Use circuit for blinking LED for use with 4 LEDS

[Mint]

I have a flashlight that I would like to change what it does.

I want the blinking LED circuit(one bulb) to be used to run the 4 LEDS
that are used
for the "flashlight".

In other words, I would like the 4 LEDS to blink.

I don't care if the blinking LED is no longer available.

Here is the circuit.

Blinking LED circuit has positive going to one lead of the blinking
bulb.

Other lead going to bulb has a resistor going between 2nd lead of
blinking LED
to one lead of the LED #4 that make up the 4 LEDS previously
mentioned.

Can I wire it so that the 4 LEDS blink instead of the single LED?

Thanks,
Andy

 

[Tim Wescott]

On 11/10/2010 03:26 PM, Mint wrote:

I have a flashlight that I would like to change what it does.

I want the blinking LED circuit(one bulb) to be used to run the 4 LEDS
that are used
for the "flashlight".

In other words, I would like the 4 LEDS to blink.

I don't care if the blinking LED is no longer available.

Here is the circuit.

Blinking LED circuit has positive going to one lead of the blinking
bulb.

Other lead going to bulb has a resistor going between 2nd lead of
blinking LED
to one lead of the LED #4 that make up the 4 LEDS previously
mentioned.

Can I wire it so that the 4 LEDS blink instead of the single LED?

Try posting a schematic of what you propose.

--

Tim Wescott
Wescott Design Services
http://www.wescottdesign.com

Do you need to implement control loops in software?
"Applied Control Theory for Embedded Systems" was written for you.
See details at http://www.wescottdesign.com/actfes/actfes.html

 

[Mint]

On Nov 10, 8:55 pm, Tim Wescott <t...@seemywebsite.com> wrote:

On 11/10/2010 03:26 PM, Mint wrote:



I have a flashlight that I would like to change what it does.

I want the blinking LED circuit(one bulb) to be used to run the 4 LEDS
that are used
for the "flashlight".

In other words, I would like the 4 LEDS to blink.

I don't care if the blinking LED is no longer available.

Here is the circuit.

Blinking LED circuit has positive going to one lead of the blinking
bulb.

Other lead going to bulb has a resistor going between 2nd lead of
blinking LED
to one lead of the LED #4 that make up the 4 LEDS previously
mentioned.

Can I wire it so that the 4 LEDS blink instead of the single LED?

Try posting a schematic of what you propose.

--

Tim Wescott
Wescott Design Serviceshttp://www.wescottdesign.com

Do you need to implement control loops in software?
"Applied Control Theory for Embedded Systems" was written for you.
See details athttp://www.wescottdesign.com/actfes/actfes.html

I don't have a schematic.

That's why I posted what the circuit board looks like and all it's
connections.

Andy

 

[ehsjr]

Mint wrote:

On Nov 10, 8:55 pm, Tim Wescott <t...@seemywebsite.com> wrote:

On 11/10/2010 03:26 PM, Mint wrote:




I have a flashlight that I would like to change what it does.

I want the blinking LED circuit(one bulb) to be used to run the 4 LEDS
that are used
for the "flashlight".

In other words, I would like the 4 LEDS to blink.

I don't care if the blinking LED is no longer available.

Here is the circuit.

Blinking LED circuit has positive going to one lead of the blinking
bulb.

Other lead going to bulb has a resistor going between 2nd lead of
blinking LED
to one lead of the LED #4 that make up the 4 LEDS previously
mentioned.

Can I wire it so that the 4 LEDS blink instead of the single LED?

Try posting a schematic of what you propose.

--

Tim Wescott
Wescott Design Serviceshttp://www.wescottdesign.com

Do you need to implement control loops in software?
"Applied Control Theory for Embedded Systems" was written for you.
See details athttp://www.wescottdesign.com/actfes/actfes.html


I don't have a schematic.

That's why I posted what the circuit board looks like and all it's
connections.

Andy

Draw one in ascii. Make up understandable symbols as needed:

Resistor = ---[R]--- or ---/\/\/---
LED = ---[LED]---
Bulb = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery = ---[+Batt]---

Show values where needed. For example ---[470R]--- is a
470 ohm resistor.

Ed

 

[Winston]

ehsjr wrote:

(...)

Draw one in ascii. Make up understandable symbols as needed:

Resistor = ---[R]--- or ---/\/\/---
LED = ---[LED]---
Bulb = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery = ---[+Batt]---

Show values where needed. For example ---[470R]--- is a
470 ohm resistor.

Or download Andreas Weber's excellent AACircuit program:
http://www.tech-chat.de/files/AACircuit1_28_6.zip

--Winston

 

[Mint]

On Nov 11, 1:15 am, Winston <Wins...@BigBrother.net> wrote:

ehsjr wrote:

(...)

