Battery question

[Jamie]

Eeyore wrote:

Jamie wrote:


redbelly wrote:

Jamie wrote:


since you're requiring 2 amps, I guess math
wise, that would give you more than an hour of
running time.


Huh? You're implying the OP's battery has more than 2 AH of charge.
Where are you getting that from?

Mark

I wasn't implying anything.


You're an utter MORON ! You're just pulling numbers out of your ignorant stupid
ass as usual.

Graham

What an asshole you are!

Back to your old steam again! I see nothing never
chances on your end.

Why don't you go back and find my original message you dick head.

Did it ever occur to you that maybe, the whole message isn't there?
No, of course not. That wouldn't give you much to go on, would it? Jerk.

You see, It's obvious that RedBelly does the same thing you do, remove
what makes the rest of it relevant and use only what is needed to fuel
the ignorant personally which I may add, must of been something you
picked up at that Turkish bath house that you make regular visits to.

If I didn't know any better, I could swear you're reverting back to
your child hood. How about it grandpa? Do silly school antics really
turn you on these days? It would explain the incoherent personally
trait.

--
"I'm never wrong, once i thought i was, but was mistaken"
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5

 

[John Fields]

On Wed, 10 Oct 2007 16:20:38 -0400, default <default@defaulter.net>
wrote:

On Wed, 10 Oct 2007 08:51:03 -0700, "louis.brinson@gvltec.edu"
louis.brinson@gvltec.edu> wrote:

20 amp hour 11.1 volt 78 % efficiency on the conversion.

If you believe that . . . what's the purpose in posting in the first
place? Do the math.

---
The reason he posted was that he was confused about the math and was
asking for help.

For which he received a lot of flak, even though this is seb, where
there are supposed to be no stupid questions.
---

In the real world we have to deal with battery chemistry, temperature,
regulator efficiency (against a whole slew of parameters) and: oh
yes, the LOAD - where it drops out, how it drops out, etc. etc.

GVTEK.EDU?????????

---
No, gvltec.edu
---

Learn to think. Knowledge is good, but understanding is better,

---
Blah, blah, blah.

_You_ need to understand that this is seb, where there are no
stupid questions, and you need to learn to be less of an asshole.

All the guy was looking for was a little help and because you
couldn't figure it out you try to make _him_ look like the heavy?


--
JF

 

[Jamie]

redbelly wrote:

On Oct 9, 8:10 pm, Jamie
jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:

redbelly wrote:

On Oct 9, 6:38 pm, Jamie
jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:

louis.brin...@gvltec.edu wrote:

Hi I have a battery that is 11.1 volt and the device I'm powering will
require 5v 2 amps. I'm going to use a regulator to step the battery
down. How long of a runtime do you think I can get out of this setup? I
appreciate any input.

Due to other things not being equal in the equations like
inefficient regulators etc..., I'll just sling some barn
yard numbers.
Get the know the AH, (Amp hour) of the battery.
basically the constant amount of energy in one
hour..
since you're requiring 2 amps, I guess math
wise, that would give you more than an hour of
running time.

Huh? You're implying the OP's battery has more than 2 AH of charge.
Where are you getting that from?

Mark

I wasn't implying anything.



The battery is to run at 2 amps. You're statement that "math wise,
that would give you more than an hour of running time" implies a 2 Amp-
hour capacity. If you're not assuming this, how did you come up with
the 1 hour run time?

At any rate, it's a moot point now that the OP has told us it's a 20 A-
hr battery.

Regards,

Mark

I don't see where the issue here is. since no AHr was giving originally,

I stand by original statement, "BARN YARD" figures.

And it's basic math..

So basic, I'm not going to waste my time explaining it., How ever, I
did see J. Fields take the time out in breaking it down for those that
needed it..
Keep in mind, not all batteries (cells) types behave the same way
nor do you want to drain them down to such a low point.
So back to my "BARN YARD" figures.

