S
SME
Guest
Hello Group,
I have a variable motor controller board that is controlled by voltage.
I wish to control this board via my computer's printer port. Ideally using
CNC software such as EMC.
Any help would be very much appreciated.
The input has 3 wires lets say A B C.
Voltmeter Testing.
A and C = 12V Steady
A and B = Variable voltage 2.3 - 9.7 V Approx.
B and C = Variable Voltage 2.3 - 9.7V Approx.
When A + B carry low Volts, B + C are carrying high Volts and vice versa
(I.E. they complement each other and are relative adding up to the total of
12V)
The Higher voltage across B and C = Faster Motor Speed
The Higher voltage across A and B = Slower Motor Speed
So when B and C are reading max voltage the voltage to the motor is approx.
190V.
BTW this is off of a very old CNC machine.
What I am going to need to-do is have these voltages controlled via EMC + a
circuit to produce the above output voltages.
Does anyone have any idea what is required or what this circuit is called.
Congratulations on getting this far ... ;-)
TIA
Steve.
I have a variable motor controller board that is controlled by voltage.
I wish to control this board via my computer's printer port. Ideally using
CNC software such as EMC.
Any help would be very much appreciated.
The input has 3 wires lets say A B C.
Voltmeter Testing.
A and C = 12V Steady
A and B = Variable voltage 2.3 - 9.7 V Approx.
B and C = Variable Voltage 2.3 - 9.7V Approx.
When A + B carry low Volts, B + C are carrying high Volts and vice versa
(I.E. they complement each other and are relative adding up to the total of
12V)
The Higher voltage across B and C = Faster Motor Speed
The Higher voltage across A and B = Slower Motor Speed
So when B and C are reading max voltage the voltage to the motor is approx.
190V.
BTW this is off of a very old CNC machine.
What I am going to need to-do is have these voltages controlled via EMC + a
circuit to produce the above output voltages.
Does anyone have any idea what is required or what this circuit is called.
Congratulations on getting this far ... ;-)
TIA
Steve.