Draw one in ascii. Make up understandable symbols as needed:

Resistor = ---[R]--- or ---/\/\/---
LED = ---[LED]---
Bulb = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery = ---[+Batt]---

Show values where needed. For example ---[470R]--- is a
470 ohm resistor.

Or download Andreas Weber's excellent AACircuit program:http://www.tech-chat.de/files/AACircuit1_28_6.zip

--Winston

Thanks a lot Winston.

Andy

 

[Mint]

On Nov 11, 12:20 am, ehsjr <eh...@nospamverizon.net> wrote:

Mint wrote:
On Nov 10, 8:55 pm, Tim Wescott <t...@seemywebsite.com> wrote:

On 11/10/2010 03:26 PM, Mint wrote:

I have a flashlight that I would like to change what it does.

I want the blinking LED circuit(one bulb) to be used to run the 4 LEDS
that are used
for the "flashlight".

In other words, I would like the 4 LEDS to blink.

I don't care if the blinking LED is no longer available.

Here is the circuit.

Blinking LED circuit has positive going to one lead of the blinking
bulb.

Other lead going to bulb has a resistor going between 2nd lead of
blinking LED
to one lead of the LED #4 that make up the 4 LEDS previously
mentioned.

Can I wire it so that the 4 LEDS blink instead of the single LED?

Try posting a schematic of what you propose.

--

Tim Wescott
Wescott Design Serviceshttp://www.wescottdesign.com

Do you need to implement control loops in software?
"Applied Control Theory for Embedded Systems" was written for you.
See details athttp://www.wescottdesign.com/actfes/actfes.html

I don't have a schematic.

That's why I posted what the circuit board looks like and all it's
connections.

Andy

Draw one in ascii.  Make up understandable symbols as needed:

Resistor     = ---[R]---   or ---/\/\/---
LED          = ---[LED]---
Bulb         = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery      = ---[+Batt]---

Show values where needed. For example ---[470R]--- is a
470 ohm resistor.

Ed

I will do that.

I will have to look up the value of my resistor.

Andy

 

[Mint]

On Nov 11, 5:27 am, Mint <chocolatemint77...@yahoo.com> wrote:

On Nov 11, 12:20 am, ehsjr <eh...@nospamverizon.net> wrote:



Mint wrote:
On Nov 10, 8:55 pm, Tim Wescott <t...@seemywebsite.com> wrote:

On 11/10/2010 03:26 PM, Mint wrote:

I have a flashlight that I would like to change what it does.

I want the blinking LED circuit(one bulb) to be used to run the 4 LEDS
that are used
for the "flashlight".

In other words, I would like the 4 LEDS to blink.

I don't care if the blinking LED is no longer available.

Here is the circuit.

Blinking LED circuit has positive going to one lead of the blinking
bulb.

Other lead going to bulb has a resistor going between 2nd lead of
blinking LED
to one lead of the LED #4 that make up the 4 LEDS previously
mentioned.

Can I wire it so that the 4 LEDS blink instead of the single LED?

Try posting a schematic of what you propose.

--

Tim Wescott
Wescott Design Serviceshttp://www.wescottdesign.com

Do you need to implement control loops in software?
"Applied Control Theory for Embedded Systems" was written for you.
See details athttp://www.wescottdesign.com/actfes/actfes.html

I don't have a schematic.

That's why I posted what the circuit board looks like and all it's
connections.

Andy

Draw one in ascii.  Make up understandable symbols as needed:

Resistor     = ---[R]---   or ---/\/\/---
LED          = ---[LED]---
Bulb         = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery      = ---[+Batt]---

Show values where needed. For example ---[470R]--- is a
470 ohm resistor.

Ed

I will do that.

I will have to look up the value of my resistor.

Andy

In making this, I realized that the blinking LED is not controlled by
a circuit.
It blinks when voltage is applied to it.

It looks like I would have to replace the 4 "regular" LEDs with the
"blinking" type or
a circuit to make those blink.

Andy

[LED1]
[R1]

[LED4] [BlinkingLED5] [LED2]


[R2] [LED3]

Notes:
LED5 emits red light
[R1] = 20 ohms
[R2] = 10 ohms
+ to one lead of all LEDS

Resistor = ---[R]---
LED = ---[LED]---
Bulb = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery = ---[+Batt]---

 

[John Fields]

On Thu, 11 Nov 2010 04:48:05 -0800 (PST), Mint
<chocolatemint77581@yahoo.com> wrote:

On Nov 11, 5:27 am, Mint <chocolatemint77...@yahoo.com> wrote:
On Nov 11, 12:20 am, ehsjr <eh...@nospamverizon.net> wrote:



Mint wrote:
On Nov 10, 8:55 pm, Tim Wescott <t...@seemywebsite.com> wrote:

On 11/10/2010 03:26 PM, Mint wrote:

I have a flashlight that I would like to change what it does.