Getting replacement batteries for emergency lighting teaches you one
thing. Not all manufacturers rate their products the same way. Or maybe
I should say. They lie a little on the performance where others we have
found actually are a little generous on their performance specs.





--
"I'm never wrong, once i thought i was, but was mistaken"
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5

 

[John Fields]

On Tue, 09 Oct 2007 20:10:01 -0400, Jamie
<jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:

redbelly wrote:

On Oct 9, 6:38 pm, Jamie
jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:

louis.brin...@gvltec.edu wrote:

Hi I have a battery that is 11.1 volt and the device I'm powering will
require 5v 2 amps. I'm going to use a regulator to step the battery
down. How long of a runtime do you think I can get out of this setup? I
appreciate any input.

Due to other things not being equal in the equations like
inefficient regulators etc..., I'll just sling some barn
yard numbers.
Get the know the AH, (Amp hour) of the battery.
basically the constant amount of energy in one
hour..
since you're requiring 2 amps, I guess math
wise, that would give you more than an hour of
running time.


Huh? You're implying the OP's battery has more than 2 AH of charge.
Where are you getting that from?

Mark

I wasn't implying anything.

---
Mark,

You made a mistake and you need to own up to it.

We all do, [make mistakes] once in a while, and while it's
humiliating when it happens in public, it's part of how we learn.

There's nothing wrong with admitting that we're not perfect, once we
find out that we aren't, but there's a lot wrong with pretending
that we are in the face of incontrovertible evidence to the
contrary.


--
JF

 

[John Fields]

On Wed, 10 Oct 2007 20:02:14 -0400, Jamie
<jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:

redbelly wrote:

On Oct 9, 8:10 pm, Jamie
jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:

redbelly wrote:

On Oct 9, 6:38 pm, Jamie
jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:

louis.brin...@gvltec.edu wrote:

Hi I have a battery that is 11.1 volt and the device I'm powering will
require 5v 2 amps. I'm going to use a regulator to step the battery
down. How long of a runtime do you think I can get out of this setup? I
appreciate any input.

Due to other things not being equal in the equations like
inefficient regulators etc..., I'll just sling some barn
yard numbers.
Get the know the AH, (Amp hour) of the battery.
basically the constant amount of energy in one
hour..
since you're requiring 2 amps, I guess math
wise, that would give you more than an hour of
running time.

Huh? You're implying the OP's battery has more than 2 AH of charge.
Where are you getting that from?

Mark

I wasn't implying anything.



The battery is to run at 2 amps. You're statement that "math wise,
that would give you more than an hour of running time" implies a 2 Amp-
hour capacity. If you're not assuming this, how did you come up with
the 1 hour run time?

At any rate, it's a moot point now that the OP has told us it's a 20 A-
hr battery.

Regards,

Mark

I don't see where the issue here is. since no AHr was giving originally,
I stand by original statement, "BARN YARD" figures.

---
So, since no Ampere Hour figures were given originally, your
barnyard figures were stupid errors?
---

And it's basic math..

---
Unfortunately, something with which you seem to have little
familiarity of.
---

So basic, I'm not going to waste my time explaining it.,

---
LOL, as if you could...
---

How ever, I
did see J. Fields take the time out in breaking it down for those that
needed it..

---
Include yourself in that set.
---

Keep in mind, not all batteries (cells) types behave the same way
nor do you want to drain them down to such a low point.
So back to my "BARN YARD" figures.

---
Idiot, "batteries" are made from cells.
---

Getting replacement batteries for emergency lighting teaches you one
thing. Not all manufacturers rate their products the same way. Or maybe
I should say. They lie a little on the performance where others we have
found actually are a little generous on their performance specs.

---
So?


