Charging A Lead Acid Battery

On Wed, 13 Feb 2008 02:50:02 GMT, ehsjr <ehsjr@bellatlantic.net> wrote:

:Ross Herbert wrote:
:> On Tue, 12 Feb 2008 01:30:43 GMT, ehsjr <ehsjr@bellatlantic.net> wrote:
:>
:> :Dave.H wrote:
:> :> How would I go about building a charger for a lead acid battery.
:> :> Jaycar Electronics sells a 5 amp hour 6 volt SLA battery for use in
:> :> flashlight lanterns, but as far as I can tell they don't sell the
:> :> charger.
:> :>
:> :> Battery
:> :> http://www.jaycar.com.au/productResults.asp?FORM=KEYWORD
:> :> (CAT. NO. SB2498)
:> :>
:> :> Thanks
:> :
:> :
:> :Very simple charger:
:> :
:> : -----
:> : +9 ------Vin|LM317|Vout---+
:> : ----- |
:> : Adj [2.5R]
:> : | | 1N400x
:> : +----------+---->|---+
:> : | +
:> : [Batt]
:> : |
:> : Gnd --------------------------------+
:> :
:> :You need a 9 or 12 volt wall wart capable of
:> :at least 500 mA, an LM317 chip, a heat sink for
:> :the chip, and 2 5 ohm, 1 watt (at least) resistors
:> :in parallel to make the 2.5 ohm resistance, and
:> :a 1N400x diode. Charge for 12-14 hours.
:> :
:> :Ed
:>
:>
:> While that might work, it is a constant current source more appropriate to
:> charging Ni-Cd or Ni-Mh cells, not a lead acid battery.
:>
:> LA battery is best charged with a constant voltage source or better still, a
:> regulated 2 or 3 stage charger.
:>
:> Read Jaycar's own reference sheet on SLA batteries.
:> http://www.jaycar.com.au/images_uploaded/slabatts.pdf
:
:
:Read Jaycar's own description for the specific battery.
:It states: "Charge current 500mA for 10- 14 hrs"
:
:There is no "might" about it (as in your statement
:"While that might work"). CC charging *does* work on SLAs.
:Note that this is not comparing CC charging to other
:methods. It is correcting the "might" to "does".
:
:If you want to talk about "best" chargers, don't snipe
:at my post which addressed a "Very simple charger"
:It's simple, it works, and it matches Jaycar's description.
:
:Ed

I said "might work" for the following reasons.

Provided that the OP does in fact stick to a "wall wart" transformer limited to
not very much more than 500mA capability, it will probably work ok.
Unfortunately, I don't know if the OP will not use a 12V "wall wart" or indeed
any other higher VA rated transformer which is capable of 1A or more, and this
is where the problem can arise.

Remember, your circuit is an add-on and CC circuits attempt to do do just that,
ie. source a constant current irrespective of load conditions.

The problem with such a simple circuit is that it depends to a large extent on
the specification of the DC input source.

If using a higher VA rated transformer (than a 500mA wall wart) the actual
output voltage of the BR and the output current rating of the transformer will
definitely have a say in how well it will work and whether the battery will be
damaged if left connected too long.

If we accept that the CC circuit you proposed is set at 500mA with such a
transformer, then it will pump this much current through the battery no matter
whether the battery is fully charged or not.

Consider the case where the transformer is capable of putting out 12V at say 2A
from the BR. The CC circuit will successfully limit the charging current to
500mA and the majority of the source voltage will be dropped across the BR and
CC circuits. When the battery is fully charged to say 6.8V or thereabouts, there
is still a surplus of 5.2V available from the BR which will continue to pump
500mA through the battery. It will destroy the battery if left connected.