I want the blinking LED circuit(one bulb) to be used to run the 4 LEDS
that are used
for the "flashlight".

In other words, I would like the 4 LEDS to blink.

I don't care if the blinking LED is no longer available.

Here is the circuit.

Blinking LED circuit has positive going to one lead of the blinking
bulb.

Other lead going to bulb has a resistor going between 2nd lead of
blinking LED
to one lead of the LED #4 that make up the 4 LEDS previously
mentioned.

Can I wire it so that the 4 LEDS blink instead of the single LED?

Try posting a schematic of what you propose.

--

Tim Wescott
Wescott Design Serviceshttp://www.wescottdesign.com

Do you need to implement control loops in software?
"Applied Control Theory for Embedded Systems" was written for you.
See details athttp://www.wescottdesign.com/actfes/actfes.html

I don't have a schematic.

That's why I posted what the circuit board looks like and all it's
connections.

Andy

Draw one in ascii.  Make up understandable symbols as needed:

Resistor     = ---[R]---   or ---/\/\/---
LED          = ---[LED]---
Bulb         = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery      = ---[+Batt]---

Show values where needed. For example ---[470R]--- is a
470 ohm resistor.

Ed

I will do that.

I will have to look up the value of my resistor.

Andy

In making this, I realized that the blinking LED is not controlled by
a circuit.
It blinks when voltage is applied to it.

It looks like I would have to replace the 4 "regular" LEDs with the
"blinking" type or
a circuit to make those blink.

Andy

[LED1]
[R1]

[LED4] [BlinkingLED5] [LED2]


[R2] [LED3]

Notes:
LED5 emits red light
[R1] = 20 ohms
[R2] = 10 ohms
+ to one lead of all LEDS

Resistor = ---[R]---
LED = ---[LED]---
Bulb = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery = ---[+Batt]---

---

You have to show connections, and don't use the tab key; use the
spacebar instead.

From what you've said so far, it appears this is what you have:

(View in a fixed-pitch font like Courier)


.. +------+---------------------------+
.. | | |
.. | [10R] [20R]
.. |+ | |
.. [BAT] +------+------+------+ |
.. | | | | | |
.. | [LED1] [LED2] [LED3] [LED4] [LED5]
.. | | | | | |
.. +------+------+------+------+------+


1. What is the battery voltage?

2. Is there an ON-OFF switch anywhere?
Where?

3. Are the resistors shown in the correct locations?

3. Are the resistors brown-black-black-gold and red-black-black-gold
or brown-black-brown-gold and red-black-brown-gold?
Or something else?

---
JF

 

[John Fields]

On Thu, 11 Nov 2010 09:21:44 -0600, John Fields
<jfields@austininstruments.com> wrote:

You have to show connections, and don't use the tab key; use the
spacebar instead.

From what you've said so far, it appears this is what you have:

(View in a fixed-pitch font like Courier)


. +------+---------------------------+
. | | |
. | [10R] [20R]
. |+ | |
. [BAT] +------+------+------+ |
. | | | | | |
. | [LED1] [LED2] [LED3] [LED4] [LED5]
. | | | | | |
. +------+------+------+------+------+


1. What is the battery voltage?

2. Is there an ON-OFF switch anywhere?
Where?

3. Are the resistors shown in the correct locations?

3. Are the resistors brown-black-black-gold and red-black-black-gold
or brown-black-brown-gold and red-black-brown-gold?
Or something else?

---
I forgot... what color are the non-blinking leds?

---
JF

 

[Mint]

On Nov 11, 9:21 am, John Fields <jfie...@austininstruments.com> wrote:

On Thu, 11 Nov 2010 04:48:05 -0800 (PST), Mint



chocolatemint77...@yahoo.com> wrote:
On Nov 11, 5:27 am, Mint <chocolatemint77...@yahoo.com> wrote:
On Nov 11, 12:20 am, ehsjr <eh...@nospamverizon.net> wrote:

Mint wrote:
On Nov 10, 8:55 pm, Tim Wescott <t...@seemywebsite.com> wrote:

On 11/10/2010 03:26 PM, Mint wrote:

I have a flashlight that I would like to change what it does.

I want the blinking LED circuit(one bulb) to be used to run the 4 LEDS
that are used
for the "flashlight".

In other words, I would like the 4 LEDS to blink.

I don't care if the blinking LED is no longer available.

Here is the circuit.

Blinking LED circuit has positive going to one lead of the blinking
bulb.

Other lead going to bulb has a resistor going between 2nd lead of
blinking LED
to one lead of the LED #4 that make up the 4 LEDS previously
mentioned.

Can I wire it so that the 4 LEDS blink instead of the single LED?

Try posting a schematic of what you propose.