--
JF

 

[redbelly]

On Oct 10, 8:12 pm, John Fields <jfie...@austininstruments.com> wrote:

On Tue, 09 Oct 2007 20:10:01 -0400, Jamie



jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:
redbelly wrote:

On Oct 9, 6:38 pm, Jamie
jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:

louis.brin...@gvltec.edu wrote:

Hi I have a battery that is 11.1 volt and the device I'm powering will
require 5v 2 amps. I'm going to use a regulator to step the battery
down. How long of a runtime do you think I can get out of this setup? I
appreciate any input.

Due to other things not being equal in the equations like
inefficient regulators etc..., I'll just sling some barn
yard numbers.
Get the know the AH, (Amp hour) of the battery.
basically the constant amount of energy in one
hour..
since you're requiring 2 amps, I guess math
wise, that would give you more than an hour of
running time.

Huh? You're implying the OP's battery has more than 2 AH of charge.
Where are you getting that from?

Mark

I wasn't implying anything.

---
Mark,

You made a mistake and you need to own up to it.

We all do, [make mistakes] once in a while, and while it's
humiliating when it happens in public, it's part of how we learn.

There's nothing wrong with admitting that we're not perfect, once we
find out that we aren't, but there's a lot wrong with pretending
that we are in the face of incontrovertible evidence to the
contrary.

--
JF

John,

Did you mean to address me (Mark, a.k.a. redbelly) or Jamie?

Mark

p.s. nice post -- the one that begins "Your load is dissipating: P2 =
I2 E2 = 2A * 5V = 10 watts, ... "

 

[Eeyore]

default wrote:

Eeyore wrote:

snip
Graham

Easy there. This guy has all the hallmarks of a Google Grooper and his
question is either posted with very limited knowledge of electronics,
or he's just a chameleon troll.

My comment was targeted at * JAMIE * who claims to be an engineer but seems happy to
make estimates of battery life knowing only its voltage !

Janie is a complete idiot. See his other posts for more examples of utter lunacy.

Graham

 

[Eeyore]

Jamie wrote:

Eeyore wrote:


Jamie wrote:


redbelly wrote:

Jamie wrote:


since you're requiring 2 amps, I guess math
wise, that would give you more than an hour of
running time.


Huh? You're implying the OP's battery has more than 2 AH of charge.
Where are you getting that from?

Mark

I wasn't implying anything.


You're an utter MORON ! You're just pulling numbers out of your ignorant stupid
ass as usual.

Graham

What an asshole you are!

Back to your old steam again! I see nothing never
chances on your end.

Why don't you go back and find my original message you dick head.

Did it ever occur to you that maybe, the whole message isn't there?
No, of course not. That wouldn't give you much to go on, would it? Jerk.

This is the only bit that matters,

" since you're requiring 2 amps, I guess math
wise, that would give you more than an hour of
running time."

MORON.

 

[John Fields]

On Wed, 10 Oct 2007 21:05:21 -0700, redbelly <redbelly98@yahoo.com>
wrote:

On Oct 10, 8:12 pm, John Fields <jfie...@austininstruments.com> wrote:
On Tue, 09 Oct 2007 20:10:01 -0400, Jamie



jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:
redbelly wrote:

On Oct 9, 6:38 pm, Jamie
jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:

louis.brin...@gvltec.edu wrote:

Hi I have a battery that is 11.1 volt and the device I'm powering will
require 5v 2 amps. I'm going to use a regulator to step the battery
down. How long of a runtime do you think I can get out of this setup? I
appreciate any input.

Due to other things not being equal in the equations like
inefficient regulators etc..., I'll just sling some barn
yard numbers.
Get the know the AH, (Amp hour) of the battery.
basically the constant amount of energy in one
hour..
since you're requiring 2 amps, I guess math
wise, that would give you more than an hour of
running time.

Huh? You're implying the OP's battery has more than 2 AH of charge.
Where are you getting that from?

Mark

I wasn't implying anything.

---
Mark,

You made a mistake and you need to own up to it.

We all do, [make mistakes] once in a while, and while it's
humiliating when it happens in public, it's part of how we learn.