You might remember those cheap and nasty Arlec chargers
http://cgi.ebay.com.au/ARLEC-BATTERY-CHARGER-6V-AND-12-VOLT-CAR-BATTERY-CHARGE_W0QQitemZ320217446445QQihZ011QQcategoryZ79253QQcmdZViewItem
They had nothing more than a transformer, a rectifier and a thermal current
limiting switch to control the charge rate. They depended upon the fact that
when the battery was fully charged the DC voltage from the rectifier and the
battery voltage were almost equal and thus very little additional current was
pumped into the battery. Unfortunately, depending on the local AC supply voltage
the transformer output voltage was usually several volts higher than the fully
charged battery voltage, so it continued to pump quite a hefty current into the
battery thus destroying it. Your CC circuit is an electronic equivalent of the
thermal current switch in those cheap chargers.
 
Ross Herbert wrote:
On Wed, 13 Feb 2008 02:50:02 GMT, ehsjr <ehsjr@bellatlantic.net> wrote:

:Ross Herbert wrote:
:> On Tue, 12 Feb 2008 01:30:43 GMT, ehsjr <ehsjr@bellatlantic.net> wrote:
:
:> :Dave.H wrote:
:> :> How would I go about building a charger for a lead acid battery.
:> :> Jaycar Electronics sells a 5 amp hour 6 volt SLA battery for use in
:> :> flashlight lanterns, but as far as I can tell they don't sell the
:> :> charger.
:> :
:> :> Battery
:> :> http://www.jaycar.com.au/productResults.asp?FORM=KEYWORD
:> :> (CAT. NO. SB2498)
:> :
:> :> Thanks
:> :
:> :
:> :Very simple charger:
:> :
:> : -----
:> : +9 ------Vin|LM317|Vout---+
:> : ----- |
:> : Adj [2.5R]
:> : | | 1N400x
:> : +----------+---->|---+
:> : | +
:> : [Batt]
:> : |
:> : Gnd --------------------------------+
:> :
:> :You need a 9 or 12 volt wall wart capable of
:> :at least 500 mA, an LM317 chip, a heat sink for
:> :the chip, and 2 5 ohm, 1 watt (at least) resistors
:> :in parallel to make the 2.5 ohm resistance, and
:> :a 1N400x diode. Charge for 12-14 hours.
:> :
:> :Ed
:
:
:> While that might work, it is a constant current source more appropriate to
:> charging Ni-Cd or Ni-Mh cells, not a lead acid battery.
:
:> LA battery is best charged with a constant voltage source or better still, a
:> regulated 2 or 3 stage charger.
:
:> Read Jaycar's own reference sheet on SLA batteries.
:> http://www.jaycar.com.au/images_uploaded/slabatts.pdf
:
:
:Read Jaycar's own description for the specific battery.
:It states: "Charge current 500mA for 10- 14 hrs"
:
:There is no "might" about it (as in your statement
:"While that might work"). CC charging *does* work on SLAs.
:Note that this is not comparing CC charging to other
:methods. It is correcting the "might" to "does".
:
:If you want to talk about "best" chargers, don't snipe
:at my post which addressed a "Very simple charger"
:It's simple, it works, and it matches Jaycar's description.
:
:Ed

I said "might work" for the following reasons.

Provided that the OP does in fact stick to a "wall wart" transformer limited to
not very much more than 500mA capability, it will probably work ok.
Unfortunately, I don't know if the OP will not use a 12V "wall wart" or indeed
any other higher VA rated transformer which is capable of 1A or more, and this
is where the problem can arise.

Remember, your circuit is an add-on and CC circuits attempt to do do just that,
ie. source a constant current irrespective of load conditions.

The problem with such a simple circuit is that it depends to a large extent on
the specification of the DC input source.

If using a higher VA rated transformer (than a 500mA wall wart) the actual
output voltage of the BR and the output current rating of the transformer will
definitely have a say in how well it will work and whether the battery will be
damaged if left connected too long.

If we accept that the CC circuit you proposed is set at 500mA with such a
transformer, then it will pump this much current through the battery no matter
whether the battery is fully charged or not.