--

Tim Wescott
Wescott Design Serviceshttp://www.wescottdesign.com

Do you need to implement control loops in software?
"Applied Control Theory for Embedded Systems" was written for you.
See details athttp://www.wescottdesign.com/actfes/actfes.html

I don't have a schematic.

That's why I posted what the circuit board looks like and all it's
connections.

Andy

Draw one in ascii. Make up understandable symbols as needed:

Resistor = ---[R]--- or ---/\/\/---
LED = ---[LED]---
Bulb = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery = ---[+Batt]---

Show values where needed. For example ---[470R]--- is a
470 ohm resistor.

Ed

I will do that.

I will have to look up the value of my resistor.

Andy

In making this, I realized that the blinking LED is not controlled by
a circuit.
It blinks when voltage is applied to it.

It looks like I would have to replace the 4 "regular" LEDs with the
"blinking" type or
a circuit to make those blink.

Andy

                   [LED1]
       [R1]

   [LED4]  [BlinkingLED5]  [LED2]

       [R2]     [LED3]

Notes:
      LED5 emits red light
      [R1] = 20 ohms
      [R2] = 10 ohms
      + to one lead of all LEDS

Resistor     = ---[R]---
LED          = ---[LED]---
Bulb         = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery      = ---[+Batt]---

---

You have to show connections, and don't use the tab key; use the
spacebar instead.

From what you've said so far, it appears this is what you have:

(View in a fixed-pitch font like Courier)

.       +------+---------------------------+
.       |      |                           |
.       |    [10R]                       [20R]
.       |+     |                           |
.     [BAT]    +------+------+------+      |
.       |      |      |      |      |      |
.       |    [LED1] [LED2] [LED3] [LED4] [LED5]
.       |      |      |      |      |      |
.       +------+------+------+------+------+

1. What is the battery voltage?

2. Is there an ON-OFF switch anywhere?
   Where?

3. Are the resistors shown in the correct locations?

3. Are the resistors brown-black-black-gold and red-black-black-gold
   or brown-black-brown-gold and red-black-brown-gold?
   Or something else?

---
JF

Non-blinking LEDS are clear.

Battery voltage is 4.5 Volts D.C.

It has an on/off switch, one side of switch turns on 4 Leds which
serve as a flashlight, the other side of switch turns on the blinking
RED Led.

Resistor values are what my pics shows, under Notes:

Andy

 

[John Fields]

On Thu, 11 Nov 2010 07:40:15 -0800 (PST), Mint
<chocolatemint77581@yahoo.com> wrote:

On Nov 11, 9:21 am, John Fields <jfie...@austininstruments.com> wrote:

You have to show connections, and don't use the tab key; use the
spacebar instead.

From what you've said so far, it appears this is what you have:

(View in a fixed-pitch font like Courier)

.       +------+---------------------------+
.       |      |                           |
.       |    [10R]                       [20R]
.       |     |                           |
.     [BAT]    +------+------+------+      |
.       |+     |k     |k     |k     |k     |k
.       |    [LED1] [LED2] [LED3] [LED4] [LED5]
.       |      |      |      |      |      |
.       +------+------+------+------+------+

1. What is the battery voltage?

2. Is there an ON-OFF switch anywhere?
   Where?

3. Are the resistors shown in the correct locations?

3. Are the resistors brown-black-black-gold and red-black-black-gold
   or brown-black-brown-gold and red-black-brown-gold?
   Or something else?

---
JF

Non-blinking LEDS are clear.

---
White light when they're on?
---

Battery voltage is 4.5 Volts D.C.

---
OK
---

It has an on/off switch, one side of switch turns on 4 Leds which
serve as a flashlight, the other side of switch turns on the blinking
RED Led.

---
OK, but what I need to know is how the switch works and how it's wired
into the circuit.

That is, assuming that there's an OFF position where eveything's off,
in the other two positions can the red LED be blinking while the white
ones are on, or does the red LED go off when the white ones are on,
and vice-versa?

Or are there two switches?
---

Resistor values are what my pics shows, under Notes:

---
Are you sure?

The reason I ask is because if you've got a 20 ohm resistor in series
with the red LED, then if the red LED drops about 1.2 volts, the
remaining 3.3 volts from your battery will have to be dropped across
the resistor and, from Ohm's law, the current through the resistor and
the LED must be:


E 3.3V
I = --- = ------ = 0.165 amperes
R 20R

Standard LEDs are supposed to have the current through them limited to
20mA, so unless yours is special that's about 8 times more current
than is supposed to be going through that LED.

On the other hand, if the resistor is 200 ohms, (red-brown-brown-gold)
then the current would be 0.0165A = 16.5mA, which is just about right.

Same reasoning for the white LEDs, except they should each have a
separate resistor in order to prevent what's called "current hogging"

Assuming the white LEDs have a drop of 3.5V at 20mA, then the 1V would
have to be dropped across 50 ohms.