There's nothing wrong with admitting that we're not perfect, once we
find out that we aren't, but there's a lot wrong with pretending
that we are in the face of incontrovertible evidence to the
contrary.

--
JF

John,

Did you mean to address me (Mark, a.k.a. redbelly) or Jamie?

---
Oops, my mistake... Jamie.
---

p.s. nice post -- the one that begins "Your load is dissipating: P2 =
I2 E2 = 2A * 5V = 10 watts, ... "

---
Thanks.


--
JF

 

[John Fields]

On Thu, 11 Oct 2007 07:30:55 +0100, Eeyore
<rabbitsfriendsandrelations@hotmail.com> wrote:

default wrote:

Eeyore wrote:

snip
Graham

Easy there. This guy has all the hallmarks of a Google Grooper and his
question is either posted with very limited knowledge of electronics,
or he's just a chameleon troll.

My comment was targeted at * JAMIE * who claims to be an engineer but seems happy to
make estimates of battery life knowing only its voltage !

---
Check the upper left hand corner of page 8 of:

http://www.panasonic.com/industrial/battery/oem/images/pdf/Panasonic_VRLA_Overview.pdf


--
JF

 

[Rich Grise]

On Wed, 10 Oct 2007 20:02:14 -0400, Jamie wrote:

And it's basic math..

So basic, I'm not going to waste my time explaining it.

IOW, you have no clue.

Quit being a rude asshole; this is sci.electronics.basics, where
the only dumb question is the one you don't ask.

Thanks,
Rich

 

[Eeyore]

Rich Grise wrote:

Jamie wrote:
And it's basic math..

So basic, I'm not going to waste my time explaining it.

IOW, you have no clue.

Quit being a rude asshole; this is sci.electronics.basics, where
the only dumb question is the one you don't ask.

Jamie's not even up to dealing with 'basic' questions.

Graham

 

[Jamie]

John Fields wrote:

On Wed, 10 Oct 2007 20:02:14 -0400, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


redbelly wrote:


On Oct 9, 8:10 pm, Jamie
jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:


redbelly wrote:


On Oct 9, 6:38 pm, Jamie
jamie_ka1lpa_not_valid_after_ka1l...@charter.net> wrote:

louis.brin...@gvltec.edu wrote:

Hi I have a battery that is 11.1 volt and the device I'm powering will
require 5v 2 amps. I'm going to use a regulator to step the battery
down. How long of a runtime do you think I can get out of this setup? I
appreciate any input.

Due to other things not being equal in the equations like
inefficient regulators etc..., I'll just sling some barn
yard numbers.
Get the know the AH, (Amp hour) of the battery.
basically the constant amount of energy in one
hour..
since you're requiring 2 amps, I guess math
wise, that would give you more than an hour of
running time.

Huh? You're implying the OP's battery has more than 2 AH of charge.
Where are you getting that from?

Mark

I wasn't implying anything.



The battery is to run at 2 amps. You're statement that "math wise,
that would give you more than an hour of running time" implies a 2 Amp-
hour capacity. If you're not assuming this, how did you come up with
the 1 hour run time?

At any rate, it's a moot point now that the OP has told us it's a 20 A-
hr battery.

Regards,

Mark


I don't see where the issue here is. since no AHr was giving originally,
I stand by original statement, "BARN YARD" figures.


---
So, since no Ampere Hour figures were given originally, your
barnyard figures were stupid errors?
---


And it's basic math..


---
Unfortunately, something with which you seem to have little
familiarity of.
---


So basic, I'm not going to waste my time explaining it.,


---
LOL, as if you could...
---


How ever, I
did see J. Fields take the time out in breaking it down for those that
needed it..


---
Include yourself in that set.
---


Keep in mind, not all batteries (cells) types behave the same way
nor do you want to drain them down to such a low point.
So back to my "BARN YARD" figures.


