problem with simulating a program

[DG]

Hi,

First I apalogize because my question is probably stupid but I am trying to
learn VHDL by writing very basic programs but I have a problem with the
follwing one

I want to simulate the following peace of code (I have no problem with that
code) :
------------------------
Library ieee;
Use ieee.std_logic_1164.all;
Use ieee.numeric_std.all;
Use ieee.std_logic_unsigned.all;

entity CMP4BITS is
PORT (
CLOCK : in std_logic;
Q : inout std_logic_vector(3 downto 0));
end CMP4BITS;

architecture DESCRIPTION of CMP4BITS is
begin
process (CLOCK)
begin
if (CLOCK ='1' and CLOCK'event) then
Q <= Q + 1;
end if;
end process;
end DESCRIPTION;
------------------------

My problem is with the program in charge to launch the simulation of the
code above; which is:
------------------------
Library ieee;
Use ieee.std_logic_1164.all;

ENTITY test_cmpt IS
END test_cmpt;

ARCHITECTURE behavior OF test_cmpt IS
COMPONENT cmp4bits
PORT (CLOCK : in std_logic;
Q : inout std_logic_vector(3 downto 0));
END COMPONENT;

SIGNAL CLOCK : std_logic;
SIGNAL Q : std_logic_vector(3 downto 0);

BEGIN
DUT: cmp4bits PORT MAP (CLOCK, Q);

stimulus: PROCESS
BEGIN
CLOCK <= '0';
wait for 100 ns;

CLOCK <= '1';
wait for 100 ns;
END PROCESS;
END behavior;
------------------------

Actually the problem is when I launch the simulation all the values of Q are
X (which means undetermined) and after having executed "Q <= Q + 1", Q is
always undetermined and so son. I guess one solution would be to initialize
Q before the execution of "cmp4bits", but I don't know how... Obviously I
tried to put an "Q <= "0000" before "CLOCK <= '0'" but it had no effects.

If someone had an idea, do not hesitate to suggest .

Regards

 

[MM]

There are many ways to solve your problem. Any particular reason why Q
should be bidirectional? Anyways, here is the code that works (as you can
see I corrected the module, not the test bench):

Library ieee;
Use ieee.std_logic_1164.all;
--Use ieee.numeric_std.all;
Use ieee.std_logic_unsigned.all;

entity CMP4BITS is
PORT (
CLOCK : in std_logic;
Q : inout std_logic_vector(3 downto 0));
end CMP4BITS;

architecture DESCRIPTION of CMP4BITS is
begin

process (CLOCK)
variable cnt : std_logic_vector(3 downto 0):=X"0"; -- the
initialization happens here
begin
if (CLOCK ='1' and CLOCK'event) then
cnt := cnt + 1;
end if;
Q <= cnt;
end process;

end DESCRIPTION;

The above is OK for simulation, but in real life you will most likely want
to add a reset signal to your counter, something lke this:

process (CLOCK, RST_N)
begin
if RST_N='0' then
Q <= (others=>'0');
if (CLOCK ='1' and CLOCK'event) then
Q <= Q + 1;
end if;
end process;

/Mikhail

 

[MM]

Q : inout std_logic_vector(3 downto 0));

I should have added why I asked about Q being bidirectional. The reason you
can't initialize Q from the test bench is because it is being driven by the
module all the time, so you have a bus conflict because a bidirectional bus
can't be driven by 2 drivers at the same time and be in a determined state
provide both drivers are of equal strength. In other words, I think you
should change your Q to be a simple output... That is unless you have a
valid reason for it to be bidirectional, but if that's the case it is a
different topic...

/Mikhail

 

[DG]

"MM" <mbmsv@yahoo.com> a écrit dans le message de
news:bm83am$j9vp1$1@ID-204311.news.uni-berlin.de...

Q : inout std_logic_vector(3 downto 0));

I should have added why I asked about Q being bidirectional. The reason
you
can't initialize Q from the test bench is because it is being driven by
the
module all the time, so you have a bus conflict because a bidirectional
bus
can't be driven by 2 drivers at the same time and be in a determined state
provide both drivers are of equal strength. In other words, I think you
should change your Q to be a simple output... That is unless you have a
valid reason for it to be bidirectional, but if that's the case it is a
different topic...

Thank you Mikhail for your help, you had solved my problem.

You are right, I don't need at all to make Q bidirectional if I had a RST
signal which allow me to reset my counter in the test driver. This is
exactly what I was looking for....

Best Regards.