basic opamp grounding question

P

panfilero

Guest
Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!
 
panfilero wrote:

Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!
Yes.
Click to expand...
The only acception to the rule is if you had some form of isolation
device. In the case of the isolation, you only used the ground/common of
the input of the isolator device, it's output common does not come in
contact with the input common how ever, the output common still needs to
be connected with the circuits ground/common.

http://webpages.charter.net/jamie_5"
 
On Mon, 16 Mar 2009 18:08:14 -0500, Jamie
<jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:

panfilero wrote:

Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!
Click to expand...
Not directly, anyway. If the amplifier is set up as a differential
amplifier with unity gain. The output signal will be referenced to
the power supply grounds. In this configuration, the inputs ('+'
input, actually - the '-' input is along for the ride) must remain
within the common mode operating range of the Op-Amp though.

___ ___
+------|___|---+----|___|-+
| R | R |
| | |
/-\ | |\| |
( )2V +----+-\ |
\+/ Vin ___ | >--+------- +2V
+-----+|___|---+----| / out
R | |/|
|
.-.
| |R
| |
'-'
|
GND

(created by AACircuit v1.28.6 beta 04/19/05 www.tech-chat.de)



Yes.
Click to expand...
Nope.

The only acception to the rule is if you had some form of isolation
device. In the case of the isolation, you only used the ground/common of
the input of the isolator device, it's output common does not come in
contact with the input common how ever, the output common still needs to
be connected with the circuits ground/common.

http://webpages.charter.net/jamie_5"
Click to expand...
As usual for Jamie, wrong. The resistors will be the "isolation"
devices (not to be confused with safety isolation).
 
On Mar 16, 1:59 pm, panfilero <panfil...@gmail.com> wrote:
Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal?
Click to expand...

Maybe. There has to be a return current path, of course, but
your ground connection, if long, can pick up hum.
A differential amplifier (amp + 4 resistors) configuration tolerates
grounding induced noise (like ground loops) well, and only
through a resistor does the power GND and signal GND
connect. Output signal is power-GND relative, and input
signal is signal-GND relative.

In noisy environments with long wires, simple signal/ground paired
wiring always gets in trouble, and transformers or differential
conversion is the usual solution.
 
krw wrote:

On Mon, 16 Mar 2009 18:08:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


panfilero wrote:


Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!


Not directly, anyway. If the amplifier is set up as a differential
amplifier with unity gain. The output signal will be referenced to
the power supply grounds. In this configuration, the inputs ('+'
input, actually - the '-' input is along for the ride) must remain
within the common mode operating range of the Op-Amp though.

___ ___
+------|___|---+----|___|-+
| R | R |
| | |
/-\ | |\| |
( )2V +----+-\ |
\+/ Vin ___ | >--+------- +2V
+-----+|___|---+----| / out
R | |/|
|
.-.
| |R
| |
'-'
|
GND

(created by AACircuit v1.28.6 beta 04/19/05 www.tech-chat.de)




Yes.


Nope.


The only acception to the rule is if you had some form of isolation
device. In the case of the isolation, you only used the ground/common of
the input of the isolator device, it's output common does not come in
contact with the input common how ever, the output common still needs to
be connected with the circuits ground/common.

http://webpages.charter.net/jamie_5"


As usual for Jamie, wrong. The resistors will be the "isolation"
devices (not to be confused with safety isolation).

That is insane,,, glad you're not in my work group.
Click to expand...

really, kind of cracks me up.


http://webpages.charter.net/jamie_5"
 
On Mon, 16 Mar 2009 19:39:14 -0500, Jamie
<jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:

krw wrote:

On Mon, 16 Mar 2009 18:08:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


panfilero wrote:


Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!


Not directly, anyway. If the amplifier is set up as a differential
amplifier with unity gain. The output signal will be referenced to
the power supply grounds. In this configuration, the inputs ('+'
input, actually - the '-' input is along for the ride) must remain
within the common mode operating range of the Op-Amp though.

___ ___
+------|___|---+----|___|-+
| R | R |
| | |
/-\ | |\| |
( )2V +----+-\ |
\+/ Vin ___ | >--+------- +2V
+-----+|___|---+----| / out
R | |/|
|
.-.
| |R
| |
'-'
|
GND

(created by AACircuit v1.28.6 beta 04/19/05 www.tech-chat.de)




Yes.