---
Idiot, "batteries" are made from cells.
---


Getting replacement batteries for emergency lighting teaches you one
thing. Not all manufacturers rate their products the same way. Or maybe
I should say. They lie a little on the performance where others we have
found actually are a little generous on their performance specs.


---
So?


I'm sorry John, I think you have me grossly mistaken .

I really thought you had more common decency than that.

I work in this field all day long, I don't plan on sitting here after
hours dumping math for public consumption. If that were the case, I'd
live at work.

I do find a few here that seem to pride them self in doing so. It
makes me wonder if it's for the good of the general audience or, some
one trying to make a mark for them self?

I don't know what you call it where you come from? Here, we call it
little man disease

Have a good day.

--
"I'm never wrong, once i thought i was, but was mistaken"
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5

 

[Jamie]

Eeyore wrote:

default wrote:


Eeyore wrote:

snip

Graham

Easy there. This guy has all the hallmarks of a Google Grooper and his
question is either posted with very limited knowledge of electronics,
or he's just a chameleon troll.


My comment was targeted at * JAMIE * who claims to be an engineer but seems happy to
make estimates of battery life knowing only its voltage !

Janie is a complete idiot. See his other posts for more examples of utter lunacy.

Graham

Hanging around the bath houses again?

I'm not one of your fantasy's


The spelling is "JAMIE" not "Janie"

Get a life.

--
"I'm never wrong, once i thought i was, but was mistaken"
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5

 

[Jamie]

Eeyore wrote:

Rich Grise wrote:


Jamie wrote:

And it's basic math..

So basic, I'm not going to waste my time explaining it.

IOW, you have no clue.

Quit being a rude asshole; this is sci.electronics.basics, where
the only dumb question is the one you don't ask.


Jamie's not even up to dealing with 'basic' questions.

Graham

That confirms my suspicion about you.

You are reverting back to your childhood. That was a classic
little school girl/boy (hard to tell with you) answer..

Thanks for clearing that up for me.

snort, snort, "he can't even answer the easy one's " snort snort.

Don't worry, mother is coming to save you.

have a good day now.

--
"I'm never wrong, once i thought i was, but was mistaken"
Real Programmers Do things like this.
http://webpages.charter.net/jamie_5

 

[ehsjr]

louis.brinson@gvltec.edu wrote:

Hi I have a battery that is 11.1 volt and the device I'm powering will
require 5v 2 amps. I'm going to use a regulator to step the battery
down. How long of a runtime do you think I can get out of this setup? I
appreciate any input.

I've read the thread, and unless I missed it, there
is something important than hasn't been addressed.

My reaction to your question is that you *should not*
attempt to get any runtime from your setup as described,
without further investigation.
Here's why:

That 11.1 volt figure indicates a (assumed lead acid)
battery that is already close to 100% discharged. If it
is a lead acid battery, you should be charging it - not
taking current from it - as continued discharging once
11.1 volts has been reached is likely to do damage to
the battery. The exact voltage figure vs % of discharge
depends on a number of factors, but in any case 11.1
volts demands a warning flag that you need to pay close
attention to whether or not you want to keep discharging
the battery.

If you're talking about some other chemistry (e.g. 10
NiCd cells discharged to 1.11 volts per cell), different
rules apply.

Ed

 

[David Bonnell]

That 11.1 volt figure indicates a (assumed lead acid)
battery that is already close to 100% discharged. If it
is a lead acid battery, you should be charging it

11.1 V is common for lithium-ion batteries (3 cells @ 3.7 V).

 

[ehsjr]

David Bonnell wrote:

That 11.1 volt figure indicates a (assumed lead acid)
battery that is already close to 100% discharged. If it
is a lead acid battery, you should be charging it


11.1 V is common for lithium-ion batteries (3 cells @ 3.7 V).

The op's battery is 20 amp hours.
11.1 may be common for LI batteries, but not at 20 AH.
A quick search finds lots of them < 10 AH, and none at 20.

Ed