M
Mr.T
Guest
"Kristian Ukkonen" <kristian.ukkonen@iki.fi> wrote in message
news:kkuEe.168$Dl5.67@read3.inet.fi...
If you improve the circuit by converting the 6V to +/- 15V instead,
(assuming that does provide some benefit for the circuit involved) at least
there may be some point to it all.
Otherwise it would probably be easier to provide a battery low indicator for
each pair of cells.
MrT.
news:kkuEe.168$Dl5.67@read3.inet.fi...
Seems like a lot of extra effort and expense for no net benefit.Tim Martin wrote:
"Watson A.Name - "Watt Sun, the Dark Remover""
Better yet, get a piece of equipment that's not so poorly
designed that it runs down one set faster than the other.
OK. Suppose we have a circuit that draws 20 milliamps at -3v, and 220
milliamps at +3 volts. And suppose our power supply is four 1.5v
2200mAh
batteries, wired so one pair provides +3v, and the other pair
provides -3v.
Is it possible to redesign the power supply to do better than replace
the
+3v pair of batteries every 10 hours, and the -3v pair of batteries
every
110 hours? (So for 110 hours of operation, we'd need to replace 12
pairs of
batteries.)
Make a switching powersupply using 6V input and outputing
two 3V voltages?
Use a latching relay to switch the batteries (3V <> -3V)
every once and a while?
If you improve the circuit by converting the 6V to +/- 15V instead,
(assuming that does provide some benefit for the circuit involved) at least
there may be some point to it all.
Otherwise it would probably be easier to provide a battery low indicator for
each pair of cells.
MrT.