Question about electrons and voltage

G

GreenXenon

Guest
Hi:

An electron has charge of 1.602 × 10^-19 coulombs. Does this mean that
the potential difference -- when comparing the presence to the absence
of -- 1 electron would be 1.602 × 10^-19 volts?


Thanks
 
On Tue, 12 May 2009 07:59:31 -0700 (PDT), GreenXenon
<glucegen1x@gmail.com> wrote:

Hi:

An electron has charge of 1.602 × 10^-19 coulombs. Does this mean that
the potential difference -- when comparing the presence to the absence
of -- 1 electron would be 1.602 × 10^-19 volts?


Thanks
Charge is not voltage; they have different units.

Only macroscopic objects, like chunks of metal, have voltages.

If you had two parallel pizza plates floating in space, electrically
neutral, and yanked an electron out of one and stuck it to the other,
then you'd have a voltage between the plates.

The voltage between those pizza plates would be

V = Q / C

where V is in volts
Q is the charge you moved
C is the capacitance between plates.

For, say, 20 pF capacitance between the floating pizza plates, for
every electron you drag across, the voltage between the plates
increases by 8 nanovolts.

If you connect a wire between the charged plates, all those electrons
zoom back home along the wire and the plates again become relatively
neutral, no voltage. The zooming-back flow is "current."

Interesting: One electron can make a lot of volts if it's used to
charge a very small object. I wonder if the concept "capacitance of an
electron" has any meaning. If it did, the electron itself could be
said to have a voltage. A *big* voltage!

John
 
On Tue, 12 May 2009 16:00:28 -0700 (PDT), mrdarrett@gmail.com wrote:

On May 12, 3:00 pm, GreenXenon <glucege...@gmail.com> wrote:
On May 12, 8:48 am, John Larkin



jjlar...@highNOTlandTHIStechnologyPART.com> wrote:
On Tue, 12 May 2009 07:59:31 -0700 (PDT), GreenXenon

glucege...@gmail.com> wrote:
Hi:

An electron has charge of 1.602 × 10^-19 coulombs. Does this mean that
the potential difference -- when comparing the presence to the absence
of -- 1 electron would be 1.602 × 10^-19 volts?

Thanks

Charge is not voltage; they have different units.

Only macroscopic objects, like chunks of metal, have voltages.

If you had two parallel pizza plates floating in space, electrically
neutral, and yanked an electron out of one and stuck it to the other,
then you'd have a voltage between the plates.

The voltage between those pizza plates would be

V = Q / C

where V is in volts
Q is the charge you moved
C is the capacitance between plates.

For, say, 20 pF capacitance between the floating pizza plates, for
every electron you drag across, the voltage between the plates
increases by 8 nanovolts.

If you connect a wire between the charged plates, all those electrons
zoom back home along the wire and the plates again become relatively
neutral, no voltage. The zooming-back flow is "current."

Interesting: One electron can make a lot of volts if it's used to
charge a very small object. I wonder if the concept "capacitance of an
electron" has any meaning. If it did, the electron itself could be
said to have a voltage. A *big* voltage!

John

How many volts-per-meter is the electric field of one 1 Hz photon?


How many inches do you weigh?
A photon does have a traveling electric field, and that field
intensity could be measured in v/m, although it is spatially and
temporally complex. Not a problem I'd care to formulate.

The energy that photon is packing is 6.6e-34 joules. And the photon is
big, would barely fit between the earth and the moon. Energy density
looks fairly low.

John
 
On May 12, 8:48 am, John Larkin
<jjlar...@highNOTlandTHIStechnologyPART.com> wrote:
On Tue, 12 May 2009 07:59:31 -0700 (PDT), GreenXenon

glucege...@gmail.com> wrote:
Hi:

An electron has charge of 1.602 × 10^-19 coulombs. Does this mean that
the potential difference -- when comparing the presence to the absence
of -- 1 electron would be 1.602 × 10^-19 volts?

Thanks

Charge is not voltage; they have different units.

Only macroscopic objects, like chunks of metal, have voltages.

If you had two parallel pizza plates floating in space, electrically
neutral, and yanked an electron out of one and stuck it to the other,
then you'd have a voltage between the plates.

The voltage between those pizza plates would be

V = Q / C

where V is in volts
Q is the charge you moved
C is the capacitance between plates.

For, say, 20 pF capacitance between the floating pizza plates, for
every electron you drag across, the voltage between the plates
increases by 8 nanovolts.

If you connect a wire between the charged plates, all those electrons
zoom back home along the wire and the plates again become relatively
neutral, no voltage. The zooming-back flow is "current."

Interesting: One electron can make a lot of volts if it's used to
charge a very small object. I wonder if the concept "capacitance of an
electron" has any meaning. If it did, the electron itself could be
said to have a voltage. A *big* voltage!

John
How many volts-per-meter is the electric field of one 1 Hz photon?
 
On May 12, 3:00 pm, GreenXenon <glucege...@gmail.com> wrote:
On May 12, 8:48 am, John Larkin



jjlar...@highNOTlandTHIStechnologyPART.com> wrote:
On Tue, 12 May 2009 07:59:31 -0700 (PDT), GreenXenon

glucege...@gmail.com> wrote:
Hi:

An electron has charge of 1.602 × 10^-19 coulombs. Does this mean that
the potential difference -- when comparing the presence to the absence
of -- 1 electron would be 1.602 × 10^-19 volts?

Thanks

Charge is not voltage; they have different units.

Only macroscopic objects, like chunks of metal, have voltages.

If you had two parallel pizza plates floating in space, electrically
neutral, and yanked an electron out of one and stuck it to the other,
then you'd have a voltage between the plates.