Consider the case where the transformer is capable of putting out 12V at say 2A
from the BR. The CC circuit will successfully limit the charging current to
500mA and the majority of the source voltage will be dropped across the BR and
CC circuits. When the battery is fully charged to say 6.8V or thereabouts, there
is still a surplus of 5.2V available from the BR which will continue to pump
500mA through the battery. It will destroy the battery if left connected.

You might remember those cheap and nasty Arlec chargers
http://cgi.ebay.com.au/ARLEC-BATTERY-CHARGER-6V-AND-12-VOLT-CAR-BATTERY-CHARGE_W0QQitemZ320217446445QQihZ011QQcategoryZ79253QQcmdZViewItem
They had nothing more than a transformer, a rectifier and a thermal current
limiting switch to control the charge rate. They depended upon the fact that
when the battery was fully charged the DC voltage from the rectifier and the
battery voltage were almost equal and thus very little additional current was
pumped into the battery. Unfortunately, depending on the local AC supply voltage
the transformer output voltage was usually several volts higher than the fully
charged battery voltage, so it continued to pump quite a hefty current into the
battery thus destroying it. Your CC circuit is an electronic equivalent of the
thermal current switch in those cheap chargers.
Right! The "very simple charger" does not include
circuitry for protection against overcharge.

Ed
 
In article <4b78e703-68e3-4822-b318-a1cd9fb8ff04
@e6g2000prf.googlegroups.com>, redbelly98@yahoo.com says...
On Feb 13, 9:09 am, James Beck <j...@reallykillersystems.com> wrote:
In article <6194982a-5fc6-406e-b08d-dd15013ba985
@y5g2000hsf.googlegroups.com>, redbell...@yahoo.com says...

Why is your simple charger so complicated? Why not use a 12 volt DC
wall transformer and 13 ohm resistor (5 watt)? You get 540mA when the
battery is low at 5 volts, and about 400mA as the battery voltage
rises to 7 volts.

-Bill

If you forget to turn off a charger like that, it will seriously
overcharge a 6V battery! On the other hand Ed's charger will not do
that

It won't?
It should continue to charge the battery up to the wall wart voltage,
which is still too high if you leave it plugged in too long.
I would, and do, just use a CV source that is set to the float voltage
of the battery. Pick a regulator that has over temp and current
limiting and let it float.

Jim

What about all the voltage drops between the wall wart and battery:

1 to 1.5V drop-out voltage of regulator
1.2-1.3V between regulator "out" and "adj" pins (across 2.5R resistor)
0.6-0.7V diode drop across 1N400x

Mark
Build it and try.
As the current drops I'll bet you don't get the drops you think,
especially across the resistor used for the current sense. You are also
assuming that the 9V wall wart is regulated. A cheap unregulated wall
wart that is a "nominal" 9V under X% of load will usually be quite a bit
higher than you expect as the load drops. A CV float charger could be
used with any wall wart that is the V drop of the regulator or higher.
 
"ehsjr"

Right! The "very simple charger" does not include
circuitry for protection against overcharge.

Ed
** What a posturing, fucking arrogant turd you are - Ed.


A very simple charger circuit WILL do just that.

Its called a voltage regulator with current limit.



......... Phil
 
On Feb 13, 9:48 pm, ehsjr <eh...@bellatlantic.net> wrote:
Bill Bowden wrote:
On Feb 12, 6:50 pm, ehsjr <eh...@bellatlantic.net> wrote:

Ross Herbert wrote:

On Tue, 12 Feb 2008 01:30:43 GMT, ehsjr <eh...@bellatlantic.net> wrote:

