Sum of array

V

VHDL_HELP

Guest
hi every body,
how calculate the sum of an array
for example , i have an array of 4 elements and i want the sum ,
please i wnt a solution ,please
thank you
 
On 13 Mar 2007 04:15:13 -0700, "VHDL_HELP" <abaidik@gmail.com> wrote:

hi every body,
how calculate the sum of an array
for example , i have an array of 4 elements and i want the sum ,
please i wnt a solution ,please
thank you
Click to expand...
for example,

sum := a(1) + a(2) + a(3) + a(4);

Generalising this to arrays of other sizes is left as a trivial
exercise for the student.
--
Jonathan Bromley, Consultant

DOULOS - Developing Design Know-how
VHDL * Verilog * SystemC * e * Perl * Tcl/Tk * Project Services

Doulos Ltd., 22 Market Place, Ringwood, BH24 1AW, UK
jonathan.bromley@MYCOMPANY.com
http://www.MYCOMPANY.com

The contents of this message may contain personal views which
are not the views of Doulos Ltd., unless specifically stated.
 
On 13 mar, 13:05, Jonathan Bromley <jonathan.brom...@MYCOMPANY.com>
wrote:
On 13 Mar 2007 04:15:13 -0700, "VHDL_HELP" <abai...@gmail.com> wrote:

hi every body,
how calculate the sum of an array
for example , i have an array of 4 elements and i want the sum ,
please i wnt a solution ,please
thank you

for example,

sum := a(1) + a(2) + a(3) + a(4);

Generalising this to arrays of other sizes is left as a trivial
exercise for the student.
--
Jonathan Bromley, Consultant

DOULOS - Developing Design Know-how
VHDL * Verilog * SystemC * e * Perl * Tcl/Tk * Project Services

Doulos Ltd., 22 Market Place, Ringwood, BH24 1AW, UK
jonathan.brom...@MYCOMPANY.comhttp://www.MYCOMPANY.com

The contents of this message may contain personal views which
are not the views of Doulos Ltd., unless specifically stated.
Click to expand...
this is my vhdl program , it is corrct on syntax but not
synthetisable

library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.STD_LOGIC_ARITH.ALL;
use IEEE.STD_LOGIC_UNSIGNED.ALL;

entity somme is
Port ( clk : in STD_LOGIC;
din : in STD_LOGIC_VECTOR (3 downto 0);
taille : in STD_LOGIC_VECTOR (2 downto 0);

dout : out STD_LOGIC_VECTOR (3 downto 0)
);
end somme;

architecture Behavioral of somme is
type tab is array(3 downto 0) of STD_LOGIC_VECTOR(3 DOWNTO 0);
signal s : tab;
begin
process(clk)
begin
if clk'event and clk ='1' then
s(conv_integer(taille)) <= din;
end if;
end process;
dout <= s(0) + s(1) + s(2) + s(3);
end Behavioral;
 
VHDL_HELP schrieb:


What was the problem for synthesis?

i dont find my result , the process cuts and i dont find my result
Click to expand...
What does it do?

Did you simulate before synthesis? Overflow will occur easily using
these bitwidths.

Ralf
 
On 13 Mar 2007 08:56:48 -0700, "VHDL_HELP"
<abaidik@gmail.com> wrote:


this is my vhdl program , it is corrct on syntax but not
synthetisable
Click to expand...
It looks synthesisable to me.
What was the problem for synthesis?

--
Jonathan Bromley, Consultant

DOULOS - Developing Design Know-how
VHDL * Verilog * SystemC * e * Perl * Tcl/Tk * Project Services

Doulos Ltd., 22 Market Place, Ringwood, BH24 1AW, UK
jonathan.bromley@MYCOMPANY.com
http://www.MYCOMPANY.com

The contents of this message may contain personal views which
are not the views of Doulos Ltd., unless specifically stated.
 
On 13 mar, 17:04, Jonathan Bromley <jonathan.brom...@MYCOMPANY.com>
wrote:
On 13 Mar 2007 08:56:48 -0700, "VHDL_HELP"

abai...@gmail.com> wrote:
this is my vhdl program , it is corrct on syntax but not
synthetisable

It looks synthesisable to me.
What was the problem for synthesis?