Nope.


The only acception to the rule is if you had some form of isolation
device. In the case of the isolation, you only used the ground/common of
the input of the isolator device, it's output common does not come in
contact with the input common how ever, the output common still needs to
be connected with the circuits ground/common.

http://webpages.charter.net/jamie_5"


As usual for Jamie, wrong. The resistors will be the "isolation"
devices (not to be confused with safety isolation).

That is insane,,, glad you're not in my work group.
Click to expand...
What would be insane is *being* in your "work" group.

really, kind of cracks me up.
Click to expand...
No, you've been there a long time.
 
On Mon, 16 Mar 2009 21:48:52 -0500, Jamie
<jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:

krw wrote:
On Mon, 16 Mar 2009 19:39:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


krw wrote:


On Mon, 16 Mar 2009 18:08:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:



panfilero wrote:



Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!


Not directly, anyway. If the amplifier is set up as a differential
amplifier with unity gain. The output signal will be referenced to
the power supply grounds. In this configuration, the inputs ('+'
input, actually - the '-' input is along for the ride) must remain
within the common mode operating range of the Op-Amp though.

___ ___
+------|___|---+----|___|-+
| R | R |
| | |
/-\ | |\| |
( )2V +----+-\ |
\+/ Vin ___ | >--+------- +2V
+-----+|___|---+----| / out
R | |/|
|
.-.
| |R
| |
'-'
|
GND

(created by AACircuit v1.28.6 beta 04/19/05 www.tech-chat.de)





Yes.


Nope.



The only acception to the rule is if you had some form of isolation
device. In the case of the isolation, you only used the ground/common of
the input of the isolator device, it's output common does not come in
contact with the input common how ever, the output common still needs to
be connected with the circuits ground/common.

http://webpages.charter.net/jamie_5"


As usual for Jamie, wrong. The resistors will be the "isolation"
devices (not to be confused with safety isolation).


That is insane,,, glad you're not in my work group.


What would be insane is *being* in your "work" group.


really, kind of cracks me up.


No, you've been there a long time.

OK, so you not only know everything,
Click to expand...
Enough...

but you also know me?
Click to expand...
to know that you're not only an idiot, but a jerk.

That my friend is a big error on your part.
Click to expand...
Hardly. You advertise quite successfully.

Btw, aren't you the one that is being called
"Always wrong" ?
Click to expand...
Wrong, again. You're just about as stupid as he, though. I'm the one
who gave him the (well deserved) "DimBulb" moniker, Junior.

Maybe I have you mixed up with another here but it seems to
fit at the moment.
Click to expand...
Who haven't you mixed it up with? You let everyone know how stupid
you are.

And also, the original poster never commented on using differential
input for balanced pairs. So, go have your fun else where, you're
barking up the wrong tree.
Click to expand...
He never indicated that he couldn't, either. Your *flat* assertion
that the grounds had to be the same is wrong. Perhaps you should take
DimBulb's "AlwaysWrong" name.

I'm barking up the wrong tree? I pin your ears to the wall, an *I* am
barking up the wrong tree? You are full of shit, but you've been told
that before.
 
krw wrote:
On Mon, 16 Mar 2009 19:39:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


krw wrote:


On Mon, 16 Mar 2009 18:08:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:



panfilero wrote:



Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!


Not directly, anyway. If the amplifier is set up as a differential
amplifier with unity gain. The output signal will be referenced to
the power supply grounds. In this configuration, the inputs ('+'
input, actually - the '-' input is along for the ride) must remain
within the common mode operating range of the Op-Amp though.

___ ___
+------|___|---+----|___|-+
| R | R |
| | |
/-\ | |\| |
( )2V +----+-\ |
\+/ Vin ___ | >--+------- +2V
+-----+|___|---+----| / out
R | |/|
|
.-.
| |R
| |
'-'
|
GND

(created by AACircuit v1.28.6 beta 04/19/05 www.tech-chat.de)





Yes.


Nope.



The only acception to the rule is if you had some form of isolation
device. In the case of the isolation, you only used the ground/common of
the input of the isolator device, it's output common does not come in
contact with the input common how ever, the output common still needs to
be connected with the circuits ground/common.

http://webpages.charter.net/jamie_5"


As usual for Jamie, wrong. The resistors will be the "isolation"
devices (not to be confused with safety isolation).


