Guest
Hi guys,
I've gotten a lot of repsonses, but no real answers. To clariy, the
text says to remove RL and short the source. To you guys that think
this is my homework.... good thing it is not. This is actually on a
computer aided instruction course at my tech school. It states the
answer as 21 ohms. I came up with 20.55 ohms. It generally wants two
decimal places, so I would be shocked if it rounded 20.55 to 21. So, I
was picking other folks brains.
Here is the original post:
Can someone tell me (step by step) how to calculate the Norton's
resistance for this circuit? (see picture below)
http://www.progressivetel.com/~radney4/NT.jpg
Thanks!
Lee
I've gotten a lot of repsonses, but no real answers. To clariy, the
text says to remove RL and short the source. To you guys that think
this is my homework.... good thing it is not. This is actually on a
computer aided instruction course at my tech school. It states the
answer as 21 ohms. I came up with 20.55 ohms. It generally wants two
decimal places, so I would be shocked if it rounded 20.55 to 21. So, I
was picking other folks brains.
Here is the original post:
Can someone tell me (step by step) how to calculate the Norton's
resistance for this circuit? (see picture below)
http://www.progressivetel.com/~radney4/NT.jpg
Thanks!
Lee