--
Jonathan Bromley, Consultant

DOULOS - Developing Design Know-how
VHDL * Verilog * SystemC * e * Perl * Tcl/Tk * Project Services

Doulos Ltd., 22 Market Place, Ringwood, BH24 1AW, UK
jonathan.brom...@MYCOMPANY.comhttp://www.MYCOMPANY.com

The contents of this message may contain personal views which
are not the views of Doulos Ltd., unless specifically stated.
Click to expand...
i dont find my result , the process cuts and i dont find my result
 
On 13 Mar 2007 09:08:18 -0700, "VHDL_HELP"
<abaidik@gmail.com> wrote:

It looks synthesisable to me.
What was the problem for synthesis?

i dont find my result , the process cuts and i dont find my result
Click to expand...
Works for me.... one 2-to-4 decoder, 16 flip-flops, three 4-bit
full adders. Seems like you have a problem with usage of
your synthesis tool. It's probably best for you to find a local
expert to get started with your tools in your environment.
--
Jonathan Bromley, Consultant

DOULOS - Developing Design Know-how
VHDL * Verilog * SystemC * e * Perl * Tcl/Tk * Project Services

Doulos Ltd., 22 Market Place, Ringwood, BH24 1AW, UK
jonathan.bromley@MYCOMPANY.com
http://www.MYCOMPANY.com

The contents of this message may contain personal views which
are not the views of Doulos Ltd., unless specifically stated.
 
On 13 mar, 16:58, Ralf Hildebrandt <Ralf-Hildebra...@gmx.de> wrote:
VHDL_HELP schrieb:

What was the problem for synthesis?
i dont find my result , the process cuts and i dont find my result

What does it do?

Did you simulate before synthesis? Overflow will occur easily using
these bitwidths.

Ralf
Click to expand...
i have as result for dout : 4'hX as a result ===> it is a result for
the simulation
 
On 13 mar, 17:20, Jonathan Bromley <jonathan.brom...@MYCOMPANY.com>
wrote:
On 13 Mar 2007 09:08:18 -0700, "VHDL_HELP"

abai...@gmail.com> wrote:
It looks synthesisable to me.
What was the problem for synthesis?
i dont find my result , the process cuts and i dont find my result

Works for me.... one 2-to-4 decoder, 16 flip-flops, three 4-bit
full adders. Seems like you have a problem with usage of
your synthesis tool. It's probably best for you to find a local
expert to get started with your tools in your environment.
--
Jonathan Bromley, Consultant

DOULOS - Developing Design Know-how
VHDL * Verilog * SystemC * e * Perl * Tcl/Tk * Project Services

Doulos Ltd., 22 Market Place, Ringwood, BH24 1AW, UK
jonathan.brom...@MYCOMPANY.comhttp://www.MYCOMPANY.com

The contents of this message may contain personal views which
are not the views of Doulos Ltd., unless specifically stated.
Click to expand...
with this program , i have the same problem into simulation , please
help me , i havent someone near to me that can give me help

library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.STD_LOGIC_ARITH.ALL;
use IEEE.STD_LOGIC_UNSIGNED.ALL;

entity somme is
Port ( clk : in STD_LOGIC;
reset : in std_logic;
clk_out : out std_logic;
din : in STD_LOGIC_VECTOR (3 downto 0);
taille : in STD_LOGIC_VECTOR (2 downto 0);
dout : out STD_LOGIC_VECTOR (3 downto 0)
);
end somme;

