Neither parallel nor series

W

Wong

Guest
What theorem or method can be applied to calculate the total
resistance at point A to B?

----- A -----
| |
| |
R1 R2
| |
| |
------R3------
| |
| |
R4 R5
| |
| |
----- B -----

Thanks.
 
tatto0_2000@yahoo.com (Wong) wrote in message news:<509bfe22.0410192154.627939bb@posting.google.com>...
What theorem or method can be applied to calculate the total
resistance at point A to B?

----- A -----
| |
| |
R1 R2
| |
| |
------R3------
| |
| |
R4 R5
| |
| |
----- B -----

Thanks.
Star to delta conversion will work here.

Your above star connection can be converted into equivalent delta
connection, like this



RB
___
|--------------|---|___|----------------|
| | | |
| | | |
| | | |
.-. .-.
B RA | | | | RC A
| | | |
| '-' '-' |
| | | |
| ___ | | ___ |
|----|___|-----|-----------|-----|___|--|

R5 R2

created by Andy´s ASCII-Circuit v1.24.140803 Beta www.tech-chat.de


RA = ( R4*R1 + R1*R3 + R3*R4 ) / R1

RB = ( R4*R1 + R1*R3 + R3*R4 ) / R3

RC = ( R4*R1 + R1*R3 + R3*R4 ) / R4


Now it is easy enough, for you to further simply it.
 
Use Delta to STAR conversion,


----- A -----
| | |
| Ra |
R1 | R2
| / \ |
| Rb Rc |
--/----R3----\-
| |
| |
R4 R5
| |
| |
----- B -----
the result became, and it is series with parallel series.

A > | | |
Ra
|
/ \
Rb Rc
--/ \-
| |
| |
R4 R5
| |
| |
----- B -----

Ra = (R1+R2)/(R1+R2+R3)
Rb = (R1+R3)/(R1+R2+R3)
Ra = (R2+R3)/(R1+R2+R3)


it is in Electrical technology by Edward Hughes

KM





tatto0_2000@yahoo.com (Wong) wrote in message news:<509bfe22.0410192154.627939bb@posting.google.com>...
What theorem or method can be applied to calculate the total
resistance at point A to B?

----- A -----
| |
| |
R1 R2
| |
| |
------R3------
| |
| |
R4 R5
| |
| |
----- B -----

Thanks.
 
kianmeng.tey@gmail.com (KM) wrote in message news:<ecdf7787.0410200555.2e97365d@posting.google.com>...
Use Delta to STAR conversion,


----- A -----
| | |
| Ra |
R1 | R2
| / \ |
| Rb Rc |
--/----R3----\-
| |
| |
R4 R5
| |
| |
----- B -----

the result became, and it is series with parallel series.

A > | | |
Ra
|
/ \
Rb Rc
--/ \-
| |
| |
R4 R5
| |
| |
----- B -----


Ra = (R1+R2)/(R1+R2+R3)
Rb = (R1+R3)/(R1+R2+R3)
Ra = (R2+R3)/(R1+R2+R3)


it is in Electrical technology by Edward Hughes

KM
I think there is a correction here, Ra should equal to
(R1*R2)/(R1+R2+R3) and Rb, Rc as well.
So the total resistance is (Ra + ((R4+Rb) || (R5+Rc)))
Let say, R1=1k, R2=2k, R3=3k, R4=4k and R5=5k. I will get the answer
of 2.9k and it is same with my simulation. Thanks !!
 
whoops, what an ugly mistake i did; feeling very shameful.
should be delta to star. really frustrating isn't it……should go and die somewhere.
 
John Popelish <jpopelish@rica.net> wrote in message news:<4177F050.DFBA105D@rica.net>...
Jack// ani wrote:


whoops, what an ugly mistake i did; feeling very shameful.
should be delta to star. really frustrating isn't it should go and
die somewhere.

If that is the biggest mistake you make this year,you are doing
well i hope so.

better than most of us.
thanks
 
tatto0_2000@yahoo.com (Wong) wrote in message news:<509bfe22.0410192154.627939bb@posting.google.com>...
What theorem or method can be applied to calculate the total
resistance at point A to B?

----- A -----
| |
| |
R1 R2
| |
| |
------R3------
| |
| |
R4 R5
| |
| |
----- B -----

You forgot to say "I don't like doing my own homework, please
do it for me."


And the correlary: if this ISN'T a homework problem, you
should say so. It also would help if you mentioned what
you've tried so far, and whether you're an absolute beginner
or not.
 
kianmeng.tey@gmail.com (KM) wrote in message news:<ecdf7787.0410200555.2e97365d@posting.google.com>...
Use Delta to STAR conversion,


----- A -----
| | |
| Ra |
R1 | R2
| / \ |
| Rb Rc |
--/----R3----\-
| |
| |
R4 R5
| |
| |
----- B -----

the result became, and it is series with parallel series.

A > | | |
Ra
|
/ \
Rb Rc
--/ \-
| |
| |
R4 R5
| |
| |
----- B -----


Ra = (R1+R2)/(R1+R2+R3)
Rb = (R1+R3)/(R1+R2+R3)
Ra = (R2+R3)/(R1+R2+R3)
I'm not following these formulas.
If all the resistors R1-R5 are 1 ohm, then the
total resistance from a to b will be 1 ohm.
But, according to the formulas, Ra, Rb ,Rc will
be 2/3 or 0.67 ohms. So, we have 1.67 in parallel
with 1.67 which is 0.83 which is in series with
Ra (0.67). That all adds up to 1.5 ohms, but it
should be 1 ohm.

What am I missing?


-Bill
 

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