For four LEDs the current would be 80mA (20 apiece X 4) and a single
resistor would be 12.5 ohms.

If you've got 10 ohms in there, then that's what they did to keep from
having to buy 3 more resistors.

Anyway, I can't think of any way to do what you want without adding a
few parts to the circuiot and rewiring it completely.

If you want to do that then please answer the questions above and I'll
be happy to work something up for you.

BTW, I connected the battery up backwards on my first schematic, but I
fixed it and put in the LED polatities as well.


---
JF

 

[Winston]

Mint wrote:

On Nov 11, 1:15 am, Winston<Wins...@BigBrother.net> wrote:
ehsjr wrote:

(...)

Draw one in ascii. Make up understandable symbols as needed:

Resistor = ---[R]--- or ---/\/\/---
LED = ---[LED]---
Bulb = ---[Bulb]---
Blinking LED = ---[BlinkingLED]---
Battery = ---[+Batt]---

Show values where needed. For example ---[470R]--- is a
470 ohm resistor.

Or download Andreas Weber's excellent AACircuit program:http://www.tech-chat.de/files/AACircuit1_28_6.zip

--Winston

Thanks a lot Winston.

Andy
.----------o----------o-----------------o---------.

| | | | |
| .-. R1 .-. R2 .-. R3 .-. R4
| | | 25k | | 250k | | 250k | | 25k
| | | | | | | | |
| '-' C1 '-' '-' C2 '-'
| | | | |
| | || | | || |
| o----||----o----. .------o---||----o
| 9V | || \ / || |
--- | \ / |
- | 1n / 1n |
| Q1 | / \ | Q2
| \| / \ |/
| 2N2222 |-------------' '----------o---| 2N2222
| <| | |>
| | | |
| | o |o--' |
| | <--| |
| | | |
| | SW open o |
| | 1ms | |
'----------o----------------------------o---------'


You are welcome, Andy!

--Winston

 

[Mint]

On Nov 11, 11:34 am, John Fields <jfie...@austininstruments.com>
wrote:

On Thu, 11 Nov 2010 07:40:15 -0800 (PST), Mint



chocolatemint77...@yahoo.com> wrote:
On Nov 11, 9:21 am, John Fields <jfie...@austininstruments.com> wrote:
You have to show connections, and don't use the tab key; use the
spacebar instead.

From what you've said so far, it appears this is what you have:

(View in a fixed-pitch font like Courier)

. +------+---------------------------+
. | | |
. | [10R] [20R]
. |   | |
. [BAT] +------+------+------+ |
. |+ |k |k |k |k |k
. | [LED1] [LED2] [LED3] [LED4] [LED5]
. | | | | | |
. +------+------+------+------+------+

1. What is the battery voltage?

2. Is there an ON-OFF switch anywhere?
Where?

3. Are the resistors shown in the correct locations?

3. Are the resistors brown-black-black-gold and red-black-black-gold
or brown-black-brown-gold and red-black-brown-gold?
Or something else?

---
JF

Non-blinking LEDS are clear.

---
White light when they're on?
---

Battery voltage is 4.5 Volts D.C.

---
OK
---

It has an on/off switch, one side of switch turns on 4 Leds which
serve as a flashlight, the other side of switch turns on the blinking
RED Led.

---
OK, but what I need to know is how the switch works and how it's wired
into the circuit.

That is, assuming that there's an OFF position where eveything's off,
in the other two positions can the red LED be blinking while the white
ones are on, or does the red LED go off when the white ones are on,
and vice-versa?

Or are there two switches?
---

Resistor values are what my pics shows, under Notes:

---
Are you sure?

The reason I ask is because if you've got a 20 ohm resistor in series
with the red LED, then if the red LED drops about 1.2 volts, the
remaining 3.3 volts from your battery will have to be dropped across
the resistor and, from Ohm's law, the current through the resistor and
the LED must be:

         E     3.3V
    I = --- = ------ = 0.165 amperes
         R     20R

Standard LEDs are supposed to have the current through them limited to
20mA, so unless yours is special that's about 8 times more current
than is supposed to be going through that LED.

On the other hand, if the resistor is 200 ohms, (red-brown-brown-gold)
then the current would be 0.0165A = 16.5mA, which is just about right.

Same reasoning for the white LEDs, except they should each have a
separate resistor in order to prevent what's called "current hogging"

Assuming the white LEDs have a drop of 3.5V at 20mA, then the 1V would
have to be dropped across 50 ohms.

For four LEDs the current would be 80mA (20 apiece X 4) and a single
resistor would be 12.5 ohms.

If you've got 10 ohms in there, then that's what they did to keep from
having to buy 3 more resistors.

Anyway, I can't think of any way to do what you want without adding a
few parts to the circuiot and rewiring it completely.

If you want to do that then please answer the questions above and I'll
be happy to work something up for you.