:Dave.H wrote:
:> How would I go about building a charger for a lead acid battery.
:> Jaycar Electronics sells a 5 amp hour 6 volt SLA battery for use in
:> flashlight lanterns, but as far as I can tell they don't sell the
:> charger.
:
:> Battery
:>http://www.jaycar.com.au/productResults.asp?FORM=KEYWORD
:> (CAT. NO. SB2498)
:
:> Thanks
:
:
:Very simple charger:
:
:               -----
:  +9 ------Vin|LM317|Vout---+
:               -----        |
:                Adj      [2.5R]
:                 |          |   1N400x
:                 +----------+---->|---+
:                                      | +
:                                    [Batt]
:                                      |
:  Gnd --------------------------------+
:
:You need a 9 or 12 volt wall wart capable of
:at least 500 mA, an LM317 chip, a heat sink for
:the chip, and 2 5 ohm, 1 watt (at least) resistors
:in parallel to make the 2.5 ohm resistance, and
:a 1N400x diode.  Charge for 12-14 hours.
:
:Ed

While that might work, it is a constant current source more appropriate to
charging Ni-Cd or Ni-Mh cells, not a lead acid battery.

LA battery is best charged with a constant voltage source or better still, a
regulated 2 or 3 stage charger.

Read Jaycar's own reference sheet on SLA batteries.
http://www.jaycar.com.au/images_uploaded/slabatts.pdf

Read Jaycar's own description for the specific battery.
It states:  "Charge current 500mA for 10- 14 hrs"

There is no "might" about it (as in your statement
"While that might work").  CC charging *does* work on SLAs.
Note that this is not comparing CC charging to other
methods. It is correcting the "might" to "does".

If you want to talk about "best" chargers, don't snipe
at my post which addressed a "Very simple charger"
It's simple, it works, and it matches Jaycar's description.

Ed- Hide quoted text -

- Show quoted text -

Why is your simple charger so complicated? Why not use a 12 volt DC
wall transformer and 13 ohm resistor (5 watt)? You get  540mA when the
battery is low at 5 volts, and about 400mA as the battery voltage
rises to 7 volts.

-Bill

The circuit you describe would require *regulated* 12 volts,
making it _more_ complicated than the "very simple" circuit.
The very simple circuit is designed to match the charging
requirements in Jaycar's description.  Can't do that with the
12 volt DC wall wart and 13 ohm resistor.

Ed- Hide quoted text -

- Show quoted text -
No, it doesn't require a regulated input.

If the transformer is rated at 500mA and 12 volts, the starting
current will be 500mA. As the battery voltage rises, the load
decreases, causing the transformer voltage to rise and the current to
remain fairly constant, or more constant than using a regulated input.
Therefore, an unregulated input is better than the alternative you
suggest.

-Bill
 
On Feb 14, 10:29 am, James Beck <j...@reallykillersystems.com> wrote:
In article <4b78e703-68e3-4822-b318-a1cd9fb8ff04
@e6g2000prf.googlegroups.com>, redbell...@yahoo.com says...



On Feb 13, 9:09 am, James Beck <j...@reallykillersystems.com> wrote:
In article <6194982a-5fc6-406e-b08d-dd15013ba985
@y5g2000hsf.googlegroups.com>, redbell...@yahoo.com says...

Why is your simple charger so complicated? Why not use a 12 volt DC
wall transformer and 13 ohm resistor (5 watt)? You get 540mA when the
battery is low at 5 volts, and about 400mA as the battery voltage
rises to 7 volts.

-Bill

If you forget to turn off a charger like that, it will seriously
overcharge a 6V battery! On the other hand Ed's charger will not do
that

It won't?
It should continue to charge the battery up to the wall wart voltage,
which is still too high if you leave it plugged in too long.
I would, and do, just use a CV source that is set to the float voltage
of the battery. Pick a regulator that has over temp and current
limiting and let it float.

Jim

What about all the voltage drops between the wall wart and battery:

1 to 1.5V drop-out voltage of regulator
1.2-1.3V between regulator "out" and "adj" pins (across 2.5R resistor)
0.6-0.7V diode drop across 1N400x

Mark

Build it and try.
As the current drops I'll bet you don't get the drops you think,
especially across the resistor used for the current sense. You are also
assuming that the 9V wall wart is regulated. A cheap unregulated wall
wart that is a "nominal" 9V under X% of load will usually be quite a bit
higher than you expect as the load drops. A CV float charger could be
used with any wall wart that is the V drop of the regulator or higher.
You make good points, I had been thinking simplistically about the
voltage drops at 500 mA.

