user list order form

[anandganesan@gmail.com]

hi
i have a list and i want to display it on a form and let the user
rearrange it in his suitable manner. finally the form needs to be
closed with the reordered list. does anyone already have a code for
this or can you suggest the simplest way of doing this?

thanks.

anand.

 

[S. Badel]

here is a bit of code. it supposes your list is a list of integers. it's
important because it uses a report field. could however be tweaked
easily for other data type or even for list of lists.
usage: OLReorderList( mylist ) => reordered_list

OLListField = hiCreateReportField(
?name 'list
?title "List"
?titleAlignment 'left
?headers '( ("Item" 300 left int nil ) )
?choices nil
)

OLUpButton = hiCreateButton(
?name 'upBtn
?buttonText "Up"
?callback "OLUpCB(hiGetCurrentForm())"
)

OLDownButton = hiCreateButton(
?name 'downBtn
?buttonText "Down"
?callback "OLDownCB(hiGetCurrentForm())"
)

OLForm = hiCreateAppForm(
?name 'adeTxtOutSetupForm
?formTitle "Order List"
?buttonLayout '(OKCancel)
?buttonDisabled '( Help )
?dialogStyle 'modal
?fields list(
list( OLListField 10:10 400:200 100 )
list( OLUpButton 450:66 50:30 )
list( OLDownButton 450:122 50:30 )
)
?initialSize 520:250
?minSize 520:250
?maxSize 520:250
) ; hiCreateAppForm

; procedure to swap two adjacent items in a list
procedure( OLSwapItems(l a b)
let( ( (x min(a b)) (y max(a b)) )
if( x==1 then
cons( cadr(l) cons( car(l) cddr(l) ) )
else
cons( car(l) swapItems(cdr(l) x-1 y-1) )
) ; if
) ; let
) ; procedure

procedure( OLUpCB(form)
; process each item from the selection
let( (selection)
selection = form~>list~>value
foreach( item form~>list~>value
; exchange the item and it's predecessor
when( item
form~>list~>choices = OLSwapItems(form~>list~>choices item item+1)
)
) ; foreach
form~>list~>value=mapcar(lambda( (x) x=x-1 ) selection )
) ; let
) ; procedure

procedure( OLDownCB(form)
; process each item from the selection
let( (selection)
selection = form~>list~>value
foreach( item reverse(selection)
; exchange the item and it's predecessor
when( item+1!=length(form~>list~>choices)
form~>list~>choices = OLSwapItems(form~>list~>choices item+1 item+2)
)
) ; foreach
form~>list~>value=mapcar(lambda( (x) x=x+1 ) selection )
) ; let
) ; procedure

procedure( OLReorderList( l )
OLForm~>list~>choices = mapcar( 'list l )
if( hiDisplayForm(OLForm) mapcar( 'car OLForm~>list~>choices ) l )
) ; procedure



anandganesan@gmail.com wrote:

hi
i have a list and i want to display it on a form and let the user
rearrange it in his suitable manner. finally the form needs to be
closed with the reordered list. does anyone already have a code for
this or can you suggest the simplest way of doing this?

thanks.

anand.