BTW, I connected the battery up backwards on my first schematic, but I
fixed it and put in the LED polatities as well.

---
JF

Resistors are brown-black-black-gold and red-black-black-gold.

Switch has 3 positions. Red LED blinking. (other LEDs OFF) --- OFF
--- 4 Clear LEDs continually on(Red LED off)

Andy

 

[John Fields]

On Thu, 11 Nov 2010 11:17:38 -0800 (PST), Mint
<chocolatemint77581@yahoo.com> wrote:

Resistors are brown-black-black-gold and red-black-black-gold.

Switch has 3 positions. Red LED blinking. (other LEDs OFF) --- OFF
--- 4 Clear LEDs continually on(Red LED off)

OK

If, as you say, the battery + goes to all of the LEDs and there's no
switch in that lead, then the flashlight must be wired like this:


.. +------+------+------+------+------+
..       |      |A     |A     |A     |A     |A
..       |    [LED1] [LED2] [LED3] [LED4] [LED5]
..       |      |      |      |      |      |
..     | +------+------+------+ |
..       |+     |                           |
..     [BAT]  [10R]         OFF           [20R]
..       |     |            O              |
..     | +----------O | O------------+
.. | / | \
.. | ON O BLINK
.. | |
.. +-------------------+


If you rewire it like this:


.. +------+------+------+------+-------+-------+
.. | | | | | | |
.. |      |A     |A     |A     |A  |  |A
.. |    [LED1] [LED2] [LED3] [LED4] | [LED5]
.. |      |      |      |      |     |  |
.. | | | | | | |
.. |+     |R1    |R2 |R3    |R4   |R5 |R6
..[4V5]  [51R]  [51R] [51R] [51R] [390R] [??R]
..  |     | |      |      |      | |
.. | +------+------+------+ | ON |
.. | | |/ OFF |
.. | C O / |
.. | 2N4401 B--O--- O |
.. | Q1 E S1 O-------+
.. | | \
.. +---------------------------+ BLINK

in the ON position, the flashlight array will throw a steady light
and the red LED will be dark.

In the OFF position, both the flashlight array and the red LED will be
dark.

In the BLINK position, both the white LEDs and the red LED will flash
at the same rate.

That is, providing the LED looks like a low-valued resistor when it's
on and a high-valued resistor or an open circuit when it's off. If it
doesn't, then the circuit won't work.

Earlier, I made the assumption that the flashing LED was dropping
about 1.2V with 165mA through it, but neglected to add in the drop for
the flashing circuitry, of which the pass element is in series with
the lamp.

The problem is, after having looked at several blinking red LEDs,
their voltage drop is all over the place and, not knowing which one
yours is, there's no way to tie down the value of R6.

If you have a voltmeter you can measure the voltage across the red LED
when it's on and then figure out the value of R6 like this:

4.5V - Vled(on) - Vbe
R5 = ----------------------
0.02A

That'll give you the value of R5 for 20mA into the base of Q1, which
should be enough to let the red LED flash and flash the rest of the
LEDs as well.

If you don't have a voltmeter, I'd guess at about 2V across the LED
when it's on, and about 0.7V across the base-to emitter junction of
Q1. Then R5 would be:

4.5V - 2V - 0.7V
R5 = ------------------ = 90 ohms
0.02A

91 ohms is a standard 5% part and should work well if the LED will
flash with 2V across it.

If it won't, try lowering the value of R6 until it does.

BTW, I have all the parts on hand and they're just pennies, so if you
email me with someplace to send them I'll just pop them in the mail
and save you the hassle of having to buy them.

Unless that creeps you out, of course. :-(

---
JF

 

[Mint]

On Nov 12, 4:33 am, John Fields <jfie...@austininstruments.com> wrote:

On Thu, 11 Nov 2010 11:17:38 -0800 (PST), Mint

chocolatemint77...@yahoo.com> wrote:
Resistors are brown-black-black-gold and red-black-black-gold.

Switch has 3 positions.    Red LED blinking. (other LEDs OFF) --- OFF
--- 4 Clear LEDs continually on(Red LED off)

OK

If, as you say, the battery + goes to all of the LEDs and there's no
switch in that lead, then the flashlight must be wired like this:

.       +------+------+------+------+------+
. | |A |A |A |A |A
. | [LED1] [LED2] [LED3] [LED4] [LED5]
. | | | | | |
.   |      +------+------+------+      |
. |+ | |
. [BAT] [10R] OFF [20R]
. |   | O |
.   |      +----------O | O------------+
.       |                /  |  \
.       |              ON   O   BLINK
.       |                   |
.       +-------------------+

If you rewire it like this:

.  +------+------+------+------+-------+-------+
.  |      |      |      |      |       |       |    
.  | |A |A |A |A     |       |A
.  | [LED1] [LED2] [LED3] [LED4]    |     [LED5]
.  | | | | |   |       |
.  |      |      |      |      |       |       |
.  |+ |R1 |R2    |R3 |R4   |R5     |R6
.[4V5] [51R] [51R]  [51R]  [51R]   [390R]  [??R]
. |   |      | | |  |       |
.  |      +------+------+------+       | ON    |
.  |                           |       |/  OFF |
.  |                           C       O  /    |
.  |                      2N4401 B--O--- O     |
.  |                       Q1  E   S1  O-------+
.  |                           |        \    
.  +---------------------------+         BLINK

in the ON position, the flashlight array  will throw a steady light
and the red LED will be dark.