That is insane,,, glad you're not in my work group.


What would be insane is *being* in your "work" group.


really, kind of cracks me up.


No, you've been there a long time.

OK, so you not only know everything, but you also know me?
Click to expand...

That my friend is a big error on your part.

Btw, aren't you the one that is being called
"Always wrong" ?

Maybe I have you mixed up with another here but it seems to
fit at the moment.
And also, the original poster never commented on using differential
input for balanced pairs. So, go have your fun else where, you're
barking up the wrong tree.


http://webpages.charter.net/jamie_5"
 
panfilero wrote:

Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?
Click to expand...
You either need to do that or configure the op-amp as a differential
amplier ( in which case ensure the ground voltage of the source and the
signal remains within the common-mode voltage range of the diff
arrrangement ).

Graham
 
Jamie wrote:

That is insane,,, glad you're not in my work group.
Click to expand...
You're the one who's insane. You're almost as bad as AlwaysWrong.

Graham
 
krw wrote:
On Mon, 16 Mar 2009 21:48:52 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


krw wrote:

On Mon, 16 Mar 2009 19:39:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:



krw wrote:



On Mon, 16 Mar 2009 18:08:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:




panfilero wrote:




Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!


Not directly, anyway. If the amplifier is set up as a differential
amplifier with unity gain. The output signal will be referenced to
the power supply grounds. In this configuration, the inputs ('+'
input, actually - the '-' input is along for the ride) must remain
within the common mode operating range of the Op-Amp though.

___ ___
+------|___|---+----|___|-+
| R | R |
| | |
/-\ | |\| |
( )2V +----+-\ |
\+/ Vin ___ | >--+------- +2V
+-----+|___|---+----| / out
R | |/|
|
.-.
| |R
| |
'-'
|
GND

(created by AACircuit v1.28.6 beta 04/19/05 www.tech-chat.de)






Yes.


Nope.




The only acception to the rule is if you had some form of isolation
device. In the case of the isolation, you only used the ground/common of
the input of the isolator device, it's output common does not come in
contact with the input common how ever, the output common still needs to
be connected with the circuits ground/common.

http://webpages.charter.net/jamie_5"


As usual for Jamie, wrong. The resistors will be the "isolation"
devices (not to be confused with safety isolation).


That is insane,,, glad you're not in my work group.


What would be insane is *being* in your "work" group.



really, kind of cracks me up.


No, you've been there a long time.


OK, so you not only know everything,


Enough...


but you also know me?


to know that you're not only an idiot, but a jerk.


That my friend is a big error on your part.


Hardly. You advertise quite successfully.


Btw, aren't you the one that is being called
"Always wrong" ?


Wrong, again. You're just about as stupid as he, though. I'm the one
who gave him the (well deserved) "DimBulb" moniker, Junior.


Maybe I have you mixed up with another here but it seems to
fit at the moment.


Who haven't you mixed it up with? You let everyone know how stupid
you are.


And also, the original poster never commented on using differential
input for balanced pairs. So, go have your fun else where, you're
barking up the wrong tree.


He never indicated that he couldn't, either. Your *flat* assertion
that the grounds had to be the same is wrong. Perhaps you should take
DimBulb's "AlwaysWrong" name.

I'm barking up the wrong tree? I pin your ears to the wall, an *I* am
barking up the wrong tree? You are full of shit, but you've been told
that before.

Typical Ass whip.
Click to expand...

Figures.



http://webpages.charter.net/jamie_5"
 
Eeyore wrote:

Jamie wrote:


That is insane,,, glad you're not in my work group.


You're the one who's insane. You're almost as bad as AlwaysWrong.

Graham

You should stay out of places you don't belong.
Click to expand...

deranged lunatic.


http://webpages.charter.net/jamie_5"
 
On Tue, 17 Mar 2009 19:32:47 -0500, Jamie
<jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:

krw wrote:
On Mon, 16 Mar 2009 21:48:52 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


krw wrote:

On Mon, 16 Mar 2009 19:39:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:



krw wrote:



On Mon, 16 Mar 2009 18:08:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:




panfilero wrote:




Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!


Not directly, anyway. If the amplifier is set up as a differential
amplifier with unity gain. The output signal will be referenced to
the power supply grounds. In this configuration, the inputs ('+'
input, actually - the '-' input is along for the ride) must remain
within the common mode operating range of the Op-Amp though.

