K
klem kedidelhopper
Guest
I have a 24 volt military truck that I use for snow plowing. In the
past I've had trouble finding 6000 series 24 volt sealed beam lamps
for the plow frame.. And when I did I have found them to be very
expensive. So I came up with a circuit using a DPDT switch in which
both the high and low circuit lamp filaments are wired in series when
power is applied. I was very careful to initially select two lamps
that drew exactly the same current when tested on my bench power
supply. The arrangement has worked flawlessly for the past few years.
The other night I had occaision to look at the lights from outside the
truck while it was running. Charging voltage on a 24 volt system can
run as high as 28 volts on a typical 24 volt system. Although I didn't
try to measure the voltage accross each lamp, I noticed that one lamp
is slightly brighter than the other on the low circuit. I'm assuming
that filament is getting weaker and thinner and will likely fail
shortly. And of course when that happens I'll lose the low circuit. I
can rematch two more lamps but before I do the thought occurred to me
if there was any practical easy way the equalise the voltage accross
both lamps in order to compensate for any minute differences in
filament resistance. I think that the total current, (two lamps in
series) is about 5.0 amps. Thanks for any suggestions. Lenny
past I've had trouble finding 6000 series 24 volt sealed beam lamps
for the plow frame.. And when I did I have found them to be very
expensive. So I came up with a circuit using a DPDT switch in which
both the high and low circuit lamp filaments are wired in series when
power is applied. I was very careful to initially select two lamps
that drew exactly the same current when tested on my bench power
supply. The arrangement has worked flawlessly for the past few years.
The other night I had occaision to look at the lights from outside the
truck while it was running. Charging voltage on a 24 volt system can
run as high as 28 volts on a typical 24 volt system. Although I didn't
try to measure the voltage accross each lamp, I noticed that one lamp
is slightly brighter than the other on the low circuit. I'm assuming
that filament is getting weaker and thinner and will likely fail
shortly. And of course when that happens I'll lose the low circuit. I
can rematch two more lamps but before I do the thought occurred to me
if there was any practical easy way the equalise the voltage accross
both lamps in order to compensate for any minute differences in
filament resistance. I think that the total current, (two lamps in
series) is about 5.0 amps. Thanks for any suggestions. Lenny