In the OFF position, both the flashlight array and the red LED will be
dark.

In the BLINK position, both the white LEDs and the red LED will flash
at the same rate.

That is, providing the LED looks like a low-valued resistor when it's
on and a high-valued resistor or an open circuit when it's off.  If it
doesn't, then the circuit won't work.

Earlier, I made the assumption that the flashing LED was dropping
about 1.2V with 165mA through it, but neglected to add in the drop for
the flashing circuitry, of which the pass element is in series with
the lamp.

The problem is, after having looked at several blinking red LEDs,
their voltage drop is all over the place and, not knowing which one
yours is, there's no way to tie down the value of R6.

If you have a voltmeter you can measure the voltage across the red LED
when it's on and then figure out the value of R6 like this:

          4.5V - Vled(on) - Vbe
    R5 = ----------------------
                 0.02A

That'll give you the value of R5 for 20mA into the base of Q1, which
should be enough to let the red LED flash and flash the rest of the
LEDs as well.

If you don't have a voltmeter, I'd guess at about 2V across the LED
when it's on, and about 0.7V across the base-to emitter junction of
Q1.  Then R5 would be:

          4.5V - 2V - 0.7V
    R5 = ------------------ = 90 ohms
               0.02A

91 ohms is a standard 5% part and should work well if the LED will
flash with 2V across it.

If it won't, try lowering the value of R6 until it does.

BTW, I have all the parts on hand and they're just pennies, so if you
email me with someplace to send them I'll just pop them in the mail
and save you the hassle of having to buy them.

Unless that creeps you out, of course. :-(

---
JF

I tried testing the voltage across the red LED.

Both leads came off. (Will replace with better wires.)
($3 special from Northern tools.

Will get back with you.

Andy

 

[Mint]

On Nov 12, 7:51 am, Mint <chocolatemint77...@yahoo.com> wrote:

On Nov 12, 4:33 am, John Fields <jfie...@austininstruments.com> wrote:



On Thu, 11 Nov 2010 11:17:38 -0800 (PST), Mint

chocolatemint77...@yahoo.com> wrote:
Resistors are brown-black-black-gold and red-black-black-gold.

Switch has 3 positions.    Red LED blinking. (other LEDs OFF) --- OFF
--- 4 Clear LEDs continually on(Red LED off)

OK

If, as you say, the battery + goes to all of the LEDs and there's no
switch in that lead, then the flashlight must be wired like this:

.       +------+------+------+------+------+
. | |A |A |A |A |A
. | [LED1] [LED2] [LED3] [LED4] [LED5]
. | | | | | |
.   |      +------+------+------+      |
. |+ | |
. [BAT] [10R] OFF [20R]
. |   | O |
.   |      +----------O | O------------+
.       |                /  |  \
.       |              ON   O   BLINK
.       |                   |
.       +-------------------+

If you rewire it like this:

.  +------+------+------+------+-------+-------+
.  |      |      |      |      |       |       |    
.  | |A |A |A |A     |       |A
.  | [LED1] [LED2] [LED3] [LED4]    |     [LED5]
.  | | | | |   |       |
.  |      |      |      |      |       |       |
.  |+ |R1 |R2    |R3 |R4   |R5     |R6
.[4V5] [51R] [51R]  [51R]  [51R]   [390R]  [??R]
. |   |      | | |  |       |
.  |      +------+------+------+       | ON    |
.  |                           |       |/  OFF |
.  |                           C       O  /    |
.  |                      2N4401 B--O--- O     |
.  |                       Q1  E   S1  O-------+
.  |                           |        \    
.  +---------------------------+         BLINK

in the ON position, the flashlight array  will throw a steady light
and the red LED will be dark.

In the OFF position, both the flashlight array and the red LED will be
dark.

In the BLINK position, both the white LEDs and the red LED will flash
at the same rate.

That is, providing the LED looks like a low-valued resistor when it's
on and a high-valued resistor or an open circuit when it's off.  If it
doesn't, then the circuit won't work.

Earlier, I made the assumption that the flashing LED was dropping
about 1.2V with 165mA through it, but neglected to add in the drop for
the flashing circuitry, of which the pass element is in series with
the lamp.