___ ___
+------|___|---+----|___|-+
| R | R |
| | |
/-\ | |\| |
( )2V +----+-\ |
\+/ Vin ___ | >--+------- +2V
+-----+|___|---+----| / out
R | |/|
|
.-.
| |R
| |
'-'
|
GND

(created by AACircuit v1.28.6 beta 04/19/05 www.tech-chat.de)






Yes.


Nope.




The only acception to the rule is if you had some form of isolation
device. In the case of the isolation, you only used the ground/common of
the input of the isolator device, it's output common does not come in
contact with the input common how ever, the output common still needs to
be connected with the circuits ground/common.

http://webpages.charter.net/jamie_5"


As usual for Jamie, wrong. The resistors will be the "isolation"
devices (not to be confused with safety isolation).


That is insane,,, glad you're not in my work group.


What would be insane is *being* in your "work" group.



really, kind of cracks me up.


No, you've been there a long time.


OK, so you not only know everything,


Enough...


but you also know me?


to know that you're not only an idiot, but a jerk.


That my friend is a big error on your part.


Hardly. You advertise quite successfully.


Btw, aren't you the one that is being called
"Always wrong" ?


Wrong, again. You're just about as stupid as he, though. I'm the one
who gave him the (well deserved) "DimBulb" moniker, Junior.


Maybe I have you mixed up with another here but it seems to
fit at the moment.


Who haven't you mixed it up with? You let everyone know how stupid
you are.


And also, the original poster never commented on using differential
input for balanced pairs. So, go have your fun else where, you're
barking up the wrong tree.


He never indicated that he couldn't, either. Your *flat* assertion
that the grounds had to be the same is wrong. Perhaps you should take
DimBulb's "AlwaysWrong" name.

I'm barking up the wrong tree? I pin your ears to the wall, an *I* am
barking up the wrong tree? You are full of shit, but you've been told
that before.

Typical Ass whip.
Click to expand...
Typical wannabe. A perfect DimBulb clone.

Figures.
Click to expand...
What a pretender.

http://webpages.charter.net/jamie_5"
Click to expand...
Jamie 5". A braggart too.
 
krw wrote:
On Tue, 17 Mar 2009 19:32:47 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:

krw wrote:
On Mon, 16 Mar 2009 21:48:52 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


krw wrote:

On Mon, 16 Mar 2009 19:39:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:



krw wrote:



On Mon, 16 Mar 2009 18:08:14 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:




panfilero wrote:




Hello,

If I have an OpAmp (a 741 for example) and I want to use it as a
buffer, and will be sending it 2Vdc, and am powering it with a dual
power supply +/-10V.... do I have to tie the grounds of my input
signal to the grounds of my power supply signal? the 2V ground and
the +/-10V ground?

much thanks!


Not directly, anyway. If the amplifier is set up as a differential
amplifier with unity gain. The output signal will be referenced to
the power supply grounds. In this configuration, the inputs ('+'
input, actually - the '-' input is along for the ride) must remain
within the common mode operating range of the Op-Amp though.

___ ___
+------|___|---+----|___|-+
| R | R |
| | |
/-\ | |\| |
( )2V +----+-\ |
\+/ Vin ___ | >--+------- +2V
+-----+|___|---+----| / out
R | |/|
|
.-.
| |R
| |
'-'
|
GND

(created by AACircuit v1.28.6 beta 04/19/05 www.tech-chat.de)






Yes.


Nope.




The only acception to the rule is if you had some form of isolation
device. In the case of the isolation, you only used the ground/common of
the input of the isolator device, it's output common does not come in
contact with the input common how ever, the output common still needs to
be connected with the circuits ground/common.

http://webpages.charter.net/jamie_5"


As usual for Jamie, wrong. The resistors will be the "isolation"
devices (not to be confused with safety isolation).


That is insane,,, glad you're not in my work group.


What would be insane is *being* in your "work" group.



really, kind of cracks me up.


No, you've been there a long time.


OK, so you not only know everything,


Enough...


but you also know me?


to know that you're not only an idiot, but a jerk.


That my friend is a big error on your part.


Hardly. You advertise quite successfully.


Btw, aren't you the one that is being called
"Always wrong" ?


Wrong, again. You're just about as stupid as he, though. I'm the one
who gave him the (well deserved) "DimBulb" moniker, Junior.


