Prove That's Impossible To Increase Surface Area of Fluoresc

[BretCahill]

I'm almost certain this proof has been done before in one of those gradient
divergence and curl fields classes.

To start the I'ld make some simplyfing assumptions. Reduce it to a 2d problem,
the tubes are square and the light only exits the glass surface in a normal
direction.

No matter how you arrange the squares or any reflective surfaces . . .

What they need is a one way mirrored glass surface. Just as CO2 keeps the IR
light in the biosphere this surface would keep the white light from reentering
the tube.


Bret

 

[Harry Conover]

bretcahill@aol.com (BretCahill) wrote in message news:<20030928123925.00367.00000291@mb-m07.aol.com>...

I'm almost certain this proof has been done before in one of those gradient
divergence and curl fields classes.

To start the I'ld make some simplyfing assumptions. Reduce it to a 2d problem,
the tubes are square and the light only exits the glass surface in a normal
direction.

No matter how you arrange the squares or any reflective surfaces . . .

What they need is a one way mirrored glass surface. Just as CO2 keeps the IR
light in the biosphere this surface would keep the white light from reentering
the tube.


Bret

Bret, in actuality (real physics) there is no such thing as a one way
mirror.

Partially silvered mirrors simply appear that way as a result of the
light attenuation of the images passing though the partially mirrored
surface making these images appear to vanish on the side of the mirror
while highlighting images on the side more brightly illuminated.

What you appear to need for your purposes is a light rectifier, which
in reality doesn't exist, although there are some liquid crystal light
switches that can come pretty close.

Harry C.

 

[Andre]

hhc314@yahoo.com (Harry Conover) wrote in message news:<7ce4e226.0309281836.587cf9f3@posting.google.com>...

bretcahill@aol.com (BretCahill) wrote in message news:<20030928123925.00367.00000291@mb-m07.aol.com>...
I'm almost certain this proof has been done before in one of those gradient
divergence and curl fields classes.

To start the I'ld make some simplyfing assumptions. Reduce it to a 2d problem,
the tubes are square and the light only exits the glass surface in a normal
direction.

No matter how you arrange the squares or any reflective surfaces . . .

What they need is a one way mirrored glass surface. Just as CO2 keeps the IR
light in the biosphere this surface would keep the white light from reentering
the tube.


Bret

Bret, in actuality (real physics) there is no such thing as a one way
mirror.

Partially silvered mirrors simply appear that way as a result of the
light attenuation of the images passing though the partially mirrored
surface making these images appear to vanish on the side of the mirror
while highlighting images on the side more brightly illuminated.

What you appear to need for your purposes is a light rectifier, which
in reality doesn't exist, although there are some liquid crystal light
switches that can come pretty close.

What would one use a "light rectifier" for if it did exist ? Lasers ,
probably (and the optical equivalent of a C/W multiplier) ?

-A

Harry C.

 

[BretCahill]

Apparently fiber optics can be used to
make all the light in a folded or spiraled
fluorescent tube available, although at a
price.

This only proves the exact opposite of
what I set out to prove.

In any event there is more to the low
intensity of fluorescent light problem than
large surface area. Large volume is the
real problem.


Bret Cahill

 

[Ian Stirling]

Andre <testing_h@yahoo.com> wrote:

hhc314@yahoo.com (Harry Conover) wrote in message news:<7ce4e226.0309281836.587cf9f3@posting.google.com>...
bretcahill@aol.com (BretCahill) wrote in message news:<20030928123925.00367.00000291@mb-m07.aol.com>...
I'm almost certain this proof has been done before in one of those gradient
divergence and curl fields classes.

To start the I'ld make some simplyfing assumptions. Reduce it to a 2d problem,
the tubes are square and the light only exits the glass surface in a normal
direction.
snip
Bret, in actuality (real physics) there is no such thing as a one way
mirror.

Partially silvered mirrors simply appear that way as a result of the
light attenuation of the images passing though the partially mirrored
surface making these images appear to vanish on the side of the mirror
while highlighting images on the side more brightly illuminated.

What you appear to need for your purposes is a light rectifier, which
in reality doesn't exist, although there are some liquid crystal light
switches that can come pretty close.

What would one use a "light rectifier" for if it did exist ? Lasers ,
probably (and the optical equivalent of a C/W multiplier) ?

Nothing so trivial.

Creating free energy.
Take a sealed box, make small box out of light rectifier.
Place this inside the sealed box.
Thermal radiation gets into the sealed box, but not out.
It gets hotter, and you can run a heat engine off it, and heat the outside
box without external energy input.


--
http://inquisitor.i.am/ | mailto:inquisitor@i.am | Ian Stirling.
---------------------------+-------------------------+--------------------------
'Where subtlety fails, we must simply make do with cream pies' -- David Brin

 

[Michael]

Nothing so trivial.

Creating free energy.
Take a sealed box, make small box out of light rectifier.
Place this inside the sealed box.
Thermal radiation gets into the sealed box, but not out.
It gets hotter, and you can run a heat engine off it, and heat the outside
box without external energy input.

Hmmmmm
If heat gets into but not out of the little box then where does the
heat come from that heats the bigger box?

 

[Sir Charles W. Shults III]

"Michael" <michael@clift.com.au> wrote in message
news:ec96e13a.0310010208.21aa6c6@posting.google.com...

Nothing so trivial.

Creating free energy.
Take a sealed box, make small box out of light rectifier.
Place this inside the sealed box.
Thermal radiation gets into the sealed box, but not out.
It gets hotter, and you can run a heat engine off it, and heat the outside
box without external energy input.

Hmmmmm
If heat gets into but not out of the little box then where does the
heat come from that heats the bigger box?

The energy is the key. Energy is being transported in the form of photons.
High or low energy is immaterial. The energy in one photon might be later
transported as two lower energy photons. As long as ANY photon can get through
a "light rectifier", it will have the capability of providing heat.
What a light rectifier implies is that anything with any temperature or
energy differential at all can operate an engine for free. However, this
violates thermodynamics. Therefore, no light rectifier can exist. QED.

Cheers!

Chip Shults
My robotics, space and CGI web page - http://home.cfl.rr.com/aichip