The problem is, after having looked at several blinking red LEDs,
their voltage drop is all over the place and, not knowing which one
yours is, there's no way to tie down the value of R6.

If you have a voltmeter you can measure the voltage across the red LED
when it's on and then figure out the value of R6 like this:

          4.5V - Vled(on) - Vbe
    R5 = ----------------------
                 0.02A

That'll give you the value of R5 for 20mA into the base of Q1, which
should be enough to let the red LED flash and flash the rest of the
LEDs as well.

If you don't have a voltmeter, I'd guess at about 2V across the LED
when it's on, and about 0.7V across the base-to emitter junction of
Q1.  Then R5 would be:

          4.5V - 2V - 0.7V
    R5 = ------------------ = 90 ohms
               0.02A

91 ohms is a standard 5% part and should work well if the LED will
flash with 2V across it.

If it won't, try lowering the value of R6 until it does.

BTW, I have all the parts on hand and they're just pennies, so if you
email me with someplace to send them I'll just pop them in the mail
and save you the hassle of having to buy them.

Unless that creeps you out, of course. :-(

---
JF

I tried testing the voltage across the red LED.

Both leads came off. (Will replace with better wires.)
($3 special from Northern tools.

Will get back with you.

Andy

I made some jumpers to test things.

I hooked up the red LED wrong, and it went nite-nite.

The other 4 white LEDs still work.

Andy

 

[Mint]

On Nov 12, 4:33 am, John Fields <jfie...@austininstruments.com> wrote:

On Thu, 11 Nov 2010 11:17:38 -0800 (PST), Mint

chocolatemint77...@yahoo.com> wrote:
Resistors are brown-black-black-gold and red-black-black-gold.

Switch has 3 positions.    Red LED blinking. (other LEDs OFF) --- OFF
--- 4 Clear LEDs continually on(Red LED off)

OK

If, as you say, the battery + goes to all of the LEDs and there's no
switch in that lead, then the flashlight must be wired like this:

.       +------+------+------+------+------+
. | |A |A |A |A |A
. | [LED1] [LED2] [LED3] [LED4] [LED5]
. | | | | | |
.   |      +------+------+------+      |
. |+ | |
. [BAT] [10R] OFF [20R]
. |   | O |
.   |      +----------O | O------------+
.       |                /  |  \
.       |              ON   O   BLINK
.       |                   |
.       +-------------------+

If you rewire it like this:

.  +------+------+------+------+-------+-------+
.  |      |      |      |      |       |       |    
.  | |A |A |A |A     |       |A
.  | [LED1] [LED2] [LED3] [LED4]    |     [LED5]
.  | | | | |   |       |
.  |      |      |      |      |       |       |
.  |+ |R1 |R2    |R3 |R4   |R5     |R6
.[4V5] [51R] [51R]  [51R]  [51R]   [390R]  [??R]
. |   |      | | |  |       |
.  |      +------+------+------+       | ON    |
.  |                           |       |/  OFF |
.  |                           C       O  /    |
.  |                      2N4401 B--O--- O     |
.  |                       Q1  E   S1  O-------+
.  |                           |        \    
.  +---------------------------+         BLINK

in the ON position, the flashlight array  will throw a steady light
and the red LED will be dark.

In the OFF position, both the flashlight array and the red LED will be
dark.

In the BLINK position, both the white LEDs and the red LED will flash
at the same rate.

That is, providing the LED looks like a low-valued resistor when it's
on and a high-valued resistor or an open circuit when it's off.  If it
doesn't, then the circuit won't work.

Earlier, I made the assumption that the flashing LED was dropping
about 1.2V with 165mA through it, but neglected to add in the drop for
the flashing circuitry, of which the pass element is in series with
the lamp.

The problem is, after having looked at several blinking red LEDs,
their voltage drop is all over the place and, not knowing which one
yours is, there's no way to tie down the value of R6.

If you have a voltmeter you can measure the voltage across the red LED
when it's on and then figure out the value of R6 like this:

          4.5V - Vled(on) - Vbe
    R5 = ----------------------
                 0.02A

That'll give you the value of R5 for 20mA into the base of Q1, which
should be enough to let the red LED flash and flash the rest of the
LEDs as well.

If you don't have a voltmeter, I'd guess at about 2V across the LED
when it's on, and about 0.7V across the base-to emitter junction of
Q1.  Then R5 would be:

          4.5V - 2V - 0.7V
    R5 = ------------------ = 90 ohms
               0.02A

91 ohms is a standard 5% part and should work well if the LED will
flash with 2V across it.

If it won't, try lowering the value of R6 until it does.

BTW, I have all the parts on hand and they're just pennies, so if you
email me with someplace to send them I'll just pop them in the mail
and save you the hassle of having to buy them.

Unless that creeps you out, of course. :-(

---
JF

John, did you get my email?

Andy