architecture Behavioral of somme is
type tab is array(3 downto 0) of STD_LOGIC_VECTOR(3 DOWNTO 0);
signal s : tab;
begin
process
begin
SEQ_LOOP:loop
wait until clk'event and clk ='1';-- Au 1er front montant
exit SEQ_LOOP when reset = '1';-- on met le front montant
clk_out <= '1';-- celui d'horloge de sortie
wait until clk'event and clk ='1';-- Au 2eme front montant
exit SEQ_LOOP when reset = '1';-- on va lire
s(0) <= din; -- le 1er element
wait until clk'event and clk ='1';-- Au 2eme front montant
exit SEQ_LOOP when reset = '1';-- on met le front descendant
clk_out <= '0'; -- de sortie
wait until clk'event and clk ='1';-- Au 3eme front montant
exit SEQ_LOOP when reset = '1';-- on va lire
s(1) <= din; -- le 2eme element
wait until clk'event and clk ='1';-- Au 4eme front montant
exit SEQ_LOOP when reset = '1';-- on met le front montant
clk_out <= '1';-- celui d'horloge de sortie
wait until clk'event and clk ='1';-- Au 4eme front montant
exit SEQ_LOOP when reset = '1';-- on va lire
s(2) <= din; -- le 3eme element
wait until clk'event and clk ='1';-- Au 5eme front montant
exit SEQ_LOOP when reset = '1';-- on met le front descendant
clk_out <= '0'; -- de sortie
wait until clk'event and clk ='1';-- Au 6eme front montant
exit SEQ_LOOP when reset = '1';-- on va lire
s(3) <= din; -- le 4eme element
dout <= s(0) + s(1) + s(2) + s(3);
end loop;
end process;

end Behavioral;
 
VHDL_HELP schrieb:


i have as result for dout : 4'hX as a result ===> it is a result for
the simulation
Click to expand...
Behavioral or post-synthesis simulation?

If there is X at the result, check the values of the array s, then check
the value of the selector taille, then check the value of din, then
check the value of the clock clk. Are there any other X?

=> Your problem is not the question if this description is synthesizable
or not but the question where the X comes from. I guess there is
something wrong with your testbench for this circuit.

Ralf
 
On 13 mar, 20:43, Ralf Hildebrandt <Ralf-Hildebra...@gmx.de> wrote:
VHDL_HELP schrieb:

i have as result for dout : 4'hX as a result ===> it is a result for
the simulation

Behavioral or post-synthesis simulation?

If there is X at the result, check the values of the array s, then check
the value of the selector taille, then check the value of din, then
check the value of the clock clk. Are there any other X?

=> Your problem is not the question if this description is synthesizable
or not but the question where the X comes from. I guess there is
something wrong with your testbench for this circuit.

Ralf
Click to expand...
hi every body ,
i want to say thank you for all of u and this program can do the sum
that i want
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.STD_LOGIC_ARITH.ALL;
use IEEE.STD_LOGIC_UNSIGNED.ALL;

entity som is
Port ( clk : in STD_LOGIC;
reset : in STD_LOGIC;
en : in STD_LOGIC_VECTOR (2 downto 0);
clk_out : out STD_LOGIC;
so : out STD_LOGIC_VECTOR (3 downto 0);
sor : out STD_LOGIC_VECTOR (3 downto 0));
end som;

architecture Behavioral of som is
TYPE TAB IS ARRAY(3 DOWNTO 0) OF STD_LOGIC_VECTOR(2 DOWNTO 0);
signal t:TAB;
SIGNAL s:STD_LOGIC_VECTOR (3 downto 0):="0000";
begin
process
begin
seq:loop
wait until clk'event and clk = '1';
exit seq when reset ='1';
clk_out <= '1';
t(0) <= en;

wait until clk'event and clk = '1';
exit seq when reset ='1';
clk_out <= '0';
t(1) <= en;

wait until clk'event and clk = '1';
exit seq when reset ='1';
clk_out <= '1';
t(2) <= en;

wait until clk'event and clk = '1';
exit seq when reset ='1';
clk_out <= '0';
t(3) <= en;
----- Mettre les éléments de tableau en sortie
wait until clk'event and clk = '1';
exit seq when reset ='1';
clk_out <= '1';

wait until clk'event and clk = '1';
exit seq when reset ='1';
clk_out <= '0';

wait until clk'event and clk = '1';
exit seq when reset ='1';
clk_out <= '1';

wait until clk'event and clk = '1';
exit seq when reset ='1';
clk_out <= '0';

end loop;
if reset = '1' then
clk_out <= '0';
s <= '0' & t(0) + t(1) + t(2) + t(3);
so <= s;
end if;
end process;
end Behavioral;

--- thank you again
 
You must log in or register to reply here.

Welcome to EDABoard.com

Sponsor

Back
Top