Mark
 
Bill Bowden wrote:
On Feb 13, 9:48 pm, ehsjr <eh...@bellatlantic.net> wrote:

Bill Bowden wrote:

On Feb 12, 6:50 pm, ehsjr <eh...@bellatlantic.net> wrote:

Ross Herbert wrote:

On Tue, 12 Feb 2008 01:30:43 GMT, ehsjr <eh...@bellatlantic.net> wrote:

:Dave.H wrote:
:> How would I go about building a charger for a lead acid battery.
:> Jaycar Electronics sells a 5 amp hour 6 volt SLA battery for use in
:> flashlight lanterns, but as far as I can tell they don't sell the
:> charger.
:
:> Battery
:>http://www.jaycar.com.au/productResults.asp?FORM=KEYWORD
:> (CAT. NO. SB2498)
:
:> Thanks
:
:
:Very simple charger:
:
: -----
: +9 ------Vin|LM317|Vout---+
: ----- |
: Adj [2.5R]
: | | 1N400x
: +----------+---->|---+
: | +
: [Batt]
: |
: Gnd --------------------------------+
:
:You need a 9 or 12 volt wall wart capable of
:at least 500 mA, an LM317 chip, a heat sink for
:the chip, and 2 5 ohm, 1 watt (at least) resistors
:in parallel to make the 2.5 ohm resistance, and
:a 1N400x diode. Charge for 12-14 hours.
:
:Ed

While that might work, it is a constant current source more appropriate to
charging Ni-Cd or Ni-Mh cells, not a lead acid battery.

LA battery is best charged with a constant voltage source or better still, a
regulated 2 or 3 stage charger.

Read Jaycar's own reference sheet on SLA batteries.
http://www.jaycar.com.au/images_uploaded/slabatts.pdf

Read Jaycar's own description for the specific battery.
It states: "Charge current 500mA for 10- 14 hrs"

There is no "might" about it (as in your statement
"While that might work"). CC charging *does* work on SLAs.
Note that this is not comparing CC charging to other
methods. It is correcting the "might" to "does".

If you want to talk about "best" chargers, don't snipe
at my post which addressed a "Very simple charger"
It's simple, it works, and it matches Jaycar's description.

Ed- Hide quoted text -

- Show quoted text -

Why is your simple charger so complicated? Why not use a 12 volt DC
wall transformer and 13 ohm resistor (5 watt)? You get 540mA when the
battery is low at 5 volts, and about 400mA as the battery voltage
rises to 7 volts.

-Bill

The circuit you describe would require *regulated* 12 volts,
making it _more_ complicated than the "very simple" circuit.
The very simple circuit is designed to match the charging
requirements in Jaycar's description. Can't do that with the
12 volt DC wall wart and 13 ohm resistor.

Ed- Hide quoted text -

- Show quoted text -


No, it doesn't require a regulated input.
Yes, it does, to get the 540 mA you specified,
and the "about 400 mA" (depending on what you mean
by "about" 400 mA) you specified.


If the transformer is rated at 500mA and 12 volts, the starting
current will be 500mA.
But you did not specify any current rating.

As the battery voltage rises, the load
decreases, causing the transformer voltage to rise and the current to
remain fairly constant, or more constant than using a regulated input.
Therefore, an unregulated input is better than the alternative you
suggest.

You are trying to argue a point not being debated.
There are many chargers that are *better*. No debate
on that.

My objection to your post was that what you claimed was
not correct. You *cannot* specify that the current will
be some particular number without regulation. That
regulation adds complexity to your circuit.

By the way, I assume your question "Why is your simple
charger so complicated?" was facetious, and you were
just busting balls. 6 simple parts does not make a
complicated charger! Your 2 part charger is even
simpler - no debate - and it may be better.

Ed



 

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