Maybe I have you mixed up with another here but it seems to
fit at the moment.


Who haven't you mixed it up with? You let everyone know how stupid
you are.


And also, the original poster never commented on using differential
input for balanced pairs. So, go have your fun else where, you're
barking up the wrong tree.


He never indicated that he couldn't, either. Your *flat* assertion
that the grounds had to be the same is wrong. Perhaps you should take
DimBulb's "AlwaysWrong" name.

I'm barking up the wrong tree? I pin your ears to the wall, an *I* am
barking up the wrong tree? You are full of shit, but you've been told
that before.

Typical Ass whip.

Typical wannabe. A perfect DimBulb clone.

Figures.

What a pretender.

http://webpages.charter.net/jamie_5"

Jamie 5". A braggart too.
Click to expand...

5 mm is likely closer to the truth.


--
http://improve-usenet.org/index.html

Goggle Groups, and Web TV users must request to be white listed, or I
will not see your messages.

If you have broadband, your ISP may have a NNTP news server included in
your account: http://www.usenettools.net/ISP.htm
 
Jamie wrote:

Eeyore wrote:
Jamie wrote:

That is insane,,, glad you're not in my work group.

You're the one who's insane. You're almost as bad as AlwaysWrong.

Graham

You should stay out of places you don't belong.

deranged lunatic.
Click to expand...
Ah, you're learning from Assilon.

Graham
 
On Wed, 18 Mar 2009 19:46:35 -0500, Jamie
<jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:

Eeyore wrote:


Jamie wrote:


Eeyore wrote:

Jamie wrote:


That is insane,,, glad you're not in my work group.

You're the one who's insane. You're almost as bad as AlwaysWrong.

Graham


You should stay out of places you don't belong.

deranged lunatic.


Ah, you're learning from Assilon.

Graham

Yes, he is my mentor. Glad you noticed!
Click to expand...
Perhaps he's your mentor (it would figure), but there isn't any
possibility of you learning anything. You're batting zero so far and
the prognosis isn't good.
 
Eeyore wrote:

Jamie wrote:


Eeyore wrote:

Jamie wrote:


That is insane,,, glad you're not in my work group.

You're the one who's insane. You're almost as bad as AlwaysWrong.

Graham


You should stay out of places you don't belong.

deranged lunatic.


Ah, you're learning from Assilon.

Graham

Yes, he is my mentor. Glad you noticed!
Click to expand...

http://webpages.charter.net/jamie_5"
 
krw wrote:
On Wed, 18 Mar 2009 19:46:35 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


Eeyore wrote:


Jamie wrote:



Eeyore wrote:


Jamie wrote:



That is insane,,, glad you're not in my work group.

You're the one who's insane. You're almost as bad as AlwaysWrong.

Graham


You should stay out of places you don't belong.

deranged lunatic.


Ah, you're learning from Assilon.

Graham


Yes, he is my mentor. Glad you noticed!


Perhaps he's your mentor (it would figure), but there isn't any
possibility of you learning anything. You're batting zero so far and
the prognosis isn't good.
Click to expand...
If that is your prognoses, I'm not to worried about it. I really don't
give much credence to your commentary. You don't hold a candle to what
I'm accustom to on a daily routine.


http://webpages.charter.net/jamie_5"
 
On Wed, 18 Mar 2009 22:21:52 -0500, Jamie
<jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:

krw wrote:
On Wed, 18 Mar 2009 19:46:35 -0500, Jamie
jamie_ka1lpa_not_valid_after_ka1lpa_@charter.net> wrote:


Eeyore wrote:


Jamie wrote:



Eeyore wrote:


Jamie wrote:



That is insane,,, glad you're not in my work group.

You're the one who's insane. You're almost as bad as AlwaysWrong.

Graham


You should stay out of places you don't belong.

deranged lunatic.


Ah, you're learning from Assilon.

Graham


Yes, he is my mentor. Glad you noticed!


Perhaps he's your mentor (it would figure), but there isn't any
possibility of you learning anything. You're batting zero so far and
the prognosis isn't good.

If that is your prognoses, I'm not to worried about it. I really don't
give much credence to your commentary. You don't hold a candle to what
I'm accustom to on a daily routine.
Click to expand...
I understand. You're used to much worse from those who really know
you. You really are stupid.
 
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