W
Winston
Guest
I'm a noob trying to get a visceral grasp of the science.
Background:
For a perfect free-field site, sound power and sound pressure
are said to be related:
Lw = Lp + 10 * log10(2*pi*r^2)
www.me.mtu.edu/courses/meem4704/lab/lab4homework.pdf
Where:
Lp = Sound pressure in dB. 0 dB = 20 micro Pascals
Lw = Sound power in dB. 0 dB = 1 pico watt
r = Distance from device to microphone in meters
Question:
Does this mean that if I could place my microphone at a
distance of 398.94 mm from the device under test that
my sound pressure reading will be within 0.0001 dB of
my sound power reading even though 'sound pressure' dBs
are different from 'sound power' dBs?
Thanks!
--Winston
Background:
For a perfect free-field site, sound power and sound pressure
are said to be related:
Lw = Lp + 10 * log10(2*pi*r^2)
www.me.mtu.edu/courses/meem4704/lab/lab4homework.pdf
Where:
Lp = Sound pressure in dB. 0 dB = 20 micro Pascals
Lw = Sound power in dB. 0 dB = 1 pico watt
r = Distance from device to microphone in meters
Question:
Does this mean that if I could place my microphone at a
distance of 398.94 mm from the device under test that
my sound pressure reading will be within 0.0001 dB of
my sound power reading even though 'sound pressure' dBs
are different from 'sound power' dBs?
Thanks!
--Winston