C
CoogarXR
Guest
Hello,
I am desigining a PC-based DVR security system. The cameras run at 8.5vdc @
700ma. I would like to run 2 of them off of a drive controller lead from the
ATX power supply running the PC. Here is my math, feel free to double-check it,
as I am just getting back into electronics, and I haven't used my electrical
math skills in quite some time![Smile :) :)](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
........
V / I = R (Ohms law)
Voltage Difference 12v -8.5 = 3.5v Divided by .7a (700ma) = 5 Ohm
700ma x 4.5v = 2.45w
........
Now, provided I did my math correctly, could I just use 2, 10ohm 10watt
resistors in parallel? I only can get 1ohm or 10 ohm in that high of wattage.
Does this all sound right? Thanks!
CoogarXR
I am desigining a PC-based DVR security system. The cameras run at 8.5vdc @
700ma. I would like to run 2 of them off of a drive controller lead from the
ATX power supply running the PC. Here is my math, feel free to double-check it,
as I am just getting back into electronics, and I haven't used my electrical
math skills in quite some time
........
V / I = R (Ohms law)
Voltage Difference 12v -8.5 = 3.5v Divided by .7a (700ma) = 5 Ohm
700ma x 4.5v = 2.45w
........
Now, provided I did my math correctly, could I just use 2, 10ohm 10watt
resistors in parallel? I only can get 1ohm or 10 ohm in that high of wattage.
Does this all sound right? Thanks!
CoogarXR