The voltage between those pizza plates would be

V = Q / C

where V is in volts
Q is the charge you moved
C is the capacitance between plates.

For, say, 20 pF capacitance between the floating pizza plates, for
every electron you drag across, the voltage between the plates
increases by 8 nanovolts.

If you connect a wire between the charged plates, all those electrons
zoom back home along the wire and the plates again become relatively
neutral, no voltage. The zooming-back flow is "current."

Interesting: One electron can make a lot of volts if it's used to
charge a very small object. I wonder if the concept "capacitance of an
electron" has any meaning. If it did, the electron itself could be
said to have a voltage. A *big* voltage!

John

How many volts-per-meter is the electric field of one 1 Hz photon?

How many inches do you weigh?
 
On Tue, 12 May 2009 17:12:07 -0700, GreenXenon wrote:

http://heasarc.gsfc.nasa.gov/cgi-bin/Tools/energyconv/energyConv.pl

I plugged 6.6e-34 joules into the above website and got a measure of
4.1194e-15 electron-volt. Does this mean that the electric field of
one 1 Hz photon has a strength of 4.1194e-15 volt per meter?
No. It means that it has an energy of 4.1194e-15 electron-Volts, i.e. the
same energy as would be required to move a single electron up a 4.1194e-15
Volt potential gap, or the same energy as would be gained by an electron
accelerating down a 4.1194e-15 Volt gap.

One Joule is one Coulomb-Volt (one Volt is defined as one Joule per
Coulomb). An electron-Volt is the same concept but for the charge on a
single electron rather than a charge of one Coulomb. Distance units don't
come into it.
 
On May 12, 4:11 pm, John Larkin
<jjlar...@highNOTlandTHIStechnologyPART.com> wrote:
On Tue, 12 May 2009 16:00:28 -0700 (PDT), mrdarr...@gmail.com wrote:
On May 12, 3:00 pm, GreenXenon <glucege...@gmail.com> wrote:
On May 12, 8:48 am, John Larkin

jjlar...@highNOTlandTHIStechnologyPART.com> wrote:
On Tue, 12 May 2009 07:59:31 -0700 (PDT), GreenXenon

glucege...@gmail.com> wrote:
Hi:

An electron has charge of 1.602 × 10^-19 coulombs. Does this mean that
the potential difference -- when comparing the presence to the absence
of -- 1 electron would be 1.602 × 10^-19 volts?

Thanks

Charge is not voltage; they have different units.

Only macroscopic objects, like chunks of metal, have voltages.

If you had two parallel pizza plates floating in space, electrically
neutral, and yanked an electron out of one and stuck it to the other,
then you'd have a voltage between the plates.

The voltage between those pizza plates would be

V = Q / C

where V is in volts
Q is the charge you moved
C is the capacitance between plates.

For, say, 20 pF capacitance between the floating pizza plates, for
every electron you drag across, the voltage between the plates
increases by 8 nanovolts.

If you connect a wire between the charged plates, all those electrons
zoom back home along the wire and the plates again become relatively
neutral, no voltage. The zooming-back flow is "current."

Interesting: One electron can make a lot of volts if it's used to
charge a very small object. I wonder if the concept "capacitance of an
electron" has any meaning. If it did, the electron itself could be
said to have a voltage. A *big* voltage!

John

How many volts-per-meter is the electric field of one 1 Hz photon?

How many inches do you weigh?

A photon does have a traveling electric field, and that field
intensity could be measured in v/m, although it is spatially and
temporally complex. Not a problem I'd care to formulate.

The energy that photon is packing is 6.6e-34 joules. And the photon is
big, would barely fit between the earth and the moon. Energy density
looks fairly low.

John
http://heasarc.gsfc.nasa.gov/cgi-bin/Tools/energyconv/energyConv.pl

I plugged 6.6e-34 joules into the above website and got a measure of
4.1194e-15 electron-volt. Does this mean that the electric field of
one 1 Hz photon has a strength of 4.1194e-15 volt per meter?
 
On Wed, 13 May 2009 02:53:20 +0100, Nobody <nobody@nowhere.com> wrote:

On Tue, 12 May 2009 17:12:07 -0700, GreenXenon wrote:

http://heasarc.gsfc.nasa.gov/cgi-bin/Tools/energyconv/energyConv.pl

I plugged 6.6e-34 joules into the above website and got a measure of
4.1194e-15 electron-volt. Does this mean that the electric field of
one 1 Hz photon has a strength of 4.1194e-15 volt per meter?

No. It means that it has an energy of 4.1194e-15 electron-Volts, i.e. the
same energy as would be required to move a single electron up a 4.1194e-15
Volt potential gap, or the same energy as would be gained by an electron
accelerating down a 4.1194e-15 Volt gap.

One Joule is one Coulomb-Volt (one Volt is defined as one Joule per
Coulomb). An electron-Volt is the same concept but for the charge on a
single electron rather than a charge of one Coulomb. Distance units don't
come into it.
A way to see that distance doesn't come into it without just accepting
the statement as fact from someone is to imagine two plates separated
by some arbitrary distance of vacuum -- call it one meter -- and with
a voltage potential across them -- call it one volt. Then imagine
releasing an electron from the surface of the plate with the more
negative potential. The electron accelerates over the distance and
eventually strikes the positive plate. At the time of impact, there
is 1/2 m v^2 kinetic energy (or 1 eV, here) to disperse. Now imagine
separating the plates by 10 meters, keeping the 1 volt potential
difference. The acceleration will be ten times slower, but the
distance is 10 times further, so the final velocity is the same in
both cases. The distance doesn't matter, in the end.

(If there were a Coulomb's worth of electrons involved, the sum of
their kinetic energies would be a Joule if accelerated by a 1 volt
potential difference, regardless of distance.)

Jon
 

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