Guest
Hi all,
I need to buy some transformers for a PIC project I'm making for
a train station model, but there's something that puzzles me.
Here are the data of two of them:
Secondary Current VA
12V 0.167A 2VA
12+12V 0.167+0.167A 8VA
Why in transformers with just one secondary the VA is V*A, while in
those with two secondaries it's just the half?
I mean, 12V*0.167A is 2W, same as 2VA.. but if I use the two 12V
secondaries in serie, to get a 24V secondary, multiplied for the
current of 0.167A I get 4W, i.e. half of the 8VA.
Where is my mistake?
When I don't need two secondaries, should I buy a transformer with
just one secondary for maximum power/money ratio?
Moreover, if the secondary gives 9V AC, after the diodes bridge and
capacitor, I should expect 11.3V, right? ( i.e. 9*1.414-(0.7*2) )
The capacitor is what accounts for the *1.414, and the diodes for the
the 2*0.7 voltage drop. But what should I expect under load, even
assuming a low impedance secondary? My fear is that the *1.414 will
be significantly lower.
I have The Art Of Electronics by Horowitz and Hill, but I didn't
really understand this issue well (and it's a simple, basic one!).
One last question.. is there any way to get, from one single AC source,
the effect of two secondaries? I know I could use two resistors, but
that would mean a lot of power loss. Any better ways?
Thanks,
Mike
I need to buy some transformers for a PIC project I'm making for
a train station model, but there's something that puzzles me.
Here are the data of two of them:
Secondary Current VA
12V 0.167A 2VA
12+12V 0.167+0.167A 8VA
Why in transformers with just one secondary the VA is V*A, while in
those with two secondaries it's just the half?
I mean, 12V*0.167A is 2W, same as 2VA.. but if I use the two 12V
secondaries in serie, to get a 24V secondary, multiplied for the
current of 0.167A I get 4W, i.e. half of the 8VA.
Where is my mistake?
When I don't need two secondaries, should I buy a transformer with
just one secondary for maximum power/money ratio?
Moreover, if the secondary gives 9V AC, after the diodes bridge and
capacitor, I should expect 11.3V, right? ( i.e. 9*1.414-(0.7*2) )
The capacitor is what accounts for the *1.414, and the diodes for the
the 2*0.7 voltage drop. But what should I expect under load, even
assuming a low impedance secondary? My fear is that the *1.414 will
be significantly lower.
I have The Art Of Electronics by Horowitz and Hill, but I didn't
really understand this issue well (and it's a simple, basic one!).
One last question.. is there any way to get, from one single AC source,
the effect of two secondaries? I know I could use two resistors, but
that would mean a lot of power loss. Any better ways?
Thanks,
Mike