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The circuit is useable with a 12V supply, but could destroy the gatehttp://chrispol.ath.cx:8080/switch.jpg
would this be the proper circuit to optically source current to a heavy
load?
Thanks
Chris wrote:
http://chrispol.ath.cx:8080/switch.jpg
would this be the proper circuit to optically source current to a
heavy load?
Thanks
The circuit is useable with a 12V supply, but could destroy the gate
of the FET if the supply was 15V or more.
Perhaps a change so the gate drive cannot be moer than 10V would help.
Make sure that you use a good heatsink on the FET.
Be advised that the power ratings of FETS cannot be achieved unless
one cools the die to -55C and uses a drive under a microsecond per
minute or longer.
And in some cases, not even then.
I assume the "GND" to the left of the 4N36 is different to the "GND"http://chrispol.ath.cx:8080/switch.jpg
would this be the proper circuit to optically source current to a heavy
load?
Thanks
On Fri, 29 Jul 2005 13:55:33 -0400, Chris <chrispol@videotron.ca
wrote:
http://chrispol.ath.cx:8080/switch.jpg
would this be the proper circuit to optically source current to a heavy
load?
Thanks
I assume the "GND" to the left of the 4N36 is different to the "GND"
to the right of it, because otherwise you don't need an optocoupler.
On a side note, I recommend you to draw schematics always placing the
higher voltages at the top.
The most negative voltage is at the bottom, which is acceptable.
Since you indicate a paltry 1 amp or less,a 5V drive would behow would i limit the voltage? the amperage load i need is < 1amp
Thanks
Chris
Robert Baer wrote:
Chris wrote:
http://chrispol.ath.cx:8080/switch.jpg
would this be the proper circuit to optically source current to a
heavy load?
Thanks
The circuit is useable with a 12V supply, but could destroy the gate
of the FET if the supply was 15V or more.
Perhaps a change so the gate drive cannot be moer than 10V would help.
Make sure that you use a good heatsink on the FET.
Be advised that the power ratings of FETS cannot be achieved unless
one cools the die to -55C and uses a drive under a microsecond per
minute or longer.
And in some cases, not even then.
Use a zener and a dropping resistor.
?Mochuelo wrote:
On Fri, 29 Jul 2005 13:55:33 -0400, Chris <chrispol@videotron.ca
wrote:
http://chrispol.ath.cx:8080/switch.jpg
would this be the proper circuit to optically source current to a heavy
load?
Thanks
I assume the "GND" to the left of the 4N36 is different to the "GND"
to the right of it, because otherwise you don't need an optocoupler.
On a side note, I recommend you to draw schematics always placing the
higher voltages at the top.
The most negative voltage is at the bottom, which is acceptable.
On Sat, 30 Jul 2005 07:49:13 GMT, Robert Baer
robertbaer@earthlink.net> wrote:
Mochuelo wrote:
On Fri, 29 Jul 2005 13:55:33 -0400, Chris <chrispol@videotron.ca
wrote:
http://chrispol.ath.cx:8080/switch.jpg
would this be the proper circuit to optically source current to a heavy
load?
Thanks
I assume the "GND" to the left of the 4N36 is different to the "GND"
to the right of it, because otherwise you don't need an optocoupler.
On a side note, I recommend you to draw schematics always placing the
higher voltages at the top.
The most negative voltage is at the bottom, which is acceptable.
?
At the bottom there is "+12V", and at the top there is "GND", so not
good.
Besides, it is not a typo. It can't be -12 V, because the channel
inside the PMOS would never turn on, the parasitic diode across it
would always conduct, and the BJT inside the optocoupler would be
wrongly connected.
I stand corrected.