2 is just about saturating, wich may mean 'full' scale is not quite
acheived depending on type of transistor.
ov input might not be quite zero current, this may corespond better to the
the guage anyway, the optional R is if you want to increase the curent on
empty. (try with 1meg)
you can always tweak it ie lower the 10k or the 6.8 ohm etc.
Colin =^.^=